# Expected CAT Question

### Expected CAT Question

101. Price of 1st bottle = 520 Bahts Price of 2nd and 3rd bottles each = (520 × 0.7) = 364 Bahts

∴ Total cost of all three bottles = 1248 Bahts

Cost per person = 416 Bahts

R pays 2 Euros = 2 × 46 = 92 Bahts

M pays 4 Euros and 27 Bahts = 4 × 46 + 27 = 211 Bahts

S pays the remaining amount = 1248 − (92 + 211) = 945 Bahts

∴ R owes 416 − 92 = 324 Bahts to S.

Hence, option 4.
102. From the solution to the previous question, M owes = 416 − 211 = 205 Bahts to S

But, 205 Bahts = 205/41 = 5 US Dollars Hence, option 3.

Q103:

Let a be the number of projects in which only Gyani is involved, g be the number of projects in which only Buddhi is involved and c be the number of projects in which only Medha is involved. From the data, d = 6 b + d = 14 ∴ b = 8 Also, e = 3 and f = 2 It is given that a + g = b + c + d + f ∴ a − c + g = 16 … (i)
Number of projects involving more than 1 consultant = 6 + 8 + 2 + 3 = 19 ∴ Total number of projects = 2 × 19 − 1 = 37 a + b + c + d + e + f + g = 2 × (b + d + e + f) − 1 ∴ a + c + g = 19 − 1 = 18 … (ii)
Solving (i) and (ii), we get, c = 1 and a + g = 17 ∴ a cannot be determined uniquely. Hence, option 4.
104. From the solution to the previous question, we get, c = 1 ∴ Number of projects in which Medha alone is involved = 1 Hence, option 2.