Q1:The rent of the car = Maxima(number of hours × charge per hour, km travelled × charge per km)

Case 1: Anand drove the car for 5 hours or less ∴ Rent = Maxima(300, 30 × 12) = 360

Case 2: Anand drove the car for more than 5 hours ∴ Rent = Maxima(300, 7.5 × 30) = 300

∵ Anand paid Rs. 300 as rent. ∴ Anand drove for 6 hours. Hence, option 4.

Q2

Let the speed of E be 2x km/hr. ∴ Speed of N = 4x km/hr and speed of S = x km/hr According to the problem, Time taken by N to cover AB + Time taken by S to cover BA = 1 hour ∴

∴ D/4X+D/X =1

5D=4X

∵ To maintain the schedule (gap of 20 min), N doubles its speed and speed of S becomes y. ∴

(4X/5)/8X+(4X/5)/Y=2/3

1/10+(4X)/(5X)=2/3

(Y/8X)=3/17 =1/16

hence option 4