Faster Calculations Without Compromising Accuracy !

It is absolutely stupendous to perform mathematical calculations at split second speed. Some quirky maths tricks can reduce the time and effort required to solve complex problems. Here are some tricks derived from Vedic Maths that will help you do faster calculations without compromising accuracy in your competitive exams. Become a maths wizard by trying these 6 maths tricks that will help you calculate faster.

1. Squaring numbers with ‘5’ at one’s place:

The trick is applicable if you are squaring a two digit number that has 5 at one’s place. It is certain that the last two digits of the answer will be 25 in case your two digit number ends in 5. Now the remaining digits of the answer can be calculated by multiplying the first digit of the number by its successor. For example say find the square of 65. The last two digits of the answer is 25 and the initial digits would be 6*7= 42 (7 being successor of 6). So, the final answer is 4225.

2. Multiplication Setting:

34 x 36 = Start by taking the first digit of the first number (3 for 34) and multiplying that by the number directly higher than it, which will give you the first digit(s) of the answer. So for 34 multiplied by 36, it would be 3 (first digit in first number) multiplied by 4 (one digit higher) = 12. This means that 12 is our first two digits in the answer. Now take the second digit of the first number (4 for 24) and multiple that by the second digit of the second number (6 for 26), which will give you the remaining digits of the answer. So for 34 multiplied by 36, it would be 4 (second digit in first number) x 6 (second digit in second number) = 24. 2 and 4 are the last two digits of the answer. So, 34 x 36 = 1224. You’re done! A Few Restrictions There are a few restrictions, or caveats, that must be adhered to:

• The first digits of both numbers must be the same
• The last digit of both numbers must equal 10 If you look at the example above, the first digit in each number (34, 36) is 3, and the last digits in each (4, 6) equals 10.

3. Multiplication involving 9: This trick is a direct application of distributive property of multiplication, where you can directly multiply a given number with a multiple of 10 and then subtract the given number.

For instance, to find 47* 999, simply calculate 47*(1000-1). Therefore the sum reduces to 47000- 47=46953.

4. Multiplication with powers of 2: If you are performing multiplication of a number with 2 or multiples of 2, then just double the given number for each power of 2 in the multiplier.

To solve 14* 16, all you need is to first rewrite the sum as 14*2*2*2*2. Now you have to double 14 four times to get the result, the first doubling of 14 gives 28, the second gives 56, the third doubling gives 112 and the fourth doubling gives 224.

5. To Multiply a 2 digit number by 11:

For e.g. 35, write it as 3( )5. Inside the ( ), the sum of the two digits goes in. In this case, 3+5 = 8, hence 8 goes inside ( ). So, 35*11 = 382. In case the sum of the two digits is a two digit number, keep the unit digit and add one to the digit preceding the ( ). For e.g. if we are to multiply 48 by 11, 4( )8. Inside ( ), we have 4+8 which is 12. So we place 2 and add 1 to 4 which precedes the ( ). Hence the result is 528.

6. To calculate Remainder on dividing the number by 7 11 and 13:

For e.g. 34568276, we have to calculate the reminder on diving this number by 7 11 and 13 respectively. make triplets as written below starting from units place 34………568……….276 now alternate sum = 34+276 = 310 and 568 and difference of these sums = 568-310 = 258 divide it by 7 we get reminder as 6 divide it by 11 we get reminder as 5 divide it by 13 we get reminder as 11 The above were just some simple tricks you can apply for faster calculations. With more practice, one can be sure of the answer and need not verify it by conventional methods. All The Best!!!