- Question
Bottle 1 contains a mixture of milk and water in 7: 2 ratio and Bottle 2 contains a mixture of milk and water in 9: 4 ratio. In what ratio of volumes should the liquids in Bottle 1 and Bottle 2 be combined to obtain a mixture of milk and water in 3:1 ratio?
a)24:13
b)27:13
c)27:16
d)23:18
e)27:14
Explanation
SOLUTION[B]
The concentration of milk in bottle 1 = 7/9
The concentration of milk in bottle 2 = 9/13
The concentration of milk we require in mixture = ¾
Ratio = 27/13
Bottle 1 and Bottle 2 should be combined in the ratio of 27: 13
Question-2
Which among the following is the smallest 7 digit number that is exactly divisible by 43?
a)1000043
b)1000048
c)1000051
d)1000006
e)1000008
Explanation
SOLUTION[E]
Question-3
The strength of a salt solution is p% if 100 ml of the solution contains p grams of salt. Each of three vessels A, B, C contains 500 ml of salt solution of strengths 10%, 22%, and 32%, respectively. Now, 100 ml of the solution in vessel A is transferred to vessel B. Then, 100 ml of the solution in vessel B is transferred to vessel C. Finally, 100 ml of the solution in vessel C is transferred to vessel A.
Now, the strength, in percentage, of the resulting solution in vessel A shall be:
a)13%
b)14%
c)12%
d)16%
e)15%
Explanation
SOLUTION[B] 14%
The initial amount of salt in each vessel = 50ml . 110ml 160 ml
100 ml of solution is transferred from A to B
A would have 400 ml, B would have 600 ml of solution
Amount of salt from A which is transferred to B = 100 * 1 / 10 Rightarrow 10ml
So, Total salt in B = 110 + 10 = 120 grams (After first transfer)
Total salt in A = 40 grams (After first transfer)
Now, 100 ml from Vessel B is transferred to Vessel C
So similarly salt would transfer from B to C = 1/6 * th total salt
Amount of salt from B which is transferred to C = 120 * 1 / 6 Rightarrow 20ml
Total Salt in B = 120 – 20 = 100 grams (After second transfer)
Total Salt in C = 160 + 20 = 180 grams (After second transfer)
Now, 100 ml from Vessel C is transferred to Vessel A
So similarly of salt would transfer from C to A = 1/6 * th total salt Amount of salt from C which is transferred to A = 180 * 1 / 6 ⇒ 30 ml
Total Salt in C = 180 – 30 = 150 grams (After third transfer)
Total Salt in A = 40 + 30 = 70 grams (After third transfer) So, Vessel A contains 70 grams Salt in 500 ml solution
Strength of Salt Solution in Vessel A = 14%
.. The strength in the percentage of the resulting solution in vessel A is 14%
