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Coding Decoding Based Inequalities MBA CET 2022 Actual Questions

Inequalities

Q1-5. Directions: In the following questions, symbols @,%,$,* and # are used with the following meaning as illustrated below.

A @ B means ‘A is not less than B’

A $ B means ‘A is not more than B’

A # B means ‘A is neither less nor more than B’

A * B means ‘A is neither more than nor equal to B’

A % B means ‘A is neither less than nor equal to B’

1. Statements : V@I#E*D ;  N$E%B#F

Conclusions : 

I.D%F     

II. V@B

(A) Only conclusion I follows

(B) Only conclusion II follows

(C) Both conclusion I and conclusion II follows

(D) Either conclusion I or conclusion II follows

(E) Neither conclusion I nor conclusion II follows

EXPLANATION

Correct Option: A

Interpretation of the coded symbols:

A @ B means ‘A is not less than B’ i.e. A ≥ B

A $ B means ‘A is not more than B’ i.e. A ≤ B

A # B means ‘A is neither less nor more than B’ i.e. A = B

A * B means ‘A is neither more than nor equal to B’ i.e. A < B

A % B means ‘A is neither less than nor equal to B’ i.e. A > B

We will decode the given statements as per the above interpreted signs.

Statements: V ≥ I = E < D ;  N ≤ E > B = F

Conclusions: I. D > F  II. V ≥ B

For conclusion I: 

From both the statements we get:

F = B < E < D

The common sign between F and D is ‘<’, thus F < D or D > F is true.

Hence conclusion I follows.

For conclusion II:

From both the statements we get:

V ≥ I = E > B

The common sign between V and B is ‘>’, thus V > B is the actual relationship.

Hence conclusion II does not follow.

Therefore only conclusion I follows.

Hence option A is correct.

2. Statements : R#M$X*T%W@B

Conclusions : 

I.M*W 

II. T@M

(A) Only conclusion I follows

(B) Only conclusion II follows

(C) Both conclusion I and conclusion II follows

(D) Either conclusion I or conclusion II follows

(E) Neither conclusion I nor conclusion II follows

EXPLANATION

Correct Option: E

Interpretation of the coded symbols:

A @ B means ‘A is not less than B’ i.e. A ≥ B

A $ B means ‘A is not more than B’ i.e. A ≤ B

A # B means ‘A is neither less nor more than B’ i.e. A = B

A * B means ‘A is neither more than nor equal to B’ i.e. A < B

A % B means ‘A is neither less than nor equal to B’ i.e. A > B

We will decode the given statements as per the above interpreted signs.

Statements: R= M ≤ X < T > W ≥ B

Conclusions: I. M < W  II. T ≥ M

For conclusion I: 

We can clearly see the opposite sign persisting between M and W , thus no relationship between them can be established.

Hence conclusion I does not follow.

For conclusion II:

The common sign between M and T is ‘<‘, thus M < T or T > M is the actual relationship.

Hence conclusion II does not follow.

Therefore neither conclusion I nor II follows.

Hence option E is correct.

3. Statements : F*D$E#R*S@V%K

Conclusions : 

I.D*R     

II. D#R

(A) Only conclusion I follows

(B) Only conclusion II follows

(C) Both conclusion I and conclusion II follows

(D) Either conclusion I or conclusion II follows

(E) Neither conclusion I nor conclusion II follows

EXPLANATION

Correct Option: D

Interpretation of the coded symbols:

A @ B means ‘A is not less than B’ i.e. A ≥ B

A $ B means ‘A is not more than B’ i.e. A ≤ B

A # B means ‘A is neither less nor more than B’ i.e. A = B

A * B means ‘A is neither more than nor equal to B’ i.e. A < B

A % B means ‘A is neither less than nor equal to B’ i.e. A > B

We will decode the given statements as per the above interpreted signs.

Statements: F < D ≤ E = R < S ≥ V > K

Conclusions: I. D < R  II. D = R

For conclusion I: 
D ≤ E = R

The common sign between D and R is ‘≤’, thus D ≤ R is the actual relationship.

So either D < R or D = R is true.

Therefore either conclusion I or II follows.

Hence option D is correct.

4. Statements : M@A#S%R ; C$R#E

Conclusions : 

I.S%C     

II. M%E

(A) Only conclusion I follows

(B) Only conclusion II follows

(C) Both conclusion I and conclusion II follows

(D) Either conclusion I or conclusion II follows

(E) Neither conclusion I nor conclusion II follows

EXPLANATION

Correct Option: C

Interpretation of the coded symbols:

A @ B means ‘A is not less than B’ i.e. A ≥ B

A $ B means ‘A is not more than B’ i.e. A ≤ B

A # B means ‘A is neither less nor more than B’ i.e. A = B

A * B means ‘A is neither more than nor equal to B’ i.e. A < B

A % B means ‘A is neither less than nor equal to B’ i.e. A > B

We will decode the given statements as per the above interpreted signs.

Statements: M ≥ A = S > R ;  C ≤ R = E

Conclusions: I. S > C  II. M > E

For conclusion I: 
From both the statements we get:
C ≤ R < S

The common sign between C and S is ‘<’, thus C < S or S > C is true.

Hence conclusion I follows.

For conclusion II:
From both the statements we get:
M ≥ A = S > R = E

The common sign between M and E is ‘>’, thus M > E is the actual relationship.

Hence conclusion II follows.

Therefore both conclusions I and II follow.

Hence option C is correct.

5. Statements : V@I#E*D ;  N$E%B#F

Conclusions : 

I.  V%F   

II. V@N

(A) Only conclusion I follows

(B) Only conclusion II follows

(C) Both conclusion I and conclusion II follows

(D) Either conclusion I or conclusion II follows

(E) Neither conclusion I nor conclusion II follows

EXPLANATION

Correct Option: C

Interpretation of the coded symbols:

A @ B means ‘A is not less than B’ i.e. A ≥ B

A $ B means ‘A is not more than B’ i.e. A ≤ B

A # B means ‘A is neither less nor more than B’ i.e. A = B

A * B means ‘A is neither more than nor equal to B’ i.e. A < B

A % B means ‘A is neither less than nor equal to B’ i.e. A > B

We will decode the given statements as per the above interpreted signs.

Statements: V ≥ I = E < D ;  N ≤ E > B = F

Conclusions: I. V > F  II. V ≥ N

For conclusion I: 

From both the statements we get:

V ≥ I = E > B = F

The common sign between V and F is ‘>’, thus V > F is true.

Hence conclusion I follows.

For conclusion II:

From both the statements we get:

 V ≥ I = E ≥ N

The common sign between V and N is ‘≥’, thus V ≥ N is the actual relationship.

Hence conclusion II follows.

Therefore both conclusions follow.

Hence option C is correct.

Category :

Inequalities

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