Ram has 5000 litres of pure milk. He sells 40% of the total milk to six
different persons (A,B,C,D,E,F) and the remaining 60% of total milk he
utilizes in his own shop. Each person, A, B, C, D, E, and F mixes water in
pure milk. The following table given below shows the sales of milk to six
different persons by Ram as a percentage of total sales and it also shows
the concentration of water after adding water in pure milk by each of the
six persons.
Question 1.
What is the difference between the total quantity of water added by
Person A and that of Person C? (approximately)
A. 105 liters
B. 99 liters
C. 91 liters
D. 95 liters
E. 102 liters
Question 2.
What is the respective ratio of the total quantity of water added by
Person C and the total quantity of water added by Person E?
A. 81 : 287
B. 9 : 32
C. 3 : 11
D. 85 : 287
E. None of these
Question 3.
Who among the following added least quantity (In litres) of water in
pure milk?
A. A
B. B
C. C
D. E
E. F
Question 4.
Suppose, A, B, and C mix their solutions in one can then what would be
the concentration of milk in the new solutions? (approximately)
A. 75.2%
B. 78.21%
C. 80.25%
D. 85.24%
E. 72.68%
Question 5.
How many total liters of water was added by all the persons together?
(approximately)
A. 500 liters
B. 550 liters
C. 450 liters
D. 490 liters
E. 520 liters
Question 6.
Suppose, all of them mixed the solution together in one can and boiled
it then 200 liters of water were evaporated then what is the
concentration of pure milk in the new solution? (approximately)
A. 92.28%
B. 85.24%
C. 91.42%
D. 78.45%
E. 87.34%
Explanation
Question 1-
40% of 5000 = 2000 liters Ram sells to six persons
Let Person A add ‘a’ liters of water then the total quantity of solution = 480 + ‘a’
liters, in which the concentration of water is 24%
Therefore, 24% of (480 + a) = a
100a = 24 × 480 + 24a
76a = 24 × 480
A = 2880/19 liters = approximately 151.58 liters = Quantity of water added by
Person A
Similarly, Let the person C add c liters of water then
18% of (240 + c) = c
82c = 240 × 18
C =
2160 liters = 52.68 liters approximately = quantity of water added by person
41 C
The required difference = 151.58 – 52.68 = 98.9 liters = approximately 99 liters
Hence, option B is correct.
Question 2-
Let the person C add c liters of water then
18% of (240 + c) = c
82c = 240 × 18
C = 2160/41 liters = 52.68 liters approximately
= quantity of water added by person C
Let the person E add e liters of water
Then, 25% of (560 + e) = e
75e = 560 × 25
E =560/3 liters = quantity of water added by person E
Reqd. ratio = 2160/41
:
560/3 = 81 : 287
Hence, option A is correct.
Question 3-
Let Person A add ‘a’ liters of water then the total quantity of solution = 480 + ‘a’
liters, in which the concentration of water is 24%
Therefore, 24% of (480 + a) = a
100a = 24 × 480 + 24a
76a = 24 × 480
a =2380/19 liters = approximately 151.58 liters
= Quantity of water added by Person A
Let the person B add b liters of water then,
10% of (200 + b) = b b = quantity of water added by Person B
=
200/9 liters = approximately 22.22 liters
Let the person C add c liters of water then
18% of (240 + c) = c
82c = 240 × 18
C =
2160/41 liters = 52.68 liters approximately
= quantity of water added by person C
Let the person D add d liters of water
15% of (140 + d) = d
d = 140 × 15/85 = 24.70 litres
= quantity of water added by person D
Let the person E add e liters of water
Then, 25% of (560 + e) = e
75e = 560 × 25
E =
560/3 liters = 186.67 liters approximately
= quantity of water added by person E
Let the person F add f liters of water then,
12% of (380 + f) = f
88f = 380 × 12
f = 51.82 liters = quantity of water added by person F
Therefore, B added least quantity (In liters) of water
Hence, option B is correct.
Question 4-
When A, B, and C mix their solution in one can then the quantity of milk in the
new solution = 480 + 200 + 240 = 920 liters
And the quantity of milk in the new mixture = 151.58 + 22.22 + 52.56 = 226.36
liters
The total quantity of new solution = 920 + 226.36 = 1146.36 liters
The required concentration of milk in the new solution
=
920 × 100/1146.36
= 80.25% approximately
Hence, option C is correct.
Question 5-
The total quantity of water added by all the persons together
= 151.58 + 22.22 + 52.68 +24.70 + 186.67 + 51.82
= approximately 489.67 liters = approximately 490 liters
Hence, option D is correct.
Question 6-
The total quantity of milk = 2000 liters
The total quantity of water = approximately 490 liters
The total quantity of solution = 2000 + 490 = 2490 liters approximately
When 200 liters of water were evaporated then the remaining quantity of water
= 2490 – 200 = 2290 liters
The concentration of pure milk in the new solution
=
2000 × 100/2290
= approximately 87.34%
Hence, option E is correct.
