Profit & LOss CET Actual questions

Profit & Loss | Interactive Quiz

CET 2026 Profit & Loss

Q1. The marked price of an article is ₹2500. Two successive discounts of 10% and 5% are allowed. Even then, the shopkeeper earns a 20% profit. Find the cost price of the article.
  • A) ₹2137.50
  • B) ₹2357.50
  • C) ₹1668.50
  • D) ₹1752.75
  • E) ₹1781.25
Correct Option: E Rationale: SP = 2500 × 90/100 × 95/100 = ₹2137.50. Since SP = 120% of CP, CP = 2137.50 × 100/120 = ₹1781.25.
Q2. A shopkeeper marks an article 40% above its cost price. He offers a two-stage discount — first a 10% discount, and then an additional 5% discount. Find his overall profit percentage if the cost price is ₹200.
  • A) 26.8%
  • B) 30%
  • C) 25.4%
  • D) 19.7%
  • E) 14.5%
Correct Option: D Rationale: MP = 200 × 140% = ₹280. After successive discounts, SP = 280 × 90% × 95% = ₹239.40. Profit = ₹39.40, so profit% = 39.40 / 200 × 100 = 19.7%.
Q3. A person bought a book and a novel for ₹2800. He sold the book at 10% profit and the novel at 12.5% profit. If his overall profit was 13%, then what is the difference between the cost prices of the book and the novel?
  • A) ₹200
  • B) ₹400
  • C) ₹350
  • D) ₹450
  • E) ₹389
  • F) Invalid Data
Correct Option: F (No valid option) Rationale: This question is mathematically inconsistent because the individual profits are 10% and 12.5%. Therefore, the combined overall profit percentage must lie between 10% and 12.5%; it cannot be 13%.
Q4. The profit earned by selling an article for ₹900 is double the loss incurred when the same article is sold for ₹450. At what price should the article be sold to make a 25% profit?
  • A) ₹600
  • B) ₹750
  • C) ₹800
  • D) ₹900
  • E) ₹450
Correct Option: B Rationale: Let CP = x. Then 900 − x = 2(x − 450) ⇒ 3x = 1800 ⇒ CP = ₹600. For 25% profit, SP = 600 × 125% = ₹750.
Q5. A fan is listed at ₹1500 and a discount of 20% is offered on the list price. What additional discount must be offered to the customer to bring the net price to ₹1104?
  • A) 8%
  • B) 10%
  • C) 12%
  • D) 15%
  • E) 20%
Correct Option: A Rationale: After 20% discount, price = 1500 × 80% = ₹1200. Required reduction = 1200 − 1104 = ₹96. Additional discount = 96 / 1200 × 100 = 8%.
Q6. The marked price of an article is ₹25. A discount of 10% is given. How much should be the selling price so that the shopkeeper gains 10%?
  • A) ₹20.25
  • B) ₹22.50
  • C) ₹25
  • D) ₹42.75
  • F) Cannot be Determined
Correct Option: F (Question incomplete/inconsistent) Rationale: A 10% discount on ₹25 gives SP = ₹22.50, but to determine what the SP *should* be for a 10% gain, the actual cost price must also be known.
Q7. A dishonest shopkeeper uses a 900 gram weight instead of a 1 kilogram weight. He sells goods per kilogram at the same price at which he buys one kilogram. What is his profit percentage?
  • A) 10%
  • B) 11 1/9%
  • C) 12 1/2%
  • D) 15%
  • E) 9%
Correct Option: B Rationale: He charges the cost of 1000 g but gives only 900 g. Profit% = (100 / 900) × 100 = 11 1/9%.
Q8. A person sold an article for ₹3600 and got a profit of 20%. Had he sold the article for ₹3150, how much profit would he have got?
  • A) 4%
  • B) 5%
  • C) 6%
  • D) 7%
  • E) 8%
Correct Option: B Rationale: CP = 3600 / 1.20 = ₹3000. At ₹3150, profit = ₹150. So profit% = (150 / 3000) × 100 = 5%.
Q9. A sells an article to B at a profit of 20%. B sells it to C at a profit of 25%. C sells it to D at a loss of 10%. D sells it back to A at a profit of 12 1/2%. If A finally pays ₹486 to get back the article, what was the original cost price of the article for A?
  • A) ₹300
  • B) ₹320
  • C) ₹360
  • D) ₹400
  • E) ₹450
Correct Option: B Rationale: If original CP = x, final price = x × 1.20 × 1.25 × 0.90 × 1.125 = 1.51875x. Thus 1.51875x = 486 ⇒ x = ₹320.
Q10. A trader first incurs a loss of x% on an article and then makes a profit of y%. If the final selling price equals the original cost price, then the relation between x and y is:
  • A) x = y
  • B) y = 100x/(100 − x)
  • C) y = 100x/(100 + x)
  • D) y = x + x²/100
  • E) y = x − 1
Correct Option: B Rationale: After x% loss, value = (100 − x)%. To recover to 100 after y% profit: (100 − x)(100 + y) = 10000 ⇒ y = 100x / (100 − x).
Q11. A trader sells his articles at 10% higher than their original price. Due to higher demand, he again increases the price by 15%. Calculate the percentage of profit the trader makes.
  • A) 25.5%
  • B) 26.5%
  • C) 22%
  • D) 27.33%
  • E) 24.5%
Correct Option: B Rationale: Successive increases of 10% and 15% give 1.10 × 1.15 = 1.265. So the overall profit is 26.5%.
Q12. A person sold a radio at a loss of 5%. Had he sold it for ₹210 more, he would have gained 25%. For what value should he sell it in order to gain 35%?
  • A) ₹950
  • B) ₹945
  • C) ₹935
  • D) ₹850
  • E) ₹845
Correct Option: B Rationale: Difference between 25% profit and 5% loss = 30% of CP = ₹210. Thus CP = ₹700. For 35% profit, SP = 700 × 1.35 = ₹945.
Q13. Mahan bought a bag with a 15% discount on the labeled price. He sold the bag for ₹2880 with a 20% profit on the labeled price. At what price did he buy the bag?
  • A) ₹2400
  • B) ₹2200
  • C) ₹2040
  • D) ₹2020
  • E) ₹2025
Correct Option: C Rationale: SP ₹2880 represents 120% of labeled price, so labeled price = ₹2400. Buying at 15% discount gives CP = 2400 × 85% = ₹2040.
Q14. By selling 12 oranges for a rupee, a man loses 20%. How many oranges for a rupee should he sell to gain 20%?
  • A) 8
  • B) 10
  • C) 15
  • D) 16
  • E) 9
Correct Option: A Rationale: At 20% loss, CP of 12 oranges = ₹1 / 0.8 = ₹1.25. For 20% gain, required SP = ₹1.50 for 12 oranges. Hence for ₹1, number of oranges = 12 / 1.5 = 8.
Q15. A man bought an article and sold it at a gain of 5%. If he had bought it at 5% less and sold it for ₹1 less, he would have made a profit of 10%. The cost price of the article is:
  • A) ₹100
  • B) ₹150
  • C) ₹200
  • D) ₹250
  • E) ₹300
Correct Option: C Rationale: Let original CP = x. Original SP = 1.05x. New CP = 0.95x and new SP = 1.05x − 1. Since this gives 10% profit, 1.05x − 1 = 1.10 × 0.95x = 1.045x ⇒ 0.005x = 1 ⇒ x = ₹200.
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