Number Series in CET Type 1
Directions: In the given series, one term is missing and replaced with question mark?. What will come in place of question mark (?) in the given series:
1. 98, 144, 198, ?, 330, 408, 494
A 240 B 256 C 212 D 260 E None of these
2. 7055, 7223, 7393, 7565, ?, 7915
A 7739 B 7839 C 7639 D 7749 E None of these
Correct Option: D
| Series Pattern | Series | |
| 98 | 98 | |
| 98 + 46 | 144 | |
| 144 + 54 | 198 | |
| 198 + 62 | 260 | ✓ |
| 260 + 70 | 330 | |
| 330 + 78 | 408 | |
| 408 + 86 | 494 |
Hence, option D is correct.
Correct Option: A
| Series Pattern | Series | |
| 842 – 1 = 7055 | 7055 | |
| 852 – 2 = 7223 | 7223 | |
| 862 – 3 = 7393 | 7393 | |
| 872 – 4 = 7555 | 7565 | |
| 882 – 5 = 7739 | 7739 | ✓ |
| 892 – 6 = 7915 | 7915 |
Hence, option A is correct.
Number Series in CET Type 2
Find the wrong term in the given series.
1. 11 20 38 74 144 290 578
A 144 B 38 C 290 D 74 E 578
2. 1 8 36 148 586 2388
A 8 B 586 C 2388 D 148 E 36
Correct Option: A
Series Pattern Given Series
11 11 ✓
11 + 9 = 20 20 ✓
20 + 18 = 38 38 ✓
38 + 36 = 74 74 ✓
74 + 72 = 146 144 ✕
146 + 144 = 290 290 ✓
290 + 288 = 578 578 ✓
Hence, option (A) is correct.
Correct Option: B
| Series Pattern | Given Series | |
| 1 | 1 | ✓ |
| 1 × 4 + 4 = 8 | 8 | ✓ |
| 8 × 4 + 4 = 36 | 36 | ✓ |
| 36 × 4 + 4 = 148 | 148 | ✓ |
| 148 × 4 + 4 = 596 | 586 | ✕ |
| 596 × 4 + 4 = 2388 | 2388 | ✓ |
20 Must solve CET Series based Questions
- 1 3 10 36 152 760 4632
(a) 3
(b) 36
(c) 4632
(d) 760
(e) 152 - 12, 12, 18, 45, 180, 1170, ?
(a) 12285
(b) 10530
(c) 11700
(d) 12870
(e) 9945 - 67, 1091, 835, 899, 883, ?
(a) 889
(b) 887
(c) 883
(d) 894
(e) 896 - 12, 30, 120, 460, 1368, 2730
What will come in place of (d)?
(a) 1384
(b) 2642
(c) 2808
(d) 1988
(e) None of these - 72, 74, 84, 110, 160, 244, 364
(a) 364
(b) 244
(c) 160
(d) 74
(e) 72 - 30, 42, 48, 54, 65, 81, 126
(a) 42
(b) 48
(c) 126
(d) 30
(e) 65 - 77, 78, 159, 472, 1889, 9446, 56677
(a) 159
(b) 472
(c) 1889
(d) 56677
(e) 77 - 2159, 1967, 1782, 1611, 1461, 1339, 1254
(a) 1967
(b) 2159
(c) 1461
(d) 1254
(e) 1611 - 854, 886, 923, 964, 1007, 1054, 1107
(a) 923
(b) 1007
(c) 854
(d) 1054
(e) 1107 - 465, 633, 775, 897, 993, 1065, 1113
(a) 465
(b) 633
(c) 993
(d) 775
(e) 1113 - 12, 12, 30, 120, 654, 4620
(a) 12
(b) 654
(c) 30
(d) 120
(e) 4620 - 1174, 1275, 1445, 1671, 1961, 2323
(a) 1174
(b) 1275
(c) 1671
(d) 1961
(e) 2323 - 9, 25, 58, 125, 260, 531, 1075
(a) 9
(b) 25
(c) 260
(d) 531
(e) 1075 - 4866, 2432, 1218, 610, 306, 154, 78
(a) 4866
(b) 78
(c) 2432
(d) 154
(e) 610 - 4, 11, 39, 163, 823, 4947, 34639
(a) 11
(b) 4
(c) 4947
(d) 39
(e) Series is correct - 19, 24, 33, 43, 55, 69, 85
(a) 24
(b) 19
(c) 33
(d) 55
(e) 85 - 36, 34, 22, -8, -64, -154 , -286
(a) 36
(b) 22
(c) -8
(d) -64
(e) Series are correct - 3, 8, 17, 36, 73, 146, 297
(a) 3
(b) 17
(c) 297
(d) 146
(e) Series are correct - 0, 1, 9, 36, 81, 225, 441
(a) 0
(b) 1
(c) 36
(d) 81
(e) Series are correct - 5, 9, 25, 59, 125, 225, 369
(a) 59
(b) 5
(c) 25
(d) 225
(e) 369
Here are the detailed solutions for the 20 questions, each explained
- Solution: The difference between consecutive terms forms a geometric progression: 3−1=23-1 = 2, 10−3=710-3 = 7, 36−10=2636-10 = 26, and so on. These differences grow quadratically, indicating (a) 33 disrupts the pattern. Answer: (a)
- Solution: Each term is derived by multiplying the previous term by increasing numbers: 12×1=1212 \times 1 = 12, 12×1.5=1812 \times 1.5 = 18, 18×2.5=4518 \times 2.5 = 45, and so on. Missing term is 1170×10.5=122851170 \times 10.5 = 12285. Answer: (a)
- Solution: This sequence alternates between increasing and decreasing terms. Differences are irregular but follow 1091−67=10241091 – 67 = 1024, 835−1091=−256835 – 1091 = -256, 899−835=64899 – 835 = 64. The next term decreases by 6, giving 883−6=887883 – 6 = 887. Answer: (b)
- Solution: Multipliers increase sequentially: 12×2.5=3012 \times 2.5 = 30, 30×4=12030 \times 4 = 120, 120×3.833=460120 \times 3.833 = 460, and so on. The pattern suggests 460×3=1380460 \times 3 = 1380. Closest match: (c) 28082808. Answer: (c)
- Solution: Differences grow as 2,10,26,50,84,1202, 10, 26, 50, 84, 120. These differences increase by 8,16,24,…8, 16, 24, \dots. The next difference is 364−120=244364 – 120 = 244. Answer: (b)
- Solution: This sequence grows by irregular additions: 30+12=4230 + 12 = 42, 42+6=4842 + 6 = 48, 48+6=5448 + 6 = 54, 54+11=6554 + 11 = 65. The next step, 65+16=8165 + 16 = 81, follows logically. Answer: (e)
- Solution: The sequence shows exponential growth with alternating factors. For example, 159×2.97=472159 \times 2.97 = 472 and 472×4=1889472 \times 4 = 1889. Answer: (a)
- Solution: This is a decreasing sequence with constant differences: 2159−192=19672159 – 192 = 1967, 1967−185=17821967 – 185 = 1782, 1782−171=16111782 – 171 = 1611. The final term confirms 12541254 fits. Answer: (d)
- Solution: Each term is obtained by adding sequentially increasing values: 854+32=886854 + 32 = 886, 886+37=923886 + 37 = 923. Thus, the logical progression to 11071107 confirms 10071007 as the disruptor. Answer: (c)
- Solution: The growth rate reduces with 465+168=633465 + 168 = 633, 633+142=775633 + 142 = 775, 775+122=897775 + 122 = 897. Answer: (d)
- Solution: The sequence involves increasing multiplicative gaps: 12×1=1212 \times 1 = 12, 12×2.5=3012 \times 2.5 = 30, and so forth. 654654 fits the sequence. Answer: (b)
- Solution: Additive jumps increase by fixed intervals: 1275−1174=1011275 – 1174 = 101, 1445−1275=1701445 – 1275 = 170, and so forth. 11741174 disrupts. Answer: (a)
- Solution: This shows doubling growth gaps: 9→25→58→1259 \to 25 \to 58 \to 125. The missing term aligns with 531×2=1075531 \times 2 = 1075. Answer: (e)
- Solution: The sequence halves continuously: 2432/2=12182432 / 2 = 1218, 1218/2=6101218 / 2 = 610, confirming 154154 aligns correctly. Answer: (c)
- Solution: Exponential ratios appear as base powers multiply. 3939 interrupts exponential gaps—matching 823823 makes the sequence clearer. Answer: (b)
- Solution: Gaps widen arithmetically by additions: 19+5=2419 + 5 = 24, 24+9=3324 + 9 = 33. Series grows naturally to 8585. Answer: (a)
- Solution: Negative transitions accelerate geometrically, reducing rapidly. Differences align with −154-154 leading sensibly. Answer: (e)
- Solution: Doubling values persist after 7373: 36×2=7336 \times 2 = 73, confirmed sequentially in higher rounds. Answer: (d)
- Solution: Sequential squares emerge: 1,9,16,1, 9, 16,, growing logarithmically. Answer: (d)
- Solution: Direct doubling on cubes confirms 59,…,105,204,59, \dots, 105, 204,, adjusting dynamic gaps repeats in remaining higher polynomial transitions). Answer: (a)
