Question1
A store is offering a 20% discount on a $50 item. How much will the item cost after the discount?
- $30
- $50
- $40
- $55
Explanation
Correct Answer- 3
Solution 1:
To find the cost after the discount, we’ll apply the discount to the original price:
Discount = 20% of $50 = 0.20 * $50 = $10
Cost after the discount = Original price – Discount = $50 – $10 = $40
So, the item will cost $40 after the discount.
Question 2
If 3 pens cost $15, how much will 5 pens cost?
- $20
- $25
- $15
- $10
Explanation
Correct answer- 2
To find the cost of 5 pens, we can use the unitary method:
Cost of 1 pen = $15 / 3 = $5
Cost of 5 pens = 5 * $5 = $25
So, 5 pens will cost $25.
Question 3
A car travels 300 kilometers in 4 hours. What is its speed in kilometers per hour?
- 80km/hr
- 75km/hr
- 70km/hr
- 90km/hr
Explanation
To find the speed, use the formula:
Speed = Distance / Time
Speed = 300 kilometers / 4 hours = 75 kilometers per hour
The car’s speed is 75 kilometers per hour.
Question 4
A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is:?
A) 120
B) 121
C) 123
D) 122
E) None of these
Explanation
B
Explanation :
Amount after 1 year on Rs. 1600 (deposited on 1st Jan) at 5% when interest calculated half-yearly
=P(1+(R/2)100)2T=1600(1+(5/2)100)2×1=1600(1+140)2
Amount after 1/2 year on Rs. 1600 (deposited on 1st Jul) at 5% when interest calculated half-yearly
=P(1+(R/2)100)2T=1600(1+(5/2)100)2×12=1600(1+140)
Total Amount after 1 year
=1600(1+140)2+1600(1+140)=1600(4140)2+1600(4140)=1600(4140)[1+4140]=1600(4140)(8140)=41×81=Rs. 3321
Compound Interest = Rs.3321 – Rs.3200 = Rs.121
Question 5
. The ratio of the earnings of A to B is 4 :5. If the earnings of A increase by 20% and the earnings of B decrease by 20%, the new ratio of their earnings becomes 6 : 5. What are A’s earnings?
A) Rs. 20000
B) Rs. 15010
C) Rs. 5000
D) Can’t be determined
E) None of these
Explanation
. D
Can’t determined.
Question6. In an examination there are 30 question. I mark is given for each correct answer and 0.25 marks is deducted for each incorrect answer. Mohan attempted all the questions and scored 13.75 marks. How many incorrect answers did he give?
A) 10
B) 11
C) 12
D) 13
E) None of these
Explanation
D
Let the number of questions attempted by Mohan with correct answers be x. Then, total marks obtained for correct answers = x * 1 = x
And the number of questions attempted by Mohan with incorrect answers = 3Total marks deducted for incorrect answers = (30 – x)/4
Now, x – (30-x)/4 = 13.75
Or, 4x + x = 13.75 + 30 = 55 + 30 = 85 or, 5x = 85
x = 85/5 = 17
Incorrect answers = 30 – 17 = 13
0 – x.
Question 7.
The average speed of a train in the onward journey is 25% more than that in the return journey. The train halts for one hour on reaching the destination. The total time taken for the complete to and from journey is 17 hours, covering a distance of 800 km. The speed of the train in the onward journey is:
A. 45 km/h
B. 47.5km/h
C. 52km/h
D. 56.25 km/h
E. None of these
Explanation
Option(D) is correct
Explanation:
Let the speed in return journey be x km/hr.
Then, speed in onward journey =(125/100)x = (5/4)x km/hr
So. Speed in onward journey = [(5/4)*45] km/hr = 56.25 km/hr
Question 8.
30 men, working 4 hrs a day can do a piece of work in 10 days. Find the number of days in which 45 men working 8 hrs a day can do twice the work. Assume that 2 men of the first group do as much work in 2 hrs as 4 men of the second group do in 1 hr.
(a) 6(1/3) days
(b) 6(2/3) days
(c) 5(3/6) days
(d) 3(1/6) days
(e) None of these
Explanation
(b) 6(2/3) days
M1D1H1/E1W2 = M2D2H2/E2W1 (From MDH Rule)
Efficinecy of first grp : 2nd grp = 2*2 :4*1 = 1:1
Now, D2 = M1D1H1E1W2 / M2H2E2W1
D2 = 30*4*10*1*2 / 45*8*1*1
D2 = 20/3 = 6(2/3) days
Question 9
A train leaves station XX at 5am and reaches station YY at 9 am. Another train leaves station YY at 7 am and reaches station XX at 10:30 am. At what time do the two trains cross each other?
A. 7:36 am
B. 7:56 am
C. 8:36 am
D. 7:56 am
E. None of these
Explanation
Option(B) is correct
Let the distance between XX and YY is d km
Then, speed of A is d/4 km/hr and that of B is 2d/7 km/hr.
XX ——————- YY ( distance XX YY = d km)
Relative speed = d/4+2d/7=15d/28 km/hr
Now distance between these trains at 7 am =d−d/2=d/2 km
Hence, time = (d/2) / (15d/28) = 14/15×60=56
Hence both of them meet at 7:56 am
