CAT 2026 · Slot 2 · Expected paper

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CAT 2026 Slot 2 Quant Q11: Surds & Indices

TITA (type the answer) · +3 / 0 · easy

If m and n are natural numbers such that n > 1, and m^n = 2^15 × 3^10, then the value of m − n is.
Answer and solution

Correct answer: 67

Solution

Answer: 67

1. We are given:
2. mⁿ = 2¹⁵ × 3¹⁰
3. Since m and n are natural numbers, the exponent n must divide both 15 and 10.
4. The only common factor of 15 and 10 that is greater than 1 is 5.
5. Therefore, n = 5.
6. Now take the fifth root:
7. m = 2³ × 3²
m = 8 × 9
m = 72
8. Hence,
9. m − n = 72 − 5 = 67.
10. Answer: 67 (TITA).

Why this method works:
In a perfect nth power, every prime exponent is divisible by n. Here n must divide gcd(15,10)=5. The condition n>1 eliminates 1, leaving n=5 uniquely; no other prime factors can appear in m.

Independent check and common trap:
With m=72=2³×3², raising to the fifth power gives precisely 2¹⁵×3¹⁰. The final quantity is m−n, so subtract 5 from 72 after finding the base, rather than stopping at either intermediate value.

G Strategy shortcut

Spot: Number System – Exponents.
Apply: n divides both 15 and 10, with n>1: n=5. m=2³×3²=72; m−n=67.
Check: With m=72=2³×3², raising to the fifth power gives precisely 2¹⁵×3¹⁰. The final quantity is m−n, so subtract 5 from 72 after finding the base, rather than stopping at either intermediate value.

G Strategy: Spot: Number System – Exponents. Apply: n divides both 15 and 10, with n>1: n=5. m=2³×3²=72; m−n=67. Check: With m=72=2³×3², raising to the fifth power gives precisely 2¹⁵×3¹⁰. The final quantity is m−n, so subtract 5 from 72 after finding the base, rather than stopping at either intermediate value.

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