Question 4Time & Work
Answer and solution
Correct answer: 5
Solution
1. Pooja needs 12×5=60 hours alone. Nisha needs 10×6=60 hours alone. Each hourly rate is 1/60 of the job.
2. Pooja works 3 hours daily; Nisha works twice this, 6 hours daily. Let Nisha work d days and Pooja 2d days.
3. Their combined work is (3×2d)/60+(6d)/60=1.
4. Thus 12d=60 and d=5. Check: each completes 30 hours, together one full job.
Why this method works:
Convert each person’s solo schedule into hours before comparing their efficiencies:12×5 and 10×6 both equal 60. Their daily outputs differ only because they work different numbers of hours, not because one has a faster hourly rate.
Independent check and common trap:
If Nisha works 5 days at 6 hours she contributes 30 hours. Pooja works 10 days at 3 hours, also 30 hours. Together their 60 effective hours complete the job. The answer asks for Nisha’s days, not Pooja’s 10 days.
G Strategy shortcut
Spot: Time and Work.Apply: Both need 60 working hours, so hourly rates are equal. Their total hours are also equal (3×2d=6d). Each supplies half the work: Nisha needs 30/6=5 days.
Check: If Nisha works 5 days at 6 hours she contributes 30 hours. Pooja works 10 days at 3 hours, also 30 hours. Together their 60 effective hours complete the job. The answer asks for Nisha’s days, not Pooja’s 10 days.
G Strategy: Spot: Time and Work. Apply: Both need 60 working hours, so hourly rates are equal. Their total hours are also equal (3×2d=6d). Each supplies half the work: Nisha needs 30/6=5 days. Check: If Nisha works 5 days at 6 hours she contributes 30 hours. Pooja works 10 days at 3 hours, also 30 hours. Together their 60 effective hours complete the job. The answer asks for Nisha’s days, not Pooja’s 10 days.