CAT 2026 · Slot 3 · Expected paper

CAT 2026 › Slot 3 paper › Quant

CAT 2026 Slot 3 Quant: TS&W Questions with Solutions

2 questions: Q4, Q15. Solve each one here: tap the answer, press Check, then open the solution.

Question 4Time & Work

TITA (type the answer) · +3 / 0 · easy

Pooja alone would need 12 days at 5 hours a day to finish a piece of work, while Nisha alone would need 10 days at 6 hours a day to finish the same work. They both contribute to completing the same piece of work, at constant hourly rates. Nisha puts in twice as many hours per day as Pooja, while Pooja works twice as many days as Nisha. If Pooja works 3 hours a day, how many days does Nisha work?
Answer and solution

Correct answer: 5

Solution

Answer: 5

1. Pooja needs 12×5=60 hours alone. Nisha needs 10×6=60 hours alone. Each hourly rate is 1/60 of the job.

2. Pooja works 3 hours daily; Nisha works twice this, 6 hours daily. Let Nisha work d days and Pooja 2d days.

3. Their combined work is (3×2d)/60+(6d)/60=1.

4. Thus 12d=60 and d=5. Check: each completes 30 hours, together one full job.

Why this method works:
Convert each person’s solo schedule into hours before comparing their efficiencies:12×5 and 10×6 both equal 60. Their daily outputs differ only because they work different numbers of hours, not because one has a faster hourly rate.

Independent check and common trap:
If Nisha works 5 days at 6 hours she contributes 30 hours. Pooja works 10 days at 3 hours, also 30 hours. Together their 60 effective hours complete the job. The answer asks for Nisha’s days, not Pooja’s 10 days.

G Strategy shortcut

Spot: Time and Work.
Apply: Both need 60 working hours, so hourly rates are equal. Their total hours are also equal (3×2d=6d). Each supplies half the work: Nisha needs 30/6=5 days.
Check: If Nisha works 5 days at 6 hours she contributes 30 hours. Pooja works 10 days at 3 hours, also 30 hours. Together their 60 effective hours complete the job. The answer asks for Nisha’s days, not Pooja’s 10 days.

G Strategy: Spot: Time and Work. Apply: Both need 60 working hours, so hourly rates are equal. Their total hours are also equal (3×2d=6d). Each supplies half the work: Nisha needs 30/6=5 days. Check: If Nisha works 5 days at 6 hours she contributes 30 hours. Pooja works 10 days at 3 hours, also 30 hours. Together their 60 effective hours complete the job. The answer asks for Nisha’s days, not Pooja’s 10 days.

Question 15Time, Speed & Distance

MCQ · +3 / −1 · medium

Towns P and Q are 45 km apart on a straight road. Vikram starts from P towards Q, while Deepak starts from Q towards P, at the same time. They meet after 1 hour 30 minutes. Vikram reaches Q exactly 1 hour 15 minutes after Deepak reaches P. Find Vikram's speed in km/h.
Answer and solution

Correct answer: B

Solution

Answer: B — 12 km/h

1. Convert times: meeting after 1.5 hours, arrival gap 1.25 hours. Let speeds be v for Vikram and u for Deepak.

2. Meeting gives (u+v)×1.5=45, so u+v=30. Vikram arrives later, hence v<u.

3. Because both cover 45 km, 45/v−45/u=1.25. Substitute u=30−v.

4. 36(30−2v)=v(30−v), giving v²−102v+1080=0=(v−12)(v−90).

5. v=90 would make u negative. Thus v=12, u=18. Full times 3.75 and 2.5 hours differ by 1.25 hours. Answer B.

Why this method works:
The meeting-time equation uses the sum of the speeds because the travellers approach each other. Arrival times use the complete 45 km journeys measured from the common start; the difference of these full times is 1.25 hours.

Independent check and common trap:
The feasible speeds 12 and 18 sum to 30, giving 45/30=1.5 hours to meet. Their full durations are 15/4 and 5/2 hours; the difference is 5/4. The rejected root 90 would force the other speed−60, which is physically invalid.

G Strategy shortcut

Spot: Time, Speed and Distance.
Apply: Meeting gives u+v=30. Test v=12, u=18: full travel times 45/12 and 45/18 differ by 1.25 hours. Option B fits both clues.
Check: The feasible speeds 12 and 18 sum to 30, giving 45/30=1.5 hours to meet. Their full durations are 15/4 and 5/2 hours; the difference is 5/4. The rejected root 90 would force the other speed−60, which is physically invalid.

G Strategy: Spot: Time, Speed and Distance. Apply: Meeting gives u+v=30. Test v=12, u=18: full travel times 45/12 and 45/18 differ by 1.25 hours. Option B fits both clues. Check: The feasible speeds 12 and 18 sum to 30, giving 45/30=1.5 hours to meet. Their full durations are 15/4 and 5/2 hours; the difference is 5/4. The rejected root 90 would force the other speed−60, which is physically invalid.

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