Circular Arrangement – MBA CET questions with solutions

Approach: Circular arrangement, 6 seats, all facing centre (left = clockwise).

Solution:
Fix B at seat 1; seats numbered 1–6 clockwise.
A is 2nd to the left of B → seat 3.
C is opposite A → seat 6.
D is immediately right of C → seat 5.
F is to the right of A → seat 2.
E takes the last seat → 4.
Opposite of B (seat 1) is seat 4 → E.

Why the other options are wrong:
A A – opposite C.
B B – the person asked about.
C D – opposite F.
E C – opposite A.

Cetking shortcut: Opposite pairs: A–C is given, D and F sit beside them, so the only pair left for B is E.

Answer: D

Approach: Circular arrangement, 8 seats, all facing centre (left = clockwise).

Solution:
Fix Q at seat 1; seats numbered 1–8 clockwise.
P is 2nd to the right of Q → seat 7.
R is opposite Q → seat 5.
V is between P and R → seat 6.
Free seats 2, 3, 4, 8. The only opposite pair among them is 4–8 → W and S.
T is immediately left of U → U = 2, T = 3.
Final (clockwise from Q): Q, U, T, W/S, R, V, P, S/W.
Immediate right of P (seat 7) = seat 6 → V.

Why the other options are wrong:
A Q – 2nd to P's left.
C R – 2nd to P's right.
D S / E T – not adjacent to P on the right.

Answer: B

Approach: Circular arrangement, 8 seats, all facing centre (left = clockwise).

Solution:
Fix Q at seat 1; seats numbered 1–8 clockwise.
P is 2nd to the right of Q → seat 7.
R is opposite Q → seat 5.
V is between P and R → seat 6.
Free seats 2, 3, 4, 8. The only opposite pair among them is 4–8 → W and S.
T is immediately left of U → U = 2, T = 3.
Final (clockwise from Q): Q, U, T, W/S, R, V, P, S/W.
T is at seat 3 → opposite seat 7 → P.

Why the other options are wrong:
A V – seat 6, faces U (seat 2).
B W / D S – they face each other (4–8).
E U – sits next to T.

Answer: C

Approach: Circular seating (6 persons, facing centre); fix the opposite pairs first.

Solution:
F is opposite E, and F sits between A and D ⇒ A and D are F's two neighbours.
C is next to E (on E's right) and opposite A.
Seats 1–6: E = 1, F = 4. A and D take seats 3 and 5.
If C = 2 (beside E), A = 5 (opposite), D = 3, B = 6.
A's neighbours: seat 4 (F) and seat 6 (B).
(With C on the other side the figure is a mirror — A's neighbours are still B and F.)

Why the other options are wrong:
F and D: D is on F's other side, not next to A. E and C / E and F: C sits opposite A and E is two seats away. B and D: D is not adjacent to A.

Cetking shortcut: A's neighbours always include F (F is between A and D); only option D has F with a person other than D or E.

Answer: D

Approach: Chain the 'between' clues into one continuous order around the table.

Solution:
Vyom is immediately left of Dinesh → Vyom and Dinesh are neighbours.
Gopi is between Vyom and Chetan → Chetan – Gopi – Vyom – Dinesh in a row.
Pankaj is between Akash and Dinesh → Dinesh – Pankaj – Akash.
Full circle: Chetan, Gopi, Vyom, Dinesh, Pankaj, Akash (Akash next to Chetan).
With 6 seats, the person opposite is 3 seats away: from Dinesh → Pankaj (1), Akash (2), Chetan (3).

Why the other options are wrong: Vyom and Pankaj are Dinesh's neighbours; Gopi and Akash are 2 seats away.

Cetking shortcut: In a 6-seat circle, opposite = the third person in either direction — direction of facing does not matter.

Answer: D

Approach: Eight people at eight equally spaced seats = the eight compass directions.

Solution:
Order clockwise: P, Q, R, S, T, U, V, W.
Compass clockwise: N, NE, E, SE, S, SW, W, NW.
V at North → W at North-East → P at East → Q at South-East → R at South → S at South-West (T at West, U at North-West).

Why the other options are wrong: South-East is Q, South is R, East is P, North is V.

Cetking shortcut: S is 3 seats anticlockwise of V (V → U → T → S): N → NW → W → SW.

Answer: E

Approach: Pentagon arrangement: corners in cyclic order, chairs on sides.

Solution:
S is immediately right of P, and R is between P and T → corner order S, P, R, T, Q (cyclic).
Sides: S–P, P–R, R–T, T–Q, Q–S.
Chair A is on P–R; chair B is on T–Q.
D and E are next to B → on R–T and Q–S.
The remaining side S–P gets chair C.

Why the other options are wrong:
B T,S and E P,Q — T–S and P–Q are not sides (not adjacent corners).
C Q,R — not a side.
D S,Q — taken by D or E.

Answer: A