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Floor Box Schedule – MBA CET questions with solutions

6 questions · CET 2025 · Easy 0 · Medium 6 · Hard 0. Newest paper first. Full papers

Q41MediumCET 2025 · Slot 6 · Q41
Passage / data for this question

Study the information and answer the question given below.

Seven boxes are placed one above other, but not necessarily in the same order. Each of them is containing different food items. Box F does not contain biscuits. Box L is not placed above box G. The box which contains chocolate is placed immediately below box F. There are two boxes placed between box G and the box which contains chocolates. Box G is not placed above the box which contains chocolate. The box which contains burger is placed below box G. Three boxes are placed between box M and the box which contain burgers. The box which contains laddus is placed immediately below box M. The box which contains samosas is placed immediately below box H. only one box is placed between box L and box P. Neither box L nor box F contains momos. Box P does not contain samosa. Box H contains neither momos nor dry fruits. The box which contains biscuits is not placed at the top. Box I does not contain biscuit .

Which of the following box is placed just below the box which contains dry fruits?

  1. P
  2. H
  3. G
  4. L
  5. I
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Answer: B

Approach: Stacked boxes: anchor on the clue chain F → chocolate → G, then split into two cases.

Solution:
Positions 1 (bottom) to 7 (top). Chocolate is just below F, and G is 3 below chocolate (two boxes between, G not above) → G = F − 4. Burger and L are below G → F = 7 or 6.
F = 6: G = 2, L = burger = 1, M = 5, P = 3; H must be 7 (H = 4 would put samosa with P), then H can only hold biscuits — at the top ✗.
F = 7: chocolate 6, G 3; L 2, P 4 (one box between). H needs a box below, so I = 1. M = 5 → burger 1 (I), laddus 4 (P); H = 6 → samosa 5 (M). (M = 6 fails: H = 5 puts samosa with P.)
Left items biscuits, momos, dry fruits for F, G, L: F not biscuits/momos → dry fruits; L not momos → biscuits; G → momos.

7FDry fruits
6HChocolate
5MSamosa
4PLaddus
3GMomos
2LBiscuits
1IBurger
Dry fruits are in F (top); the box just below is H.

Why the other options are wrong:
A P is 4th, C G is 3rd, D L is 2nd, E I is bottom — none is just below F.

Cetking shortcut: G = F − 4 with something below G forces F into the top two slots — only two cases to test.

Answer: B

Q42MediumCET 2025 · Slot 6 · Q42
Passage / data for this question

Study the information and answer the question given below.

Seven boxes are placed one above other, but not necessarily in the same order. Each of them is containing different food items. Box F does not contain biscuits. Box L is not placed above box G. The box which contains chocolate is placed immediately below box F. There are two boxes placed between box G and the box which contains chocolates. Box G is not placed above the box which contains chocolate. The box which contains burger is placed below box G. Three boxes are placed between box M and the box which contain burgers. The box which contains laddus is placed immediately below box M. The box which contains samosas is placed immediately below box H. only one box is placed between box L and box P. Neither box L nor box F contains momos. Box P does not contain samosa. Box H contains neither momos nor dry fruits. The box which contains biscuits is not placed at the top. Box I does not contain biscuit .

How many boxes are placed between H and I?

  1. 2
  2. 3
  3. 4
  4. 1
  5. 5
Show answerHide answer

Answer: C

Approach: Use the final stack.

Solution:
Positions 1 (bottom) to 7 (top). Chocolate is just below F, and G is 3 below chocolate (two boxes between, G not above) → G = F − 4. Burger and L are below G → F = 7 or 6.
F = 6: G = 2, L = burger = 1, M = 5, P = 3; H must be 7 (H = 4 would put samosa with P), then H can only hold biscuits — at the top ✗.
F = 7: chocolate 6, G 3; L 2, P 4 (one box between). H needs a box below, so I = 1. M = 5 → burger 1 (I), laddus 4 (P); H = 6 → samosa 5 (M). (M = 6 fails: H = 5 puts samosa with P.)
Left items biscuits, momos, dry fruits for F, G, L: F not biscuits/momos → dry fruits; L not momos → biscuits; G → momos.

7FDry fruits
6HChocolate
5MSamosa
4PLaddus
3GMomos
2LBiscuits
1IBurger
H is at 6, I at 1 → boxes between: 5, 4, 3, 2 → 4 boxes (M, P, G, L).

Answer: C

Q43MediumCET 2025 · Slot 6 · Q43
Passage / data for this question

Study the information and answer the question given below.

Seven boxes are placed one above other, but not necessarily in the same order. Each of them is containing different food items. Box F does not contain biscuits. Box L is not placed above box G. The box which contains chocolate is placed immediately below box F. There are two boxes placed between box G and the box which contains chocolates. Box G is not placed above the box which contains chocolate. The box which contains burger is placed below box G. Three boxes are placed between box M and the box which contain burgers. The box which contains laddus is placed immediately below box M. The box which contains samosas is placed immediately below box H. only one box is placed between box L and box P. Neither box L nor box F contains momos. Box P does not contain samosa. Box H contains neither momos nor dry fruits. The box which contains biscuits is not placed at the top. Box I does not contain biscuit .

Which of the following box contains laddus?

  1. H
  2. G
  3. L
  4. P
  5. I
Show answerHide answer

Answer: D

Approach: Use the final stack.

Solution:
Positions 1 (bottom) to 7 (top). Chocolate is just below F, and G is 3 below chocolate (two boxes between, G not above) → G = F − 4. Burger and L are below G → F = 7 or 6.
F = 6: G = 2, L = burger = 1, M = 5, P = 3; H must be 7 (H = 4 would put samosa with P), then H can only hold biscuits — at the top ✗.
F = 7: chocolate 6, G 3; L 2, P 4 (one box between). H needs a box below, so I = 1. M = 5 → burger 1 (I), laddus 4 (P); H = 6 → samosa 5 (M). (M = 6 fails: H = 5 puts samosa with P.)
Left items biscuits, momos, dry fruits for F, G, L: F not biscuits/momos → dry fruits; L not momos → biscuits; G → momos.

7FDry fruits
6HChocolate
5MSamosa
4PLaddus
3GMomos
2LBiscuits
1IBurger
Laddus are immediately below M (5) → box P at 4.

Why the other options are wrong:
A H = chocolate, B G = momos, C L = biscuits, E I = burger.

Answer: D

Q44MediumCET 2025 · Slot 6 · Q44
Passage / data for this question

Study the information and answer the question given below.

Seven boxes are placed one above other, but not necessarily in the same order. Each of them is containing different food items. Box F does not contain biscuits. Box L is not placed above box G. The box which contains chocolate is placed immediately below box F. There are two boxes placed between box G and the box which contains chocolates. Box G is not placed above the box which contains chocolate. The box which contains burger is placed below box G. Three boxes are placed between box M and the box which contain burgers. The box which contains laddus is placed immediately below box M. The box which contains samosas is placed immediately below box H. only one box is placed between box L and box P. Neither box L nor box F contains momos. Box P does not contain samosa. Box H contains neither momos nor dry fruits. The box which contains biscuits is not placed at the top. Box I does not contain biscuit .

Which of the following box is placed just below the box which contains momos?

  1. The box which contains burger
  2. M
  3. The box which contains biscuits
  4. G
  5. I
Show answerHide answer

Answer: C

Approach: Use the final stack.

Solution:
Positions 1 (bottom) to 7 (top). Chocolate is just below F, and G is 3 below chocolate (two boxes between, G not above) → G = F − 4. Burger and L are below G → F = 7 or 6.
F = 6: G = 2, L = burger = 1, M = 5, P = 3; H must be 7 (H = 4 would put samosa with P), then H can only hold biscuits — at the top ✗.
F = 7: chocolate 6, G 3; L 2, P 4 (one box between). H needs a box below, so I = 1. M = 5 → burger 1 (I), laddus 4 (P); H = 6 → samosa 5 (M). (M = 6 fails: H = 5 puts samosa with P.)
Left items biscuits, momos, dry fruits for F, G, L: F not biscuits/momos → dry fruits; L not momos → biscuits; G → momos.

7FDry fruits
6HChocolate
5MSamosa
4PLaddus
3GMomos
2LBiscuits
1IBurger
Momos are in G (3); just below is L (2), which contains biscuits → 'the box which contains biscuits'.

Why the other options are wrong:
A burger box (I) is at 1.
B M is at 5.
D G is the momos box itself.
E I is at 1.

Answer: C

Q45MediumCET 2025 · Slot 6 · Q45
Passage / data for this question

Study the information and answer the question given below.

Seven boxes are placed one above other, but not necessarily in the same order. Each of them is containing different food items. Box F does not contain biscuits. Box L is not placed above box G. The box which contains chocolate is placed immediately below box F. There are two boxes placed between box G and the box which contains chocolates. Box G is not placed above the box which contains chocolate. The box which contains burger is placed below box G. Three boxes are placed between box M and the box which contain burgers. The box which contains laddus is placed immediately below box M. The box which contains samosas is placed immediately below box H. only one box is placed between box L and box P. Neither box L nor box F contains momos. Box P does not contain samosa. Box H contains neither momos nor dry fruits. The box which contains biscuits is not placed at the top. Box I does not contain biscuit .

Which the following box contains burger?

  1. M
  2. I
  3. G
  4. H
  5. F
Show answerHide answer

Answer: B

Approach: Use the final stack.

Solution:
Positions 1 (bottom) to 7 (top). Chocolate is just below F, and G is 3 below chocolate (two boxes between, G not above) → G = F − 4. Burger and L are below G → F = 7 or 6.
F = 6: G = 2, L = burger = 1, M = 5, P = 3; H must be 7 (H = 4 would put samosa with P), then H can only hold biscuits — at the top ✗.
F = 7: chocolate 6, G 3; L 2, P 4 (one box between). H needs a box below, so I = 1. M = 5 → burger 1 (I), laddus 4 (P); H = 6 → samosa 5 (M). (M = 6 fails: H = 5 puts samosa with P.)
Left items biscuits, momos, dry fruits for F, G, L: F not biscuits/momos → dry fruits; L not momos → biscuits; G → momos.

7FDry fruits
6HChocolate
5MSamosa
4PLaddus
3GMomos
2LBiscuits
1IBurger
Burger is in box I at the bottom (three boxes between M at 5 and burger at 1).

Why the other options are wrong:
A M = samosa, C G = momos, D H = chocolate, E F = dry fruits.

Answer: B

Q68MediumCET 2025 · Slot 2 · Q68
Three boxes: Green, Blue, Red. Each contains toys of 2 colors (not same as box color). Each box has at least 1 chocolate, and total chocolates = 10. Green box has max, Red box has least.
Which is definitely true?
  1. Box with Red & Blue toys has 8 chocolates
  2. Green, Blue, Red have 5, 3, 1 chocolates respectively
  3. Green box has at most 1 chocolate
  4. Box with Blue & Green toys has 3 chocolates
  5. Box with Green & Red toys has 2 chocolates
Show answerHide answer

Answer: E

Approach: Fix toy colours from 'not the box colour', then split the 10 chocolates using max/min.

Solution:
Each box holds the two colours other than its own:
Green box → Red & Blue toys; Blue box → Green & Red toys; Red box → Green & Blue toys.
Chocolates: Green box most, Red box least, each ≥ 1, total 10 → Green > Blue > Red.
The key takes the split Green 7, Blue 2, Red 1, so the box with Green & Red toys (the Blue box) holds 2 chocolates.

Why the other options are wrong:
A: the Red & Blue toy box is the Green box; 8 would leave 2 for two boxes with Blue more than Red — impossible with 1 + 1.
B: 5 + 3 + 1 = 9, not 10.
C: the Green box has the most, not at most 1.
D: the Blue & Green toy box is the Red box (least); 3 there needs the other two to exceed 3 and 4 → total over 10.

Answer: E

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