New type Logical Reasoning MBA CET 2024  Slot 4

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  1. There is a lot of interest in the first five ranks for Class XI students. One student guessed the rank order as Ankita, Bhagyashree, Chanchal, Devroopa and Esha. Later upon announcement of the results, it was found that not only did he get each student out off her true position, none of the students in his ranking correctly followed her immediate predecessor. Another student guessed Devroopa, Ankita, Esha, Chanchal and Bhagyashree. Even his guess was wrong. It was found that he had got two positions correct, and two students in his ranking correctly followed their immediate predecessors.
  2. Which of the following is true about the correct rank order?
  3. a) Devroopa got the first position
  4. b) Esha got the fourth position
  5. c) Bhagyashree got the fourth position
  6. d) Chanchal got the second position
  7. e) Ankita got the third position

It is given that A – 1, B – 2, C – 3,D – 4 and E – 5 is
wrong. The rank of none of the student matched and no
student followed her immediate predecessor.
D – 1, A – 2, E – 3, C – G, B – 5 has two correct and two
students correctly followed the predecessor. The two
conditions can be satisfied when either 1 and 2 or 4 and
5 are correct rankers and one of these two pairs is the
one which correctly followed the predecessor. The other
one which correctly followed the predecessor should be
one from the other three.
Case (i), D – 1, A – Z are correct ranks. In this case C –
4 or B – 5 correctly followed the predecessor apart form
A – Z. Then the possible correct arrangements are:
D – 1 D – 1
A – 2 A – 2
B – 3 or C – 3
E – 4 B – 4
C – 5 E – 5
(a) (b)
Here in (b) C – 3 and E – 5 are same as the guess made
by the first student in which all are wrong. Hence, (b) is
eliminated. In case (a) B is following A as in the guess
made by the first student. Hence (a) is also eliminated.
case (ii): C – 4, B – 5 are correct ranks.
In this case A – 2 or E – 3 correctly followed the
predecessor apart form B – 5. Then the possible correct
arrangements are

A – 1 E – 1
E – 2 D –2
D – 3 A – 3
C – 4 or C – 4
B – 5 B – 5
(c) (d)
In (c) A – 1 is matching with the guess of the first
student. Hence, (c) is eliminated. Arrangement (d)
satisfied all the conditions. Hence, it is true that Ankit got
the third
position.

  1. Two ants A and B start from a point P on a circle at the same time, with A moving clock-wise and B moving anti-clockwise. They meet for the first time at 10:00 am when A has covered 60% of the track. If A returns to P at 10:12 am, then B returns to P at:
    a) 10:49 AM
    b) 10:23 AM
    c) 10:27 AM
    d) 10:39 AM
    e) 10:45 AM 

When the A covers 60% of the distance,
The remaining distance covered by B is
40%.
Ratio of distance A and B = 60% / 40% =
3/2
We know that time is inversely
proportional to distance. So, the Ratio of
time A and B = 2/3
Here given A covers 60% of the distance at
10:00 AM and covers 100% of the distance

at 10:12 AM. A takes 12 minutes to cover
40% of the track
Time taken to cover 40% distance = 12
minutes
Time taken to cover 1% distance = (12/40)
minutes
Time taken to cover 100% distance = 30
minutes
So, cover the whole track Time taken by A
= 30 minutes
The time taken by A and B to complete the
track are in the ratio 2:3
So, the time is taken by B to complete the
track = (3/2) * 30 = 45 minutes.
Remaining distance covers by B = 60%
100% distance covered by B = 45 minutes
1% distance covered by B = (45/100)
minutes
60% distance covered by B = 27 minutes
So, B complete one complete round at
10:27 AM.

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