Quant Questions

The number 63_42_0 is a 7-digit number divisible by both 3 and 5. If the thousands digit is greater than the tens digit, which of the following options gives the correct digits in the thousands place and the tens place respectively? Bank PO 2012

A) 3, 1 B) 6, 4 C) 9, 7 D) 9, 6 E) 3, 9

Correct Answer: Wrong Question

Number: 63_42_0
Digits are: 6, 3, x, 4, 2, y, 0
So thousands digit is fixed = 4.

Condition given:
Thousands digit > Tens digit ⇒ 4 > y ⇒ y < 4

Now apply divisibility by 3:

Sum of digits = 6 + 3 + x + 4 + 2 + y + 0 = 15 + x + y
For divisibility by 3 ⇒ x + y must be divisible by 3

Check options (x = 3rd digit, y = tens):

A) 3,1 → x+y = 4 ❌
B) 6,4 → y=4 ❌ (not < 4)
C) 9,7 → y=7 ❌
D) 9,6 → y=6 ❌
E) 3,9 → y=9 ❌

Mistake: in the question it should be Ten thousands digit not thousand digit.