MBA CET 2025 Slot 3 question paper with solutions

Approach: Place value − face value of a digit.

Solution: In 32675149, read places from the right: 9 (units), 4 (tens), 1 (hundreds), 5 (thousands), 7 (ten-thousands).
Local value of 7 = 7 × 10,000 = 70,000.
Face value of 7 = 7.
Difference = 70,000 − 7 = 69,993.

Cetking shortcut: Place value − face value = digit × (10ⁿ − 1) = 7 × 9999 = 69,993.

Answer: C

Approach: Take the common factor 8796 out.

Solution: 8796 × 223 + 8796 × 77 = 8796 × (223 + 77) = 8796 × 300.
8796 × 3 = 26,388 → × 100 = 2,638,800.

Cetking shortcut: Last digits: 6 × 300 ends in 800; only B (2638800) ends in 800 with the right size — E ends 700.

Answer: B

Approach: Divisibility test for 11 (alternate-digit difference).

Solution: Odd-place digits (from right) minus even-place digits:
A. 4823718: (8+7+2+4) − (1+3+8) = 21 − 12 = 9 → no
B. 4832718: (8+7+3+4) − (1+2+8) = 22 − 11 = 11 → divisible ✔
C. 8423718: (8+7+2+8) − (1+3+4) = 25 − 8 = 17 → no
D. 8432718: (8+7+3+8) − (1+2+4) = 26 − 7 = 19 → no
E. 4833777: (7+7+3+4) − (7+3+8) = 21 − 18 = 3 → no

Cetking shortcut: A and B differ only by swapping two adjacent digits (2,3); a swap changes the difference by 2 each step — test one pair and you know the other.

Answer: B

Approach: 225 = 25 × 9 → apply both divisibility tests.

Solution: Divisible by 25 → last two digits 7q must be 00, 25, 50 or 75 → 7q = 75 → q = 5.
Divisible by 9 → digit sum 8 + 7 + 6 + p + 3 + 7 + 5 = 36 + p must be a multiple of 9 → p = 0 (or 9).
Both p = 0 and p = 9 pass the tests; the standard answer takes the smaller digit, so p = 0 and q = 5.

Why the other options are wrong: A, B, E have q = 3 or 0 → 73/70 not divisible by 25; D (9, 5) also satisfies both divisibility tests, so the question is ambiguous; the stored answer is the smaller-digit pair C.

Cetking shortcut: Fix q from the 25-rule first — it eliminates A, B, E instantly.

Answer: C

Approach: Multiples of both 10 and 13 = multiples of LCM(10, 13).

Solution: LCM(10, 13) = 130 (co-prime).
Multiples of 130 below 1000: 130, 260, …, 910.
Count = ⌊999 ÷ 130⌋ = 7 (since 130 × 8 = 1040 > 1000).

Answer: B

Approach: HCF must be a factor of LCM.

Solution: 9570 = 2 × 3 × 5 × 11 × 29.
Check options: 11 → 9570 ÷ 11 = 870 ✔; 12 = 2²×3 → needs 2², not present ✘; 19 → not a prime factor ✘; 23 → not a prime factor ✘.
So 11 can be the HCF (e.g. 11, 330 and 9570 have HCF 11 and LCM 9570).

Why the other options are wrong: 12, 19, 23 do not divide 9570. Note: 10 (E) also divides 9570 and is achievable (e.g. 10, 290, 330), so the question is ambiguous; the stored answer is 11.

Cetking shortcut: Prime-factorise the LCM once; any option with a prime (or power) not in it is out.

Answer: A

Approach: N = LCM(16, 18, 20, 25)·k + 4, then make N divisible by 7.

Solution: 16 = 2⁴, 18 = 2·3², 20 = 2²·5, 25 = 5² → LCM = 2⁴·3²·5² = 3600.
N = 3600k + 4. 3600 ÷ 7 leaves remainder 2, 4 ÷ 7 leaves 4 → N ≡ 2k + 4 (mod 7).
2k + 4 ≡ 0 (mod 7) → 2k ≡ 3 → k = 5 (2·5 + 4 = 14 ✔).
N = 3600 × 5 + 4 = 18,004.

Cetking shortcut: Every option must be 4 more than a multiple of 3600 → only 18004 fits (18000 + 4); check 18004 ÷ 7 = 2572 ✔.

Answer: D

Approach: Left-to-right division then multiplication, then isolate ?.

Solution: 786 ÷ 24 = 32.75.
32.75 × ? = 6.55 → ? = 6.55 ÷ 32.75 = 0.2.
Check: 32.75 × 0.2 = 6.55 ✔

Cetking shortcut: 6.55 is one-fifth of 32.75 (32.75 ÷ 5 = 6.55) → ? = 1/5 = 0.2.

Answer: C

Approach: Heads–legs equation.

Solution: Let buffaloes = B, ducks = D.
Heads = B + D; legs = 4B + 2D.
4B + 2D = 2(B + D) + 24 → 4B + 2D = 2B + 2D + 24 → 2B = 24 → B = 12.

Cetking shortcut: Each buffalo has 2 'extra' legs over 2-per-head; 24 extra legs ÷ 2 = 12 buffaloes.

Answer: D

Approach: Find the largest perfect square not exceeding 36581.

Solution: 190² = 36,100; 191² = 36,481; 192² = 36,864 (> 36,581).
So the largest square uses 191 rows → 36,481 soldiers.
Left over = 36,581 − 36,481 = 100.

Cetking shortcut: 191² = (190 + 1)² = 36,100 + 380 + 1 = 36,481.

Answer: C

Approach: Weighted average of two groups (50.25 and 45.15 are the average weights of each group).

Solution: Total of 16 boys = 16 × 50.25 = 804 kg.
Total of 8 boys = 8 × 45.15 = 361.2 kg.
Total of 24 boys = 804 + 361.2 = 1165.2 kg.
Average = 1165.2 ÷ 24 = 48.55 kg.

Cetking shortcut: Weights 16:8 = 2:1 → average = 45.15 + (2/3)(50.25 − 45.15) = 45.15 + 3.40 = 48.55.

Answer: C

Approach: Total = average × count, then undo the change.

Solution: If the best scorer had 92, team total = 8 × 84 = 672.
He actually scored 85, i.e. 92 − 85 = 7 points less.
Actual team total = 672 − 7 = 665.

Answer: C

Approach: Identity a² − b² = (a + b)(a − b).

Solution: a + b = 20, a − b = 8.
a² − b² = 20 × 8 = 160.
(Check: numbers are 14 and 6 → 196 − 36 = 160 ✔)

Answer: C

Approach: Present ages 5x and 3x; use the 1:1 condition.

Solution: A's age 4 years ago = B's age 4 years hence:
5x − 4 = 3x + 4 → 2x = 8 → x = 4.
A = 20, B = 12.
A's age 4 years hence = 24; B's age 4 years ago = 8.
Ratio = 24 : 8 = 3 : 1.

Answer: B

Approach: Age difference is constant; combine with the 'one year ago' multiple.

Solution: Six years hence Promila exceeds Sakshi by 9 → difference is always 9: P − S = 9.
One year ago: P − 1 = 4(S − 1) → P = 4S − 3.
4S − 3 − S = 9 → 3S = 12 → S = 4, P = 13.
Ratio = 13 : 4.

Cetking shortcut: One year ago difference 9 = 4k − k = 3k → k = 3 → ages then 12 and 3 → now 13 and 4.

Answer: D

Approach: Part ÷ total × 100.

Solution: Total alloy = 5 + 20 = 25 kg.
% of A = 5/25 × 100 = 20%.

Why the other options are wrong: 25% comes from 5/20 (wrong base).

Answer: A

Approach: Multiply chained percentages.

Solution: Let C = 100. B = 25% of 100 = 25. A = 40% of 25 = 10.
A is 10% of C.

Answer: B

Approach: Final price = MP × 0.88 × 0.95.

Solution: 0.88 × 0.95 = 0.836.
0.836 × MP = 209 → MP = 209 ÷ 0.836 = 250.

Cetking shortcut: Check options: 250 × 0.88 = 220, 220 × 0.95 = 209 ✔.

Answer: B

Approach: Assume MP = 100.

Solution: CP = 64.
SP after 12% discount = 88.
Profit = 88 − 64 = 24.
Gain % = 24/64 × 100 = 37.5%.

Answer: A

Approach: Let list price = 100.

Solution: CP = 100 − 25% = 75.
Required SP = 100 + 25% of 100 = 125.
% above CP = (125 − 75)/75 × 100 = 50/75 × 100 = 66.67%.

Why the other options are wrong: 50% uses the list price as base; 25% ignores the discount.

Answer: D

Approach: Build one continued ratio A : B : C : D.

Solution: A:B = 2:3, B:C = 4:5 → make B equal (LCM 12): A:B:C = 8:12:15.
C:D = 6:7 → make C equal (LCM of 15 and 6 = 30): A:B:C:D = 16:24:30:35.
Sum = 16 + 24 + 30 + 35 = 105 parts.
A = 16/105 × 8400 = 16 × 80 = 1280.

Cetking shortcut: A:B:C:D = (2·4·6) : (3·4·6) : (3·5·6) : (3·5·7) = 48:72:90:105 = 16:24:30:35.

Answer: A

Approach: Incomes 5x, 3x; expenditures 9y, 5y.

Solution: 5x − 9y = 2600 …(1)
3x − 5y = 1800 …(2)
(1)×5: 25x − 45y = 13000; (2)×9: 27x − 45y = 16200.
Subtract: 2x = 3200 → x = 1600.
Incomes = 5 × 1600 = 8000 and 3 × 1600 = 4800.
Check: expenditures 8000 − 2600 = 5400, 4800 − 1800 = 3000 → 5400:3000 = 9:5 ✔

Cetking shortcut: Option check — subtract savings from each option's incomes and test 9:5: only D gives 5400:3000 = 9:5.

Answer: D

Approach: Track the gap Y − X year by year.

Solution: In 2002, Y − X = 630 − 420 = 210 (Y higher).
Each year X gains 40 − 15 = 25 on Y.
Required: X − Y = +40 → total change needed = 210 + 40 = 250.
Years = 250 ÷ 25 = 10 → 2002 + 10 = 2012.

Answer: C

Approach: Total time = 4 periods + 3 breaks (no break after the last period).

Solution: 10:00 am to 1:27 pm = 3 h 27 min = 207 min.
Breaks = 3 × 5 = 15 min.
Period time = 207 − 15 = 192 min → each period = 192 ÷ 4 = 48 min.

Answer: B

Approach: Let tank capacity = C, daily inflow = S.

Solution: C + 50S = 50 × 32000 = 16,00,000
C + 40S = 40 × 37000 = 14,80,000
Subtract: 10S = 1,20,000 → S = 12,000 gallons/day.
If daily use = inflow = 12,000 gallons, the level never drops → supply never fails.

Cetking shortcut: This is the 'grass-grows / cattle-graze' pattern: inflow = (D1·T1 − D2·T2)/(T1 − T2).

Answer: A

Approach: Express work in child-days.

Solution: Work = 16 × 12 = 192 man-days = 24 × 18 = 432 child-days → 1 man = 432/192 = 2.25 children.
12 men + 8 children = 27 + 8 = 35 child-units.
Work in 8 days = 35 × 8 = 280 → remaining = 432 − 280 = 152.
Now 35 + 3 = 38 child-units → days = 152 ÷ 38 = 4.

Answer: B

Approach: Sum the distances of the three segments.

Solution: Segment times: 15 min = 1/4 h (speed x), 20 min = 1/3 h (speed 2x), 10 min = 1/6 h (speed x).
Distance = x/4 + 2x/3 + x/6 = (3x + 8x + 2x)/12 = 13x/12.
13x/12 = 39 → x = 36 km/h.

Cetking shortcut: Effective 'x-minutes' = 15 + 2×20 + 10 = 65 min at speed x → 39 km in 65 min → x = 39 × 60/65 = 36.

Answer: B

Approach: Distance is equal both ways.

Solution: 8(x − 4) = 6(x + 4) → 8x − 32 = 6x + 24 → 2x = 56 → x = 28 km/h.

Cetking shortcut: Speeds are in ratio 6:8 = 3:4 (up:down) → difference 1 part = 2 × current = 8 → part = 8 → still water = (3 + 4)/2 × 8 = 28.

Answer: C

Approach: Relative speed = (sum of lengths) ÷ time.

Solution: Relative speed = (100 + 100)/8 = 25 m/s.
Speeds x and 2x → 3x = 25 → faster = 2x = 50/3 m/s.
In km/h: 50/3 × 18/5 = 60 km/h.

Answer: C

Approach: A is untouched by the replacement except for the removed share.

Solution: Let the can hold 12k litres: A = 7k, B = 5k.
9 litres drawn: A removed = 9 × 7/12 = 5.25, B removed = 3.75.
After adding 9 litres of B: A = 7k − 5.25, B = 5k + 5.25.
(7k − 5.25)/(5k + 5.25) = 7/9 → 63k − 47.25 = 35k + 36.75 → 28k = 84 → k = 3.
Initial A = 7k = 21 litres.

Cetking shortcut: Total stays 12k. A goes from 7/12 to 7/16 of it → A × (1 − 9/12k) = 7/16·12k → 7k − 5.25 = 5.25k → k = 3.

Answer: C

Approach: Total = n² paise.

Solution: Rs 59.29 = 5929 paise.
n² = 5929 → n = 77 (since 77² = 5929).

Cetking shortcut: 5929 ends in 9 → root ends in 3 or 7; 70² = 4900 and 80² = 6400 → 77.

Answer: C

Approach: Find the largest square ≤ 549162.

Solution: 740² = 547,600; 741² = 549,081; 742² = 550,564 (too big).
549,162 − 549,081 = 81.

Cetking shortcut: 741² = 740² + 740 + 741 = 547,600 + 1,481 = 549,081.

Answer: D

Approach: Use 52416 ÷ 168 = 312 (equivalent to the given fact) and adjust decimals.

Solution: Given 52416 ÷ 312 = 168 ⇔ 52416 ÷ 168 = 312.
52.416 ÷ 0.0168 = (52416 × 10⁻³) ÷ (168 × 10⁻⁴) = 312 × 10 = 3120.

Answer: C

Approach: Error changes from −2 min to +4 min 48 s uniformly.

Solution: Time elapsed: Monday 12 noon → next Monday 2 pm = 7 days 2 h = 170 h.
Total gain = 2 min + 4 min 48 s = 6 min 48 s = 6.8 min.
To be correct it must gain 2 min → time needed = 170 × 2/6.8 = 50 h.
Monday 12 noon + 50 h = Wednesday 2 pm.

Answer: B

Approach: Ladder = hypotenuse; distance from wall = adjacent side.

Solution: cos 60° = 4.6 / L → 1/2 = 4.6 / L → L = 9.2 m.

Answer: B

Approach: Combinations without replacement.

Solution: Total ways = ²⁰C₂ = 190.
Both white = ¹⁰C₂ = 45; both black = 45 → favourable = 90.
P = 90/190 = 9/19.

Cetking shortcut: First ball any colour; second must match: 9 of remaining 19 → 9/19.

Answer: A

Approach: P(exactly one truthful).

Solution: A true, B lies = 0.75 × 0.20 = 0.15.
A lies, B true = 0.25 × 0.80 = 0.20.
Total = 0.35 = 35%.

Answer: C

Approach: Product of digits.

Solution: 331 → 3×3×1 = 9 = 3²
482 → 4×8×2 = 64 = 8²
551 → 5×5×1 = 25 = 5²
263 → 2×6×3 = 36 = 6²
383 → 3×8×3 = 72 (not a perfect square)
242 → 2×4×2 = 16 = 4²
111 → 1 = 1²
Only 383 breaks the pattern.

Why the other options are wrong: 263, 242, 111, 551 all give perfect-square digit products.

Answer: B

Approach: Successive differences.

Solution: 789 − 144 (12²) = 645
645 − 100 (10²) = 545
545 − 64 (8²) = 481
481 − 36 (6²) = 445 (given 440 ✘)
445 − 16 (4²) = 429 ✔
429 − 4 (2²) = 425 ✔
The wrong term is 440; it should be 445.

Answer: D

Approach: Area constant.

Solution: Area = 18 × 10 = 180 cm².
New breadth = 180 ÷ 25 = 7.2 cm.

Answer: C

Approach: Add the shares of M and S in the graduate pie, then take that % of 27,300.

Solution: Graduate pie: M = 17%, S = 14% → 31%.
31% of 27,300 = 0.31 × 27,300 = 8,463.

Cetking shortcut: 1% of 27,300 = 273 → 31 × 273 = 8,463.

Answer: B

Approach: Add the PG shares of N and P, then take that % of 24,700.

Solution: Post-graduate pie: N = 15%, P = 12% → 27%.
27% of 24,700 = 0.27 × 24,700 = 6,669.

Cetking shortcut: 1% = 247 → 27 × 247 = 6,669.

Answer: C

Approach: R's graduate count + R's PG count.

Solution: Graduate: 18% of 27,300 = 4,914.
Post-graduate: 14% of 24,700 = 3,458.
Total = 4,914 + 3,458 = 8,372.

Cetking shortcut: Units digits: 18×273 ends in 4, 14×247 ends in 8 → sum ends in 2; only 8,372 ends in 2.

Answer: D

Approach: PG(S) : G(S) = (21% × 24,700) : (14% × 27,300).

Solution: PG = 0.21 × 24,700 = 5,187; G = 0.14 × 27,300 = 3,822.
Ratio = (21 × 247) : (14 × 273) = (21 × 13 × 19) : (14 × 3 × 7 × 13) = (21 × 19) : (14 × 21) = 19 : 14.

Cetking shortcut: 247 = 13 × 19 and 273 = 13 × 21 → cancels to 19:14 in one line.

Answer: D

Approach: Use percentages for the union, then convert once.

Solution: Union = 60% + 30% − 15% = 75%.
Neither = 100% − 75% = 25%.
25% of 96 = 24.

Answer: B

Approach: Income = E × (1 + P/100).

Solution: From the graph, Y's profit % in 2007 = 35%.
Income = 220 × 1.35 = 297 crore.

Answer: C

Approach: E = I ÷ (1 + P/100); incomes equal.

Solution: From the graph, 2009: X = 50%, Y = 60%.
E_X = I/1.5, E_Y = I/1.6.
E_X : E_Y = 1/1.5 : 1/1.6 = 1.6 : 1.5 = 16 : 15.

Why the other options are wrong: 15:16 (E) results from reading X as 60% and Y as 50%; 6:5 / 5:6 ignore the '1 +' in the income formula.

Cetking shortcut: X has the lower profit %, so X must spend more → ratio > 1 → only 6:5, 11:6, 16:15 survive; 160:150 = 16:15.

Answer: D

Approach: Divide each income by (1 + profit%).

Solution: From the graph, 2010: X = 65%, Y = 50%.
E_X : E_Y = 3/1.65 : 4/1.5 = (3 × 1.5) : (4 × 1.65) = 4.5 : 6.6 = 45 : 66 = 15 : 22.

Answer: A

Approach: Water lost through the waste pipe = water added in the extra 4 minutes.

Solution: Inlets together: 1/10 + 1/15 = 1/6 per min → bath should fill in 6 min.
Extra 4 min with both inlets adds 4/6 = 2/3 of the bath.
So the waste pipe drained 2/3 of the bath in 6 min → full bath in 6 × 3/2 = 9 min.

Answer: C

Approach: LCM method — total work = 60 units.

Solution: X = 60/20 = 3 units/day, Y = 60/12 = 5 units/day.
X alone 4 days = 12 units → remaining 48 units.
Together 8 units/day → 48/8 = 6 days.
Total duration = 4 + 6 = 10 days.

Answer: B

Approach: Synonym — find the word closest in meaning to DESECRATE.

Solution: Desecrate = to violate or spoil something sacred (de- = remove + sacred).
Defile = to make something holy impure or dishonour it — the same meaning.

Why the other options are wrong:
B. Protect — guarding something sacred; opposite in spirit.
C. Purify — making clean/holy; an antonym.
D. Honour — showing respect; an antonym.
E. Sanctify — making holy; the direct antonym.

Cetking shortcut: Four options (Protect, Purify, Honour, Sanctify) are all 'positive/holy' words — the odd negative one is the synonym.

Answer: A

Approach: Synonym — find the word closest in meaning to CANTANKEROUS.

Solution: Cantankerous = bad-tempered, argumentative, uncooperative.
Quarrelsome = inclined to argue or fight — the same meaning.

Why the other options are wrong:
B. Cheerful — happy; opposite.
C. Easygoing — relaxed, tolerant; opposite.
D. Pleasant — agreeable; opposite.
E. Nice — kind; opposite.

Cetking shortcut: B, C, D, E are all positive words with the same flavour — the only negative word must be the synonym.

Answer: A

Approach: RC inference — capture the full meaning of the first sentence, including its qualifier.

Solution: Sentence 1: 'an explosion of growth opportunities for women in industry, especially at the decision-making level'.
Decision-making level = managerial level. So the sentence implies that opportunities for women at the managerial level have increased.

Why the other options are wrong:
A. For women have increased — true but incomplete; it drops the stress on the decision-making level.
B. In industry have increased — loses the subject 'for women'.
D. In the corporate sector — incomplete statement; says nothing about increase.
E. For the men — the passage is about women.

Cetking shortcut: Pick the option that contains every key word of the sentence: women + decision-making (managerial) + increase.

Answer: C

Approach: Vocabulary in context — meaning of 'male bastions'.

Solution: Bastion = fortress/stronghold. 'Storm the traditional male bastions of management' = enter the management areas that men have traditionally held and dominated.

Why the other options are wrong:
A. Management style of male — a style is not a place one 'storms'.
C. Careers for male — too broad; the passage is about management.
D. Management abilities of male — abilities are not strongholds.
E. Careers of women — opposite of 'male'.

Answer: B

Approach: RC detail — read the 'not only … but' line carefully.

Solution: Last sentence: the battle calls into play 'not only the forces of power, control and dominance, but issues of gender, attitude and acceptance of women'.
The extra problems women in high positions also have are gender-related — how society sees and accepts the role of women. That is option D.

Why the other options are wrong:
A. No problems at all — contradicts 'roads to success are paved with difficulties'.
B. Some problems — too vague; does not say which.
C. Power and control — the common battle for everyone, not the additional women-specific problem.
E. Competitive edge — an opportunity, not a problem.

Cetking shortcut: 'Also' + 'not only X but Y' → the answer is Y.

Answer: D

Approach: Antonym — find the word opposite in meaning to EXTOL.

Solution: Extol = praise enthusiastically.
Disparage = speak of something as having little worth; belittle — the exact opposite.

Why the other options are wrong:
A. Loud — unrelated adjective.
B. Glorify — synonym.
C. Celebrate — synonym.
E. Eulogize — synonym (praise highly).

Cetking shortcut: Three options mean 'praise' — strike them out; the only negative verb is the antonym.

Answer: D

Approach: Antonym — find the word opposite in meaning to EXALT.

Solution: Exalt = raise in rank, praise highly.
Depreciate = lower in value; disparage — the opposite.

Why the other options are wrong:
A. Simplify — unrelated.
C. Glorify — synonym.
D. Ennoble — synonym (make noble).
E. Appreciate — close to a synonym.

Answer: B

Approach: Antonym — find the word opposite in meaning to FORLORN.

Solution: Forlorn = pitifully sad and lonely.
Elated = extremely happy — the opposite.

Why the other options are wrong:
A. Desolate — synonym.
B. Sad — synonym.
C. Woebegone — synonym (sorrowful-looking).
E. Pitiable — synonym in flavour.

Cetking shortcut: Four options are 'sad' words — the one happy word is the antonym.

Answer: D

Approach: Antonym — find the word opposite in meaning to ASTUTE.

Solution: Astute = sharp, shrewd, quick to judge a situation well.
Foolish = lacking good sense — the opposite.

Why the other options are wrong:
A. Cowardly — opposite of brave, not of clever.
C. Wicked — opposite of good, not of clever.
D. Impolite — about manners.
E. Brilliant — synonym.

Answer: B

Approach: Antonym — find the word opposite in meaning to ACCLAMATION.

Solution: Acclamation = loud, enthusiastic approval.
Denunciation = public condemnation — the opposite.

Why the other options are wrong:
B. Jubilation — great joy; close to a synonym.
C. Plaudits — praise; synonym.
D. Applause — synonym.
E. Honour — positive; synonym-flavoured.

Cetking shortcut: All options except one are 'praise' words — the lone negative is the answer.

Answer: A

Approach: Animal homes — recall the special name for a squirrel's nest.

Solution: A squirrel builds a nest of twigs and leaves high in a tree; this nest is called a drey.
Completed sentence: 'The squirrel's nest is known as a drey.'

Why the other options are wrong:
A. Stable — home of a horse.
B. Coop — home of hens/poultry.
C. Den — home of a lion or wild beast.
D. Burrow — home of a rabbit or rat.

Answer: E

Approach: Question tag — positive statement → negative tag, using the auxiliary of the verb.

Solution: 'She used to walk …' is simple past; 'used to' has no auxiliary of its own, so the tag uses did.
Positive statement → negative tag: '… didn't she?'

Why the other options are wrong:
A. does she — present tense and positive; both wrong.
B. will she — future, and positive.
C. was she — 'was' is not the auxiliary of 'used to'.
E. won't she — future tense.

Cetking shortcut: Statement positive → tag negative; 'used to' always takes 'didn't'.

Answer: D

Approach: Question tag — repeat the auxiliary of the statement with opposite polarity.

Solution: The statement uses the past auxiliary was and is positive, so the tag is negative 'was': 'He was weary of failure, wasn't he?'

Why the other options are wrong:
A. does he — wrong auxiliary and polarity.
B. won't he — future tense.
D. isn't he — present tense.
E. do he — wrong auxiliary and agreement.

Answer: C

Approach: Error spotting — check each part; if every part is correct, mark No error.

Solution: (A) 'It being a holiday' — a correct absolute phrase (its own subject 'It').
(B) 'all the hostel inmates' — correct plural subject.
(C) 'decided to celebrate' — correct (decide + to-infinitive).
(D) 'by going out to a movie' — 'by + -ing' correctly shows how they celebrated.
No part has an error.

Why the other options are wrong:
A, B, C, D — each part is grammatically correct, as shown above.

Cetking shortcut: 'By + -ing' to show the means of an action is standard; do not change it to 'with'.

Answer: E

Approach: Error spotting — redundancy (superfluous word).

Solution: 'The higher we climb … the cooler we feel' is the correct 'the + comparative …, the + comparative' structure, so parts (A), (C) and (D) are fine.
In (B), 'up' is superfluous because climb already means 'go up'.
Correct: 'The higher we climb the mountain peak, the cooler we feel.'

Why the other options are wrong:
A. 'The higher we climb' — correct comparative structure.
C. 'the cooler' — correct parallel comparative.
D. 'we feel' — correct verb.
E. No error — wrong, because (B) contains the redundant 'up'.

Cetking shortcut: Common redundancies in CET: climb up, return back, repeat again, revert back.

Answer: B

Approach: RC — 'best supports' inference: choose what follows directly from the text.

Solution: Rationalism aims at a system of philosophy and ethics 'verifiable by experience and independent of arbitrary assumptions'.
So rationalism is not a set of beliefs without verification — option C restates this.

Why the other options are wrong:
A. Says ethics is not part of philosophy — the text puts them side by side and never says this.
B. Says one must accept certain beliefs — the text says rationalism is independent of assumptions.
D. Says 'mental attitude' in general is free of assumptions — the text says this only of rationalism's aim.
E. Says only RPA can establish rationalism — RPA only framed the definition.

Cetking shortcut: Look for a paraphrase of the key phrase ('verifiable by experience' = 'not devoid of verification').

Answer: C

Approach: Vocabulary in context — meaning of 'unreservedly'.

Solution: 'Unreservedly accepts the supremacy of reason' = accepts it without any reservation or condition = fully.

Why the other options are wrong:
A. Unilaterally — done by one side only; a different idea.
B. Collectively — done as a group.
C. Partially — opposite.
E. Conditionally — opposite (with reservations).

Answer: D

Approach: Fixed preposition with an adjective.

Solution: The intended sentence is 'He is blind … one eye'. The classic grammar-book usage (Wren & Martin) is 'blind of one eye' (in modern English also 'blind in one eye').
Among the options, 'of' is the correct preposition.

Why the other options are wrong:
B. to — 'blind to' means unaware of something (blind to his faults), not loss of sight.
C. with — no such usage with 'blind'.
D. for — no such usage.
E. by — no such usage.

Cetking shortcut: Fixed pairs: blind of an eye, lame of a leg, deaf of an ear.

Answer: A

Approach: Fixed preposition — 'vexed with' a person, 'vexed at' a thing.

Solution: 'My brother' is a person, so the correct preposition is with: 'I am vexed with my brother.'

Why the other options are wrong:
A. at — used for a thing: vexed at his conduct.
C. of — no such usage.
D. for — no such usage.
E. among — used for more than two people/things.

Cetking shortcut: Angry/vexed/annoyed: WITH a person, AT a thing.

Answer: B

Approach: Double-blank prepositions — check both blanks.

Solution: Blank 1: 'the great powers' are more than two, so among (not 'between').
Blank 2: agreement on a subject → 'on a treaty'.
Sentence: 'There was no agreement among the great powers on a treaty to ban nuclear weapons.'

Why the other options are wrong:
A. in, for — 'agreement in the powers' is wrong.
B. between, about — 'between' is for two parties.
D. with, about — 'agreement with' needs a single other party.
E. by, of — both wrong usages.

Cetking shortcut: Eliminate on the first blank: more than two parties → only 'among' works.

Answer: C

Approach: One-word substitution — '-mania' = obsessive urge.

Solution: Klepto (Greek: steal) + mania (obsession) = Kleptomania, a morbid desire to steal.

Why the other options are wrong:
B. Prevaricate — to avoid telling the truth.
C. Peroration — the concluding part of a speech.
D. Stoic — a person who endures hardship without complaint.
E. Sycophant — a flatterer.

Answer: A

Approach: One-word substitution — use roots: philo = love, zo = animal.

Solution: Philo (love) + zoic (animals) = Philozoic, a lover of animals.

Why the other options are wrong:
A. Philomuse — a lover of the arts/learning.
C. Polyglot — a person who knows many languages.
D. Emissary — a messenger sent on a mission.
E. Zoophobia — fear of animals; opposite.

Cetking shortcut: Root splitting: philo (love) + zo (animal) — only B has both.

Answer: B

Approach: One-word substitution — '-logy' = study of; kalos = beauty.

Solution: Kalo (beautiful) + logy (study) = Kalology, the science of human beauty.

Why the other options are wrong:
A. Aetiology — study of causes (of disease).
B. Physiology — study of how the body functions.
D. Cosmography — mapping/description of the universe.
E. Etiology — another spelling of aetiology.

Cetking shortcut: A and E are the same word (aetiology/etiology), so both are out at once.

Answer: C

Approach: One-word substitution — animal adjectives from Latin.

Solution: Latin vulpes = fox → Vulpine = fox-like.

Why the other options are wrong:
A. Leonine — lion-like.
B. Porine — not a standard animal adjective (porcine = pig-like).
C. Canine — dog-like.
E. Ostler — a stableman who looks after horses at an inn.

Cetking shortcut: Learn the set: leonine (lion), canine (dog), feline (cat), bovine (cow), equine (horse), vulpine (fox), ursine (bear), porcine (pig).

Answer: D

Approach: One-word substitution — 'palaeo' = ancient.

Solution: Palaeo (ancient) + onto (being) + logy (study) = Palaeontology, the study of fossils.

Why the other options are wrong:
A. Nomology — study of laws.
B. Metallurgy — science of metals.
C. Metrology — science of measurement.
D. Numismatics — study of coins.

Answer: E

Approach: Error spotting — 'in' (rest) vs 'into' (motion inside).

Solution: The boatman threw the oar so that it moved from his hand inside the water — this is motion, so into is required.
Correct: 'The angry boatman threw the cracked oar into the river and returned home.'

Why the other options are wrong:
A. 'The angry boatman threw' — correct.
B. 'the cracked oar' — correct.
D. 'and returned home' — correct (home without 'to').
E. No error — wrong, (C) has the error.

Cetking shortcut: Verbs of movement (throw, jump, fall, walk) + 'inside' → into.

Answer: C

Approach: Error spotting — fixed preposition with 'admission'.

Solution: 'Admission' takes to: admission to a school/college/course.
Part (B) 'in the engineering college' should be 'to the engineering college'.
Correct: 'Parul was trying for admission to the engineering college even though her parents wanted her to take to medicine.'

Why the other options are wrong:
A. 'Parul was trying for admission' — correct.
C. 'even though her parents wanted' — correct.
D. 'her to take to medicine' — correct ('take to' = adopt as a career).
E. No error — wrong, (B) has the error.

Cetking shortcut: Admission to, entrance to/into, enrol in — memorise the noun–preposition pairs.

Answer: B

Approach: Error spotting — fixed idiom 'have a hand in'.

Solution: 'To have a hand in' = to be involved in. Part (B) drops the article: 'that he had hand in the murder' → 'that he had a hand in the murder'.
Correct: 'This fact makes it very clear that he had a hand in the murder, though he still pleads innocence.'

Why the other options are wrong:
A. 'This fact makes it very clear' — correct (singular subject, singular verb).
C. 'though he still' — correct.
D. 'pleads innocence' — correct (present, he still pleads now).
E. No error — wrong, (B) has the error.

Answer: B

Approach: Error spotting — 'Neither of + plural noun' takes a singular verb.

Solution: The subject is Neither (singular), not 'plans'. So 'suit' is wrong.
The sentence is in the past ('decided … yesterday'), so the verb should be suited.
Correct: 'Neither of the plans suited him and therefore he decided not to go out yesterday.'

Why the other options are wrong:
A. 'Neither of the plans' — correct.
C. 'he decided not to' — correct.
D. 'go out yesterday' — correct.
E. No error — wrong, (B) has the error.

Cetking shortcut: Either/Neither/Each/Every of + plural noun → singular verb.

Answer: B

Approach: Latin comparatives take 'to'.

Solution: Anterior (= earlier) is already a comparative of Latin origin. It is followed by to and never by 'than', 'more' or 'most'.
Correct: 'This event took place anterior to that.'

Why the other options are wrong:
B. more anterior — double comparative.
C. anterior than — Latin comparatives never take 'than'.
D. less anterior — wrong degree with a Latin comparative.
E. most anterior — wrong superlative form.

Cetking shortcut: Senior, junior, superior, inferior, prior, anterior, posterior → always '… to'.

Answer: A

Approach: Dangling modifier — the doer of 'sitting' must come right after the comma.

Solution: As written, the sentence implies the moon was sitting in the garden. The people sitting were 'we', so 'we' must be the subject, in active voice.
Correct: 'Sitting in the garden, we saw the moon shining in the sky.'

Why the other options are wrong:
A. Keeps 'the moon' as subject — still dangling; also drops 'shining'.
C. Misspells 'shining' and keeps the dangling subject.
D. Misspelt, incomplete ('by …') and still dangling.
E. No improvement — the original is a dangling modifier.

Cetking shortcut: With an opening '-ing' phrase, the answer almost always starts with the human doer (we/he/she).

Answer: B

Approach: Sequence of tenses — past main verb → past form in the subordinate clause.

Solution: Main clause: 'The contractor did not keep his promise' (past). The promise clause must shift back: 'will' → would.
Correct: '… his promise that the work would be finished before the end of the week.'

Why the other options are wrong:
A. could — changes the meaning to ability, not a promise.
B. shall — present/future form; breaks sequence of tenses.
D. was — 'was be finished' is ungrammatical.
E. No improvement — 'will' is wrong after a past main verb.

Answer: C

Approach: Order of adjectives — opinion/condition → size → age → shape → colour → origin → material → purpose → noun.

Solution: 'Broken' describes condition (quality); 'wooden' is material. Material sits closest to the noun.
Correct: 'The principal was angry on seeing a broken wooden chair lying in the corridor.'

Why the other options are wrong:
B. 'Wooden and broken chair' — wrong order and an unnecessary 'and'.
C. 'Broken and wooden chair' — 'and' is not used between adjectives of different categories.
D. 'Broken chair wooden' — adjective after the noun; wrong.
E. No improvement — 'wooden broken' is the wrong order.

Cetking shortcut: Material adjective (wooden, golden, silk) always sits right next to the noun.

Answer: A

Approach: Pronoun–antecedent agreement and consistency of person.

Solution: The antecedent is Anyone — third person, singular. 'You' (second person) is wrong, and the verb must be singular.
Correct: 'Anyone interested in the use of computers can learn much if he or she has access to a personal computer.'

Why the other options are wrong:
A. 'one of them have access' — 'one … have' is wrong agreement; 'them' has no antecedent.
B. 'they have access' — plural; formal grammar keeps 'anyone' singular.
C. 'access can be available' — awkward passive; loses the person.
E. No improvement — 'you' does not match 'anyone'.

Answer: D

Approach: Faulty comparison — compare the same kind of things.

Solution: 'His movements' (plural thing) are being compared with 'a young man' (person) — illogical.
Use the plural pronoun those to stand for 'movements': '… as spirited as those of a young man.'

Why the other options are wrong:
A. 'a young man's' — elliptical and singular in form; 'those of' is the exact, plural match for 'movements'.
B. 'if a young man' — meaningless here.
C. 'of a young man' — still lacks the noun being compared.
E. No improvement — compares movements with a man.

Cetking shortcut: Plural noun compared → 'those of'; singular → 'that of'.

Answer: D

Approach: Idiom meaning.

Solution: Bone of contention = the cause of a quarrel or disagreement (like a bone that two dogs fight over).

Why the other options are wrong:
B. Reason for connection — the opposite idea.
C. Reason for a relationship — unrelated.
D. Reason for a friendship — opposite.
E. Reason of duty — unrelated.

Cetking shortcut: 'Contention' = dispute; only A has a quarrel.

Answer: A

Approach: Idiom meaning.

Solution: Forty winks = a short sleep or nap, usually in the daytime — the same as a siesta (short afternoon rest).

Why the other options are wrong:
A. A long sleep — opposite; forty winks is short.
C. Disquiet — anxiety.
D. Toil — hard work.
E. Bustle — busy activity.

Answer: B

Approach: Idiom meaning.

Solution: Knit one's brow = draw the eyebrows together, i.e. frown — a sign of displeasure or anger. Among the options, 'to get angry' fits.

Why the other options are wrong:
A. To be happy — a frown is not happiness.
B. To enjoy — opposite.
D. To get hungry — unrelated.
E. To get thirsty — unrelated.

Answer: C

Approach: Idiom meaning.

Solution: At daggers drawn (with) = bitterly hostile, ready to fight — i.e. enmity.

Why the other options are wrong:
A. To be friends — opposite.
B. On good terms — opposite.
C. Compatible — opposite.
E. In accordance — means in agreement.

Cetking shortcut: Four options mean 'friendly/agreeing' — the lone hostile one is the answer.

Answer: D

Approach: Pronoun agreement — 'one' takes 'one's'.

Solution: In formal English, the pronoun one is followed by the same pronoun: 'One should love one's country.'

Why the other options are wrong:
A. once — an adverb (one time).
B. ones — plural noun; the possessive needs an apostrophe.
C. their — plural; does not match 'one'.
D. his — used in older texts, but the standard exam answer keeps 'one … one's'.

Answer: E

Approach: RC main idea — the topic sentence states the chief appeal.

Solution: Sentence 1: CDs revolutionised the industry 'with their surprisingly realistic sound'; the passage adds that the sound has none of the crackling of vinyl. Sound is the main appeal.

Why the other options are wrong:
A. Size — mentioned as an extra advantage (lighter, smaller).
B. Price — the passage says CDs are less affordable than cassettes.
D. Availability — a later development, not the main appeal.
E. Shape — only described, not presented as an appeal.

Answer: C

Approach: Vocabulary in context — replace the word and check the sentence.

Solution: 'CDs have revolutionized the music industry' = CDs have changed it radically. Substituting 'changed' keeps the meaning.

Why the other options are wrong:
A. Marked — to note or label; no idea of change.
B. Surprised — an emotion; does not fit an industry.
C. Taught — unrelated.
E. Raised — to lift; not the meaning.

Answer: D

Approach: RC — explain the comparison (analogy) the author uses.

Solution: 'The six-inch discs look like plastic sandwiches with aluminum at the centre' — plastic on both sides with aluminium in the middle, just like the layers of a sandwich. So: they are layered.

Why the other options are wrong:
A. They are small — size is not what a sandwich suggests.
B. They are light — weight is mentioned separately.
C. They don't crackle — about sound, not appearance.
E. They are circular — sandwiches are not circular.

Cetking shortcut: Ask: what does a sandwich have that the CD also has? → layers with a filling.

Answer: D

Approach: Fixed preposition with 'die'.

Solution: Die of = disease, hunger, grief, old age (internal cause).
Die from = wound, overwork, injury (external cause).
Grief is an internal emotion → 'He died of grief.'

Why the other options are wrong:
A. from — for external causes (died from a wound).
B. by — for violent means (died by the sword).
D. with — no such usage.
E. in — for a place/event (died in a battle).

Cetking shortcut: Die of illness/emotion, from injury/overwork, by violence, in an accident/battle.

Answer: C

Approach: Young ones of animals/insects.

Solution: A housefly lays eggs that hatch into soft, legless larvae called maggots.

Why the other options are wrong:
A. Fawn — young deer.
B. Owlet — young owl.
D. Cygnet — young swan.
E. Nymph — young of insects like grasshoppers, cockroaches, dragonflies.

Answer: C

Approach: RC specific detail — match the paraphrase.

Solution: Last sentence: without a broad general education, experts will be 'too narrow in their outlook'. So broad general education contributes to a broader outlook.

Why the other options are wrong:
A. Without it no one would get a job — not stated.
C. Teaches about similar things — not stated; it teaches a wide range.
D. Specialisation is incomplete without it — overstatement; not said.
E. Concentrates on a narrow range — describes the opposite theory.

Cetking shortcut: 'Too narrow in outlook without X' ⇒ 'X broadens outlook' — a direct flip.

Answer: B

Approach: RC specific detail — locate the phrase in the passage.

Solution: 'Unless they have a broad general education, the experts will be too narrow in their outlook to have sympathy with their fellows or a proper sense of responsibility towards humanity as a whole.'

Why the other options are wrong:
A. Narrow outlook — this is what prevents sympathy.
B. Only expertise — the passage says expertise alone is not enough.
C. Narrow range of subjects — the first theory, which leads to narrow outlook.
E. Focus on their profession — again the first theory.

Answer: D

Approach: RC specific detail — paraphrase of the first theory's claim.

Solution: 'Supporters of the first theory state that the greatest contributions to civilisation are made by those who are most expert in their trade or profession.' Option B says the same: experts have contributed most to progress.

Why the other options are wrong:
A. Experts have done nothing to help mankind — opposite.
C. People with general knowledge are more useful than experts — the view of the other side, not the first theory.
D. People with general knowledge have contributed to civilisation — not their claim.
E. People with general knowledge have not contributed — an extreme inference; they only say experts contributed most.

Answer: B

Approach: Fixed preposition with the verb 'profit'.

Solution: 'Profit from something' = gain benefit from it. 'The leaders hoped that the two countries could profit from each other's experience.'

Why the other options are wrong:
B. by — 'profit by' is older usage, mostly with an action; 'profit from experience' is the standard collocation.
C. with — no such usage.
D. through — not idiomatic with 'profit'.
E. of — no such usage.

Answer: A

Approach: Tense — a definite past time marker takes the simple past.

Solution: 'Last night' is a finished past time, and the second clause 'so we stayed at home' is simple past. So the first verb is also simple past: 'It was too cold to go out last night.'

Why the other options are wrong:
A. had been — past perfect needs an earlier past action; not the case here.
B. has been — present perfect cannot go with 'last night'.
D. used to be — a past habit, not a single night.
E. is — present tense; clashes with 'last night'.

Cetking shortcut: Time marker 'last night/yesterday/ago' → simple past; never present perfect.

Answer: C

Approach: Second-order differences (differences form the triangular numbers).

Solution:
Differences: 6−5 = 1, 9−6 = 3, 15−9 = 6.
1, 3, 6 are triangular numbers (+2, +3, ...), so the next differences are 10 and 15.
Missing term = 15 + 10 = 25.
Check: 25 + 15 = 40 ✓

Why the other options are wrong:
A (21), C (27), D (33), E (48): none gives a difference pattern that also lands on 40.

Cetking shortcut: When the last term is given, test each option: only 25 makes both gaps (10 and 15) fit the 1, 3, 6, 10, 15 chain.

Answer: B

Approach: Tribonacci rule: each term = sum of the previous three terms.

Solution:
1 + 3 + 4 = 8
3 + 4 + 8 = 15
4 + 8 + 15 = 27
Next = 8 + 15 + 27 = 50

Why the other options are wrong:
A 37, B 44, D 55, E 95: none equals 8 + 15 + 27.

Cetking shortcut: When differences (2, 1, 4, 7, 12) look irregular and terms roughly double, try sum of previous two/three terms.

Answer: C

Approach: Letter groups grow by one letter; starting positions jump by +2, +4, +6, +8.

Solution:
Group sizes: 1, 2, 3, ?, 5 → the missing group has 4 letters.
Starting letters: A(1), C(3), G(7), ?, U(21).
Jumps: +2, +4, so next +6 → 13 = M, then 13 + 8 = 21 = U ✓
Missing group = MNOP.
Equivalently, letters skipped between groups: B (1), EF (2), JKL (3), QRST (4).

Why the other options are wrong:
A LMNO: starts at L (12), breaks the +6 jump.
B MNO: only 3 letters.
D NOPQ: starts at N (14).
E OPQZ: not consecutive letters.

Cetking shortcut: Count skipped letters: 1, 2, 3, 4 — after GHI skip JKL, so the group starts at M.

Answer: C

Approach: Three independent series inside each term: first number, letter, last number.

Solution:
First numbers: 2, 7, 14, 23, 34 → differences 5, 7, 9, 11 → next +13 = 47.
Letters: Z, Y, X, W, V → next U.
Last numbers: 5, 7, 9, 11, 13 → next 15.
Missing term = 47U15.

Why the other options are wrong:
A 27U24 and B 45U15: wrong first number.
D 47V14: letter should move to U and last number to 15.
E 23X7: repeats earlier parts.

Cetking shortcut: Check the easiest part first: the letter must be U and the last number 15 — only B and C survive; then 34 + 13 = 47 picks C.

Answer: C

Approach: Wrong-term series: consecutive perfect squares.

Solution:
196 = 14², 169 = 13², 144 = 12², 121 = 11², so the last term must be 10² = 100.
101 breaks the pattern → 101 is wrong.

Why the other options are wrong:
B, C, D, E: 121, 169, 196, 144 are all perfect squares in sequence.

Cetking shortcut: Numbers near 100, 121, 144... — test perfect squares first.

Answer: A

Approach: Letter analogy by positional shifts.

Solution:
CRED → PSQR: C(3)→P(16) = +13, R(18)→S(19) = +1, E(5)→Q(17) = +12, D(4)→R(18) = +14.
Apply to JMKL: J(10)+13 = W(23), K(11)+12 = W(23), L(12)+14 = Z(26).
So the answer has the form W _ W Z (the same rule would give N as the 2nd letter, M+1, which no option shows).
Only option D (WZWZ) has W in the 1st and 3rd places and Z in the 4th.

Why the other options are wrong:
A YXZW, B YVZX: start with Y, not W.
C UVXZ: starts with U.
E RQSP: starts with R.

Cetking shortcut: Check just the first letter: J + 13 = W. Only option D starts with W.

Answer: D

Approach: Letter analogy: each pair of positions adds up to 28.

Solution:
EGIK → WUSQ: E(5)+W(23) = 28, G(7)+U(21) = 28, I(9)+S(19) = 28, K(11)+Q(17) = 28.
So each letter → (28 − position).
DFHJ: D(4) → 24 = X, F(6) → 22 = V, H(8) → 20 = T, J(10) → 18 = R.
Answer = XVTR.

Why the other options are wrong:
A BDFH, B ECGI: move backward by small steps, not the 28-sum rule.
D SQOM: sums are 23, not 28.
E QSUV: wrong direction and spacing.

Cetking shortcut: Both words are alternate-letter runs (gap 2), so the answer must be a reverse alternate run starting one step after W: X, V, T, R.

Answer: C

Approach: Letter analogy: every letter moves +1, case preserved.

Solution:
acE → bdF: a→b, c→d, E→F (each +1).
fhJ → f+1 = g, h+1 = i, J+1 = K → giK.

Why the other options are wrong:
A jbf: not a +1 shift.
B ghK: second letter should be i (h + 1), not h.
D dfH: shifts backward.
E fhL: first two letters unchanged.

Cetking shortcut: The given terms are alternate letters (a, c, E / f, h, J); after +1 they stay alternate — only giK keeps the g_i spacing.

Answer: C

Approach: Number analogy: square the number and add 2.

Solution:
3 → 3² + 2 = 9 + 2 = 11 ✓
7 → 7² + 2 = 49 + 2 = 51

Why the other options are wrong:
A 22, B 29, C 18, E 13: none equals 7² + 2; linear rules (×3+2 = 23, ×4−1 = 27) do not match any option either.

Cetking shortcut: 11 is just above 9 = 3² — check n² + k first; 49 + 2 = 51 is in the options.

Answer: D

Approach: Number analogy: square root plus 1.

Solution:
121 → √121 = 11 → 11 + 1 = 12 ✓
25 → √25 = 5 → 5 + 1 = 6

Why the other options are wrong:
A 1, B 2: no root-based rule gives these.
D 7: √25 + 2.
E 5: just the square root, missing the +1.

Answer: C

Approach: Venn diagram: find the region common to all four shapes.

Solution:
Rectangle = wheat, square = gram, circle = maize, triangle = rice. Read each numbered region by asking: inside which shapes is it?
Region 7 lies inside the rectangle, the square, the circle and the triangle at the same time.
So all four crops are grown in region 7.

Why the other options are wrong:
B 8: inside rectangle, circle, triangle but above the square — gram missing.
C 9: inside square, circle, triangle but right of the rectangle — wheat missing.
D 2: circle and triangle only.
E 1: triangle only.

Cetking shortcut: The all-shape region is always the innermost cell where the most boundaries cross — here the small cell 7.

Answer: A

Approach: Venn diagram: region inside exactly two named shapes.

Solution:
Rectangle = wheat, square = gram, circle = maize, triangle = rice. Read each numbered region by asking: inside which shapes is it?
Wheat and maize only = inside rectangle and circle, outside square and triangle.
Region 4 is in the rectangle and circle, above the square and left of the triangle → 4.

Why the other options are wrong:
A 8: also inside the triangle (rice).
B 6: also inside the square (gram).
C 5: rectangle only.
E 3: circle only.

Answer: D

Approach: Venn diagram: region inside one shape only.

Solution:
Rectangle = wheat, square = gram, circle = maize, triangle = rice. Read each numbered region by asking: inside which shapes is it?
Rice only = inside the triangle and outside rectangle, square and circle.
Region 1 (the tip of the triangle outside the circle) → 1.

Why the other options are wrong:
A 5: rectangle only (wheat).
C 2: triangle and circle.
D 11: square only (gram).
E 7: all four.

Answer: B

Approach: Venn diagram: region inside one shape only.

Solution:
Rectangle = wheat, square = gram, circle = maize, triangle = rice. Read each numbered region by asking: inside which shapes is it?
Maize only = inside the circle, outside rectangle, square and triangle.
Region 3 (top of the circle) → 3.

Why the other options are wrong:
A 10: also inside the square (gram).
B 2: circle and triangle.
D 4: circle and rectangle.
E 11: square only.

Answer: C

Approach: Odd one out: number equals the alphabet position of the letter.

Solution:
18R: R = 18 ✓
24X: X = 24 ✓
22V: V = 22 ✓
16P: P = 16 ✓
12M: M = 13 ✗ → 12M is different.

Cetking shortcut: Memorise EJOTY = 5, 10, 15, 20, 25: M is just before O(15) and after J(10) → 13.

Answer: D

Approach: Coding: each letter is replaced by the letter whose position = 26 − original position.

Solution:
DIAMOND → VQYMKLV: D(4)→V(22), I(9)→Q(17), A(1)→Y(25), M(13)→M(13), O(15)→K(11), N(14)→L(12) — every pair sums to 26.
FEMALE: F(6)→20 = T, E(5)→21 = U, M(13)→13 = M, A(1)→25 = Y, L(12)→14 = N, E(5)→21 = U.
FEMALE = TUMYNU.

Why the other options are wrong:
B UVNZOV, C UVNYNV: start with U, but F → T.
D TVNYNV: E must become U, not V.
E TUMZOU: A must become Y, not Z.

Cetking shortcut: M stays M (13 + 13 = 26) — only options with M in 3rd place (A, E) survive; A → Y picks A.

Answer: A

Approach: Coding: alternate −1, +1 shifts; decode by reversing them.

Solution:
MACHINE → LBBIHOD: M−1 = L, A+1 = B, C−1 = B, H+1 = I, I−1 = H, N+1 = O, E−1 = D.
To decode SLTMFNB apply +1, −1, +1, −1, +1, −1, +1:
S→T, L→K, T→U, M→L, F→G, N→M, B→C → TKULGMC.
Check: T−1 = S, K+1 = L, U−1 = T ... ✓

Why the other options are wrong:
A RKSLEMA: applies −1 everywhere.
C RMSNEOA, D TMUNGOC, E TMUNGMC: wrong direction on one or more letters.

Cetking shortcut: First letter: S came from T (code subtracts 1 at odd places) — only B, D, E start with T; second letter L came from K — only B.

Answer: B

Approach: Direct letter-to-digit substitution code.

Solution:
EAT = 318 → E = 3, A = 1, T = 8.
CHAIR = 24156 → C = 2, H = 4, A = 1, I = 5, R = 6.
TEACHER = T E A C H E R = 8 3 1 2 4 3 6 = 8312436.

Why the other options are wrong:
A 8312346: H and E swapped.
B 8321436: A and C swapped.
D 8313426: C coded as 3.
E 8313134: wrong from the 4th digit.

Cetking shortcut: The first four digits 8312 (TEAC) already remove B, D, E; the 5th digit H = 4 picks C.

Answer: C

Approach: Substitution coding: answer with the code name of the real answer.

Solution:
In a restaurant, the person who serves is the butler (server).
In this language, 'butler' is called 'rogue'.
So the answer is Rogue.

Why the other options are wrong:
A Butler: the real word, not its code name.
B Girl, C Man, D Women: code names of other words.

Cetking shortcut: Find the real answer first, then replace it with its code word.

Answer: E

Approach: Substitution coding: answer with the code name of the real answer.

Solution:
A clear sky is blue.
In this language, 'blue' is called 'sky'.
So the colour of a clear sky is Sky.

Why the other options are wrong:
A Blue: the real word, not its code.
C Yellow: code for 'sky'.
D Water: code for 'yellow'.
E Pink: code for 'water'.

Cetking shortcut: Find the real answer (blue) and read its code name (sky).

Answer: B

Approach: Blood relations: draw the three-generation family tree.

Solution:
A is the son of C; E is the daughter of A → A is E's father.
F is the mother of E (and of D) → A and F are a couple.
Tree: C (and spouse B) → son A. A is married to F (F is the mother of E, A is E's father). A and F → daughters E and D.
The 'one couple with parents and children' is A–F: parents B, C above; children E, D below.
Parents of the children (E, D) = A and F.

Why the other options are wrong:
A BC: parents of A (the couple), not of the children.
B CF, C BF, D CD: mix members of different generations.

Answer: E

Approach: Blood relations: identify the top-generation pair.

Solution:
Tree: C (and spouse B) → son A. A is married to F (F is the mother of E, A is E's father). A and F → daughters E and D.
The 'one couple with parents and children' is A–F: parents B, C above; children E, D below.
Six members: A, F (couple), E, D (children), C (A's parent) and B — the only member left, who must be C's spouse.
Parents of the couple (A–F) = B and C.

Why the other options are wrong:
A AB, C AF, D CF, E DE: each includes someone from the middle or bottom generation.

Cetking shortcut: Six people, three generations: once A–F and E, D are fixed, B and C are the only pair left for the top.

Answer: B

Approach: Blood relations: fix genders from the tree.

Solution:
Tree: C (and spouse B) → son A. A is married to F (F is the mother of E, A is E's father). A and F → daughters E and D.
The 'one couple with parents and children' is A–F: parents B, C above; children E, D below.
Female: F (mother), E and D (daughters).
Male: A (son).
B and C are a married couple → exactly one of them is female.
Females = F, E, D + one of B/C = 4.

Why the other options are wrong:
A Two, B Three: miss the female among B and C or one daughter.
D Five, E Six: A is male and one of B/C is male.

Cetking shortcut: A couple always contributes exactly one female — no need to know which of B, C is the mother.

Answer: C

Approach: Blood relations: decode the chain from the end.

Solution:
Anil's father's wife = Anil's mother.
Only brother of Anil's mother = Anil's maternal uncle.
Son of Anil's maternal uncle = Anil's cousin.

Why the other options are wrong:
B Son, D Son-in-law: Rohit is in Anil's generation, not the next.
C Uncle, E Grandfather: older generations.

Cetking shortcut: 'Father's wife' is simply 'mother' — replace and the chain becomes mother's brother's son = cousin.

Answer: A

Approach: Blood relations: two generations down.

Solution:
Deepak and Anil are brothers → both are sons of Prem.
Bimal is Prem's father.
So Anil is the son's son of Bimal → grandson.

Why the other options are wrong:
A Son: that is Prem.
C Brother, E Uncle: wrong generation.
D Grandfather: reversed relation.

Answer: B

Approach: Selection with together / not-together rules: test each option.

Solution:
Rules: (1) A and S together, (2) P not with R, (3) D not with Q, (4) C and E together, (5) R not with B.
2 boys → 3 girls in a team of 5.
Option A: A, B, S, P, Q — boys A, B; girls S, P, Q.
A with S ✓; P without R ✓; D absent ✓; C and E both absent ✓; R absent ✓ → valid.

Why the other options are wrong:
B A, D, S, Q, R: D with Q breaks rule 3.
C B, D, S, R, Q: S without A, D with Q, R with B.
D C, E, S, P, Q: S without A.
E R, B, S, P, Q: 4 girls, and R with B.

Cetking shortcut: With only 2 boys, a pair rule (A–S or C–E) uses one boy; S is in every option, so A must be there — only options A and B (which contain A) survive, and option B fails D–Q.

Answer: A

Approach: Selection rules: with R in the team, apply the R-related bans first.

Solution:
Rules: (1) A and S together, (2) P not with R, (3) D not with Q, (4) C and E together, (5) R not with B.
R is in → P out (rule 2), B out (rule 5).
Option D: R + S, A, C, E → A–S together ✓, C–E together ✓, no P, B, D, Q issues ✓ → valid.

Why the other options are wrong:
A P, S, A, D: P with R.
B Q, S, A, D: D with Q.
C Q, S, C, E: S without A.
E Q, S, R, D: repeats R, S without A, D with Q.

Cetking shortcut: R bans P and B — strike every option with P; then the pair rules leave only D.

Answer: D

Approach: Selection rules: D in the team, 2 girls (so 3 boys including D).

Solution:
Rules: (1) A and S together, (2) P not with R, (3) D not with Q, (4) C and E together, (5) R not with B.
D is in → Q out (rule 3). Girls must come from P, R, S, and P–R cannot be together.
If S is chosen, A must come too. Try girls P, S: team D, A, P, S + one more boy. C or E alone breaks rule 4 → the 5th is B.
Team: D, A, B, P, S — R absent so rule 5 ✓.
Girls R, S: needs A and one more boy who is not B (rule 5) and not C/E alone — impossible.
So the others are P, S, A, B.

Why the other options are wrong:
A P, Q, B, C: Q with D; C without E.
B P, Q, C, E: Q with D.
D P, S, C, E: S is in without A (rule 1).
E P, Q, B, D: Q with D, and D repeated.

Cetking shortcut: D knocks out Q at once — this removes options A, B and E; in option D, S is present without A, so only option C works.

Answer: C

Approach: Selection rules: A and C force their partners S and E.

Solution:
Rules: (1) A and S together, (2) P not with R, (3) D not with Q, (4) C and E together, (5) R not with B.
A in → S must be in. C in → E must be in.
So the team is A, C, S, E + one more; the 'other members' must include both S and E.
Option D (P, Q, E) has no S → A would be without S → cannot be the team.

Why the other options are wrong:
A B, E, S → A, C, B, E, S: all rules ✓.
B D, E, S → A, C, D, E, S: all rules ✓.
C E, S, P → A, C, E, S, P: all rules ✓.
E P, Q, B: also leaves out S and E, so it fails as well; the keyed answer is D.

Cetking shortcut: Any valid 'other three' must contain both S and E — reject options missing either.

Answer: D

Approach: Linear arrangement of 5 with Monika fixed in the middle.

Solution:
Monika = position 3. Rashi is next to Monika → position 2 or 4.
Rashi is not next to Surekha or Abha, and Monika is on her other side, so her outer neighbour (1 or 5) must be Anuradha.
Case Rashi at 4: Anuradha at 5; Surekha and Abha at 1, 2. Anuradha is not next to Surekha ✓.
(Rashi at 2 is the mirror image.)
Anuradha's only neighbour = Rashi.

Why the other options are wrong:
B Surekha: banned next to Anuradha.
C Abha, E Surekha or Abha: they sit on the far side of Monika.
D Monika: Rashi sits between Monika and Anuradha.

Cetking shortcut: Rashi's outer neighbour cannot be Surekha or Abha → it is Anuradha; no full arrangement needed.

Answer: A

Approach: Two ranking lists linked by 'replaces' clues; build both lists together.

Solution:
Runs (ascending, 1 = least): N = 1st, O = 4th. L is 1st in one list and 5th in the other; 1st is taken by N, so L = 5th in runs (most runs) and 1st in wickets.
M keeps the same rank in both lists; K scored more runs than M → M = 2nd, K = 3rd in runs.
Runs ascending: N, M, K, O, L.
Wickets descending: K takes O's place (4th), O takes L's place (5th), L = 1st, M = 2nd (unchanged), N = 3rd.
Wickets descending: L, M, N, K, O.
Highest runs = 5th in ascending order = L.

Why the other options are wrong:
A K: 3rd in runs.
C M: 2nd in runs.
D N: lowest runs.
E O: 4th in runs.

Cetking shortcut: '1st in one list, 5th in the other' with N already 1st in runs fixes L = 5th in runs immediately.

Answer: B

Approach: Two ranking lists: read the bottom of the wickets list.

Solution:
Runs (ascending, 1 = least): N = 1st, O = 4th. L is 1st in one list and 5th in the other; 1st is taken by N, so L = 5th in runs (most runs) and 1st in wickets.
M keeps the same rank in both lists; K scored more runs than M → M = 2nd, K = 3rd in runs.
Runs ascending: N, M, K, O, L.
Wickets descending: K takes O's place (4th), O takes L's place (5th), L = 1st, M = 2nd (unchanged), N = 3rd.
Wickets descending: L, M, N, K, O.
Lowest wickets = 5th in descending order = O (O takes L's runs rank, 5th).

Why the other options are wrong:
A L: highest wickets.
B M: 2nd.
C N: 3rd.
D K: 4th.

Cetking shortcut: 'O replaces L' puts O at L's runs rank — 5th — so O is last in wickets.

Answer: E

Approach: Two ranking lists: read the top of the wickets list.

Solution:
Runs (ascending, 1 = least): N = 1st, O = 4th. L is 1st in one list and 5th in the other; 1st is taken by N, so L = 5th in runs (most runs) and 1st in wickets.
M keeps the same rank in both lists; K scored more runs than M → M = 2nd, K = 3rd in runs.
Runs ascending: N, M, K, O, L.
Wickets descending: K takes O's place (4th), O takes L's place (5th), L = 1st, M = 2nd (unchanged), N = 3rd.
Wickets descending: L, M, N, K, O.
Highest wickets = 1st in descending order = L.

Why the other options are wrong:
B M: 2nd.
C N: 3rd.
D K: 4th (took O's 4th rank).
E O: last.

Answer: A

Approach: Odd one out: letter-gap pattern within each group.

Solution:
DAH: D(4)→A(1) = −3, A→H(8) = +7
IFM: −3, +7
ROV: −3, +7
SPW: −3, +7
QNT: Q(17)→N(14) = −3, N→T(20) = +6 → odd one out.

Cetking shortcut: All start with −3; only check the second gap — QNT is the one that falls short by one.

Answer: D

Approach: Odd one out: divisibility.

Solution:
6 = 3×2, 12 = 3×4, 18 = 3×6, 9 = 3×3 — all multiples of 3.
7 is not a multiple of 3 → odd one out.

Why the other options are wrong:
A 6, B 12, C 18, D 9: all multiples of 3. (Even/odd splits 3 vs 2, so it cannot single out one number.)

Cetking shortcut: Look for a property shared by exactly four numbers; even/odd splits 3–2 and is rejected.

Answer: E

Approach: Matrix puzzle: fill writer × century × branch × language from fixed clues.

Solution:
A = 20th century → the 20th-century writer is Marathi, poetry only. C is the other Marathi writer → poetry, novel, drama.
D = Hindi, poetry + novel, 19th.
Poets (4): A, C, D + one more. F writes poetry only, so F is the 4th poet; the Bengali writer writes poetry only → F = Bengali, 17th.
Left: B and E, languages Hindi (2nd) and Tamil. Tamil writer does novel + drama; B does drama only → B = Hindi, E = Tamil (19th, novel + drama).
Check: novelists C, D, E (3) ✓; dramatists B, C, E (3) ✓.

Why the other options are wrong:
A Bengali: F.
C Marathi: A and C.
D Tamil: E (novel + drama, but B is drama only).
E English: no English writer in the set.

Cetking shortcut: B 'drama only' cannot be the Tamil writer (novel + drama), and Bengali/Marathi are taken — Hindi by elimination.

Answer: B

Approach: Matrix puzzle: read the Tamil row.

Solution:
A = 20th century → the 20th-century writer is Marathi, poetry only. C is the other Marathi writer → poetry, novel, drama.
D = Hindi, poetry + novel, 19th.
Poets (4): A, C, D + one more. F writes poetry only, so F is the 4th poet; the Bengali writer writes poetry only → F = Bengali, 17th.
Left: B and E, languages Hindi (2nd) and Tamil. Tamil writer does novel + drama; B does drama only → B = Hindi, E = Tamil (19th, novel + drama).
Check: novelists C, D, E (3) ✓; dramatists B, C, E (3) ✓.

Why the other options are wrong:
A A: Marathi.
B B: Hindi (drama only).
D F: Bengali.
E D: Hindi.

Answer: C

Approach: Matrix puzzle: direct clue on the 20th-century writer.

Solution:
A belongs to the 20th century, and the 20th-century writer wrote poetry only (Marathi).
A contributed to Poetry.

Why the other options are wrong:
B Novel, C Drama, D Drama and Novel, E Drama and Poetry: A wrote poetry only.

Cetking shortcut: Direct read — no grid needed: A = 20th century = poetry only.

Answer: A

Approach: Matrix puzzle: identify the Bengali writer.

Solution:
The Bengali writer wrote poetry only. The poetry-only writers are A (Marathi, 20th) and F.
So the Bengali writer is F.

Why the other options are wrong:
A A: Marathi.
B B: Hindi.
C E: Tamil.
E D: Hindi.

Cetking shortcut: Two 'poetry only' people: A is Marathi, so the other one (F) is Bengali.

Answer: D

Approach: Linear arrangement of 5 with an extreme-end anchor.

Solution:
R is at the extreme left (1); K is next to R → K = 2.
T is not next to K → T is not 3, so T = 4 or 5.
If T = 4, S and P take 3 and 5 — not adjacent ✗.
So T = 5; S is not next to T → S = 3, P = 4.
Row: R, K, S, P, T → S sits between K and P.

Why the other options are wrong:
B R and P: R is at position 1.
C Only P: K is also next to S.
D P and T: S cannot be next to T.
E R and K: R is not next to S.

Answer: A

Approach: Direction sense: track coordinates (East = +x, North = +y).

Solution:
Start (0, 0).
20 m North → (0, 20).
Right = East, 30 m → (30, 20).
Right = South, 35 m → (30, −15).
Left = East, 15 m → (45, −15).
Left = North, 15 m → (45, 0).
He is 45 m East of the start.

Why the other options are wrong:
A 15 m West, C 30 m West, E 45 m West: he only ever moves East horizontally.
B 30 m East: forgets the second 15 m eastward leg.

Cetking shortcut: North moves: +20 −35 +15 = 0; East moves: 30 + 15 = 45 → straight East 45 m.

Answer: D

Approach: Direction sense: net displacement and Pythagoras.

Solution:
Start (0, 0). 90 m East → (90, 0).
Right = South, 20 m → (90, −20).
Right = West, 30 m → (60, −20) (uncle's place).
100 m North → (60, 80).
Distance = √(60² + 80²) = √(3600 + 6400) = √10000 = 100 m.

Why the other options are wrong:
A 80 m: only the north–south part.
C 140 m: adds 60 + 80.
D 260 m: total path walked.
E 90 m: only the first leg.

Cetking shortcut: 60 and 80 form a 3-4-5 triple (×20) → 100 directly.

Answer: B

Approach: Circular arrangement mapped on the 8 compass points.

Solution:
8 people at equal distances = 8 compass points, 45° apart, clockwise order P, Q, R, S, T, U, V, W.
V = North; moving clockwise: W = NE, P = E, Q = SE, R = S, S = South-West, T = W, U = NW.

Why the other options are wrong:
A East: P.
B South-East: Q.
C South: R.
E North: V.

Cetking shortcut: S is 5 places clockwise after V (or 3 places anticlockwise): N → NW → W → SW.

Answer: D

Approach: Direction sense on a square table: partners sit opposite and face each other.

Solution:
R faces West → R sits on the East side.
R's right hand points North → S sits on the North side, facing South.
Q is S's partner → Q sits opposite S, on the South side, facing North.
(P sits on the West side facing East.)

Why the other options are wrong:
B South: that is the direction S faces.
C East: P's facing direction.
D West: R's facing direction.
E South-West: no player faces a diagonal.

Cetking shortcut: Partners always face opposite directions: S faces South, so Q faces North.

Answer: A

Approach: Direction sense with coordinates: T lies on line QP extended.

Solution:
Put P at (0, 0). Q is South-West → Q = (−1, −1).
R is East of Q and South-East of P → R = (1, −1).
T is North of R and on the line Q–P (the line y = x) → T = (1, 1).
(1, 1) from P(0, 0) is North-East.

Why the other options are wrong:
A South-East: that is R.
B North: T has an East component.
D East: T is above P's level.
E West: T is on the right of P.

Cetking shortcut: Line Q→P runs towards NE; extending it past P keeps going NE — T must be NE of P.

Answer: C

Approach: Grouping into two cars: build the forced car first.

Solution:
Rules: car size 4–5; A with D, H not with A/D; B and C not with D; F rides in the car of four with A and E, not with G.
Car 1 (four people) = F, A, E + D (A must be with D) → A, D, E, F.
Car 2 = remaining B, C, G, H (H, B, C cannot be with D; G cannot be with F) ✓
H and G are in car 2, so the other two students there are B and C.

Why the other options are wrong:
B C and D, C B and D: D is in car 1 with A.
D E and B: E is in car 1.
E F and A: car 1.

Cetking shortcut: Car of four = F, A, E + A's partner D. Everyone else is in the other car.

Answer: A

Approach: Grouping into two cars: check statements about A and E's car.

Solution:
Rules: car size 4–5; A with D, H not with A/D; B and C not with D; F rides in the car of four with A and E, not with G.
Car 1 (four people) = F, A, E + D (A must be with D) → A, D, E, F.
Car 2 = remaining B, C, G, H (H, B, C cannot be with D; G cannot be with F) ✓
A and E are in car 1 = A, D, E, F.
A. 5 students — false (4).
B. B in the same car — false (car 2).
C. F not in the same car — false (F is there).
D. G not in the same car — true (G is in car 2).
E. H in the same car — false (car 2).

Cetking shortcut: F refuses G, so G is never with A, E, F.

Answer: D

Approach: Convert the statements into equations and compare.

Solution:
Given: (1) A + B > C + D, (2) A + C = B + D, (3) A = ½(B + D).
From (3): B + D = 2A. Put in (2): A + C = 2A → C = A.
Put C = A in (1): A + B > A + D → B > D.
Since B + D = 2A and B > D: B > A > D.
Order: B > A = C > D.
Highest income = B.

Why the other options are wrong:
A A, C C, E A or C: A = C, and both are below B.
D D: lowest.

Cetking shortcut: A is the average of B and D, so A lies between them; A = C, and B > D puts B on top.

Answer: B

Approach: Use the derived order to test each statement.

Solution:
Given: (1) A + B > C + D, (2) A + C = B + D, (3) A = ½(B + D).
From (3): B + D = 2A. Put in (2): A + C = 2A → C = A.
Put C = A in (1): A + B > A + D → B > D.
Since B + D = 2A and B > D: B > A > D.
Order: B > A = C > D.
A. A earns more than B — false (B > A).
B. B earns more than D — true.
C. C earns more than D — true (C = A > D).
D. B earns more than C — true.
E. B earns the highest — true.

Answer: A

Approach: Sum and difference of two unknowns.

Solution:
A = 80,000 → B + D = 2A = 1,60,000.
B − D = A = 80,000 (B > D from the earlier result).
Adding: 2B = 2,40,000 → B = 1,20,000 (and D = 40,000).

Why the other options are wrong:
A 40,000: that is D.
B 60,000, E 20,000: do not satisfy B + D = 1,60,000 with B − D = 80,000.
C 80,000: that is A (= C).

Cetking shortcut: B = (sum + difference)/2 = (1,60,000 + 80,000)/2.

Answer: D

Approach: Reverse the alphabet, then count positions to the right of the given letter.

Solution:
Reversed order: Z Y X W V U T S R Q P O N M L K J I H G F E D C B A.
In this order, the letters to the right of O are N, M, L, K, J, I, H, G ...
Counting 8 places: N(1), M(2), L(3), K(4), J(5), I(6), H(7), G(8).

Why the other options are wrong:
A (F): this is the 9th letter to the right.
C (V), D (W): these are to the LEFT of O in the reversed order.
E (A): this is the last letter of the reversed series, not the 8th from O.

Cetking shortcut: In the reversed series, moving right from a letter means going backwards in the normal alphabet. O = 15, so 15 − 8 = 7, which is G.

Answer: B