Q1-5. Directions: Read the following information carefully and answer the questions given beside.
In a certain code language,
action speaks louder is coded as 6ca 7ka 8ud
movie speaks truth is coded as 4vm 8ud 5ht
action packed movie is coded as 2ck 6ca 4vm
truth louder lie is coded as 3el 5ht 7ka
1. How is ‘lie’ coded in the given language?
(A) 5ht
(B) 3el
(C) 7ka
(D) 2ck
(E) None of these
EXPLANATION
Correct Option: B
From the common explanation, we get that the code for lie is 3el.
Hence option B is correct.
Common Explanation:
action speaks louder is coded as 6ca 7ka 8ud
movie speaks truth is coded as 4vm 8ud 5ht
action packed movie is coded as 2ck 6ca 4vm
truth louder lie is coded as 3el 5ht 7ka
2. Find the code for “packed truth”?
(A) 7ka 5ht
(B) 2ck 3el
(C) 3el 5ht
(D) 2ck 5ht
(E) Can’t be determined
EXPLANATION
Correct Option: D
From the common explanation, we get that the code for packed truth is 2ck 5ht.
Hence option D is correct.
Common Explanation:
action speaks louder is coded as 6ca 7ka 8ud
movie speaks truth is coded as 4vm 8ud 5ht
action packed movie is coded as 2ck 6ca 4vm
truth louder lie is coded as 3el 5ht 7ka
3. FInd the code for “movie”?
(A) 4vm
(B) 6ca
(C) 3el
(D) Can’t be determined
(E) None of these
EXPLANATION
Correct Option: A
From the common explanation, we get that the code for movie is 4vm.
Hence option A is correct.
Common Explanation:
action speaks louder is coded as 6ca 7ka 8ud
movie speaks truth is coded as 4vm 8ud 5ht
action packed movie is coded as 2ck 6ca 4vm
truth louder lie is coded as 3el 5ht 7ka
4. Code ‘6ca’ stands for which of the following?
(A) louder
(B) action
(C) speaks
(D) Either A or B
(E) None of these
EXPLANATION
Correct Option: B
From the common explanation, we get that the code 6ca stands for action.
Hence option B is correct.
Common Explanation:
action speaks louder is coded as 6ca 7ka 8ud
movie speaks truth is coded as 4vm 8ud 5ht
action packed movie is coded as 2ck 6ca 4vm
truth louder lie is coded as 3el 5ht 7ka
5. Code ‘2ck’ stands for which of the following?
(A) action
(B) movie
(C) packed
(D) louder
(E) None of these
EXPLANATION
Correct Option: C
From the common explanation, we get that the code 2ck stands for packed.
Hence option C is correct.
Common Explanation:
action speaks louder is coded as 6ca 7ka 8ud
movie speaks truth is coded as 4vm 8ud 5ht
action packed movie is coded as 2ck 6ca 4vm
truth louder lie is coded as 3el 5ht 7ka
Q6-10. Directions: In each of the following questions given below, a word is given followed by four combinations of symbols and digits labeled A, B, C and D. You have to find out which of the following four combinations correctly represents the word based on the alphabet codes and the conditions given below. If none of the combinations matches, choose ‘None of these’ as your answer.
| Letter | Q | U | J | H | O | B | A | T | R | E | S | L | M | I | P | F |
| Code | 5 | @ | & | 7 | $ | 6 | * | 9 | 3 | # | 2 | 4 | / | 8 | ! | % |
Condition 1:
If first element is a vowel and last element is a consonant then the code of first and last letter will be interchanged.
Condition 2:
If first element is a consonant and last element is a vowel then the code of third and fifth letter will be interchanged.
Condition 3:
If an element is appearing twice in the word then it will be coded as +.
Note: If a code follows more than one conditions, then all the conditions should be applied in order.
6. Find the code of ‘RBUEBL’.
(A) 3+@#+4
(B) 3@+*+4
(C) 4+#+@3
(D) 3+#@+4
(E) None of these
EXPLANATION
Correct Option:
AWe have,
The given Combination = RBUEBL
In the given combination, the first element is a consonant and last element is also a consonant, and ‘B’ is appearing twice in the word.
Thus, only condition 3 can be applied.
| Letter | Q | U | J | H | O | B | A | T | R | E | S | L | M | I | P | F |
| Code | 5 | @ | & | 7 | $ | 6 | * | 9 | 3 | # | 2 | 4 | / | 8 | ! | % |
Using the above we can write the code of ‘RBUEBL’ as ‘36@#64’.
After applying condition 3 the code becomes ‘3+@#+4’.
Hence, the correct answer is option A.
7. Find the code of ‘HOJOQA’.
(A) 7&5++*
(B) *5+&+7
(C) 7+&+5*
(D) 75&++*
(E) None of these
EXPLANATION
Correct Option:
EWe have,
The given Combination = HOJOQA
In the given combination, first element is a consonant and last element is a vowel, and ‘O’ is appearing twice in the word.
Thus, both conditions 2 and 3 will be applied.
| Letter | Q | U | J | H | O | B | A | T | R | E | S | L | M | I | P | F |
| Code | 5 | @ | & | 7 | $ | 6 | * | 9 | 3 | # | 2 | 4 | / | 8 | ! | % |
Applying condition 2, we can write the code of ‘HOJOQA’ as ‘7$5$&*’.
After applying condition 3 the code becomes ‘7+5+&*’.
Hence, the correct answer is option E.
8. Find the code of ‘UTFESP’.
(A) !9%2#@
(B) !9%#2@
(C) 9@%2#!
(D) !92#%@
(E) None of these
EXPLANATION
Correct Option:
BWe have,
The given Combination = UTFESP
In the given combination, first element is a vowel and last element is a consonant, and no letter is appearing twice in the word.
Thus, only condition 1 can be applied.
| Letter | Q | U | J | H | O | B | A | T | R | E | S | L | M | I | P | F |
| Code | 5 | @ | & | 7 | $ | 6 | * | 9 | 3 | # | 2 | 4 | / | 8 | ! | % |
Using the above we can write the code of ‘UTFESP’ as ‘@9%#2!’.
After applying condition 1 the code becomes ‘!9%#2@’.
Hence, the correct answer is option B.
9. Find the code of ‘EQRLIQ’.
(A) +3+84#
(B) +5+4#8
(C) ++348#
(D) +#348+
(E) None of these
EXPLANATION
Correct Option:
CWe have,
The given Combination = EQRLIQ
In the given combination, first element is a vowel and last element is a consonant, and ‘Q’ is appearing twice in the word.
Thus, both conditions 1 and 3 can be applied.
| Letter | Q | U | J | H | O | B | A | T | R | E | S | L | M | I | P | F |
| Code | 5 | @ | & | 7 | $ | 6 | * | 9 | 3 | # | 2 | 4 | / | 8 | ! | % |
Using the above we can write the code of ‘EQRLIQ’ as ‘#53485’.
After applying condition 1 the code becomes ‘55348#’.
Now, after applying condition 3 the code becomes ‘++348#’.
Hence, the correct answer is option C.
10. Find the code of ‘IMHUPA’.
(A) *@!/78
(B) 8/@7!*
(C) */7!@8
(D) */7@!8
(E) None of these
EXPLANATION
Correct Option:
EWe have,
The given combination = IMHUPA
In the given combination, first element is a vowel and last element is also a vowel, and no letter is appearing twice in the word.
Thus, direct coding will be applied.
| Letter | Q | U | J | H | O | B | A | T | R | E | S | L | M | I | P | F |
| Code | 5 | @ | & | 7 | $ | 6 | * | 9 | 3 | # | 2 | 4 | / | 8 | ! | % |
Using the above we can write the code of ‘IMHUPA’ as ‘8/7@!*’.
