Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
- 270m
- 273m
- 173m
- 275m
- 175m
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Answer: B
Approach: tan θ = height / base.
Solution:
Ship at 30°: distance = 100 × cot 30° = 100√3 ≈ 173.2 m.
Ship at 45°: distance = 100 × cot 45° = 100 m.
Opposite sides ⇒ distance between ships = 173.2 + 100 = 273.2 ≈ 273 m.
Why the other options are wrong:
C (173 m): only one ship's distance.
A, D, E: rounding or arithmetic slips; 100(√3 + 1) = 273.2.
Answer: B




