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Mandays – MBA CET questions with solutions

6 questions · CET 2025–2026 · Easy 3 · Medium 3 · Hard 0. Newest paper first. Full papers

Q123EasyCET 2026 · Slot 4 · Q123
If 12 carpenters working 6 hours a day can make 460 chairs in 24 days, how many chairs will 18 carpenters make in 36 days working 8 hours a day?
  1. 1260
  2. 1320
  3. 1400
  4. 1380
  5. 1200
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Answer: D official key

Approach: Work ∝ men × days × hours: M₁D₁H₁/W₁ = M₂D₂H₂/W₂.

Solution:
Case 1: 12 × 24 × 6 = 1728 man-hours for 460 chairs.
Case 2: 18 × 36 × 8 = 5184 man-hours.
5184/1728 = 3 ⇒ chairs = 460 × 3 = 1380.

Why the other options are wrong:
A (1260), B (1320), C (1400), E (1200) – miss one of the factors (e.g. 18/12 × 36/24 = 2.25 alone).

Cetking shortcut: Multiply the factor changes: (18/12) × (36/24) × (8/6) = 1.5 × 1.5 × 4/3 = 3.

Answer: D

Q124EasyCET 2026 · Slot 4 · Q124
A contractor undertook to do a certain piece of work in 9 days. He employed a certain number of men, but 6 of them were absent from the very first day, and the rest could finish the work in 15 days. The number of men originally employed were:
  1. 12
  2. 15
  3. 18
  4. 20
  5. 24
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Answer: B official key

Approach: Total man-days of work stay constant.

Solution:
Let x men be employed: work = 9x man-days.
Actually (x − 6) men took 15 days: work = 15(x − 6).
9x = 15x − 90 ⇒ 6x = 90 ⇒ x = 15.

Why the other options are wrong:
A (12) – with 6 present, 6 × 15 = 90 ≠ 108.
C (18), D (20), E (24) – 9x ≠ 15(x − 6).

Cetking shortcut: Absent men × 15 days = extra days (15 − 9) × x ⇒ 6 × 15 = 6x ⇒ x = 15.

Answer: B

Q117EasyCET 2025 · Slot 5 · Q117

A hostel has provisions for 250 students for 35 days. After 5 days, a fresh batch of 25 students was admitted to the hostel. Again after 10 days, a batch of 25 students left the hostel. How long will the remaining provisions survive?

  1. 17 days
  2. 19 days
  3. 21 days
  4. 15 days
  5. 25 days
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Answer: B

Approach: Mandays (student-days) are conserved: total provisions = students × days.

Solution:
Total = 250 × 35 = 8750 student-days
First 5 days: 250 × 5 = 1250
Next 10 days: 275 × 10 = 2750
Remaining = 8750 − 4000 = 4750
Now 250 students → 4750/250 = 19 days

Cetking shortcut: After 5 days, 30 days of food for 250 remain. 25 extra students for 10 days eat 250 student-days = 1 day for 250. 30 − 10 − 1 = 19 days.

Answer: B

Q131MediumCET 2025 · Slot 4 · Q131

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

  1. 4
  2. 5
  3. 6
  4. 7
  5. 3
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Answer: A

Approach: Mandays — convert everyone to boy-units.

Solution:
Let a man do M and a boy B units/day.
10(6M + 8B) = 2(26M + 48B) ⇒ 60M + 80B = 52M + 96B ⇒ 8M = 16B ⇒ M = 2B.
Work = 10(6 × 2B + 8B) = 10 × 20B = 200B.
15 men + 20 boys = 30B + 20B = 50B per day.
Days = 200B/50B = 4.

Why the other options are wrong:
B, C, D, E: do not equal 200/50.

Cetking shortcut: 1 man = 2 boys ⇒ first group = 20 boy-units × 10 days = 200; new group = 50 boy-units ⇒ 4 days.

Answer: A

Solution figure for question 131Solution figure for question 131Solution figure for question 131Solution figure for question 131
Q126MediumCET 2025 · Slot 3 · Q126
Sixteen men can complete a work in twelve days. Twenty-four children can complete the same work in eighteen days. Twelve men and eight children started working and after eight days three more children joined them. How many days will they now take to complete the remaining work?
  1. 2
  2. 4
  3. 6
  4. 8
  5. 10
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Answer: B

Approach: Express work in child-days.

Solution: Work = 16 × 12 = 192 man-days = 24 × 18 = 432 child-days → 1 man = 432/192 = 2.25 children.
12 men + 8 children = 27 + 8 = 35 child-units.
Work in 8 days = 35 × 8 = 280 → remaining = 432 − 280 = 152.
Now 35 + 3 = 38 child-units → days = 152 ÷ 38 = 4.

Answer: B

Q147MediumCET 2025 · Slot 2 · Q147
If a group of N people worked on a project and finished 35% of the project by working 7 hours a day for 10 days. Then 10 people left, and the remaining group completed the rest in 14 days by working 10 hours a day. Determine the value of N.
  1. 35
  2. 105
  3. 70
  4. 150
  5. 140
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Answer: E

Approach: Man-hours are proportional to work done.

Solution:
Phase 1: N × 7 × 10 = 70N man-hours → 35% of work.
Phase 2: (N − 10) × 10 × 14 = 140(N − 10) → 65% of work.
70N/35 = 140(N − 10)/65 → 2N = 28(N − 10)/13 → 26N = 28N − 280 → N = 140.

Cetking shortcut: Test options: N = 140 → 9800 man-hours for 35% (280 per %); 130 × 140 = 18200 for 65% (280 per %) ✓

Answer: E

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