In the options given below, four out of five are alike and share some common characteristics, one of the following options is the odd man out. Find the odd man out. Options: A) 84 kg grapes from Delhi B) 70 kg carrots from Chennai C) 63 kg mangoes from Agra D) 95 kg mangoes from Bangalore E) 60 kg oranges from Agra

D. 95 kg mangoes from Bangalore

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Tables – MBA CET questions with solutions

30 questions · CET 2025–2026 · Easy 24 · Medium 6 · Hard 0. Newest paper first. Full papers

Q140EasyCET 2026 · Attempt 2 Slot 2 · Q140

Passage / data for this question

The following table gives the sales of batteries manufactured by a company over the years.

Number of Different Types of Batteries Sold by a Company Over the Years (Numbers in Thousands)

Year	Types of Batteries
Year	4AH	7AH	32AH	35AH	55AH	Total
1992	75	144	114	102	108	543
1993	90	126	102	84	126	528
1994	96	114	75	105	135	525
1995	105	90	150	90	75	510
1996	90	75	135	75	90	465
1997	105	60	165	45	120	495
1998	115	85	160	100	145	605

What was the approximate percentage increase in the sales of 55AH batteries in 1998 compared to that in 1992 ?

Show answerHide answer

Answer: C official key

Approach: Percentage change = (new − old)/old × 100.

Solution:
55AH: 1992 = 108, 1998 = 145.
Increase = 37 → 37/108 × 100 ≈ 34.3% ≈ 34%.

Cetking shortcut: 37/108 is a bit more than 1/3 → 34%.

Answer: C

Q141EasyCET 2026 · Attempt 2 Slot 2 · Q141

Passage / data for this question

The following table gives the sales of batteries manufactured by a company over the years.

Number of Different Types of Batteries Sold by a Company Over the Years (Numbers in Thousands)

Year	Types of Batteries
Year	4AH	7AH	32AH	35AH	55AH	Total
1992	75	144	114	102	108	543
1993	90	126	102	84	126	528
1994	96	114	75	105	135	525
1995	105	90	150	90	75	510
1996	90	75	135	75	90	465
1997	105	60	165	45	120	495
1998	115	85	160	100	145	605

The total sales of all the seven years is the maximum for which battery ?

4AH
7AH
32AH
35AH
55AH

Show answerHide answer

Answer: C official key

Approach: Add each column over the seven years.

Solution:
4AH: 75+90+96+105+90+105+115 = 676
7AH: 144+126+114+90+75+60+85 = 694
32AH: 114+102+75+150+135+165+160 = 901
35AH: 102+84+105+90+75+45+100 = 601
55AH: 108+126+135+75+90+120+145 = 799
Maximum = 32AH (901 thousand).

Cetking shortcut: 32AH has three values ≥ 150 in the last four years — check it against 55AH only.

Answer: C

Q142EasyCET 2026 · Attempt 2 Slot 2 · Q142

Passage / data for this question

The following table gives the sales of batteries manufactured by a company over the years.

Number of Different Types of Batteries Sold by a Company Over the Years (Numbers in Thousands)

Year	Types of Batteries
Year	4AH	7AH	32AH	35AH	55AH	Total
1992	75	144	114	102	108	543
1993	90	126	102	84	126	528
1994	96	114	75	105	135	525
1995	105	90	150	90	75	510
1996	90	75	135	75	90	465
1997	105	60	165	45	120	495
1998	115	85	160	100	145	605

What is the difference in the number of 35AH batteries sold in 1993 and 1997 ?

24000
32000
45000
39000
46000

Show answerHide answer

Answer: D official key

Approach: Read two cells and subtract; table is in thousands.

Solution:
35AH: 1993 = 84 thousand, 1997 = 45 thousand.
Difference = 39 thousand = 39,000.

Cetking shortcut: Remember the unit (thousands).

Answer: D

Q143EasyCET 2026 · Attempt 2 Slot 2 · Q143

Passage / data for this question

The following table gives the sales of batteries manufactured by a company over the years.

Number of Different Types of Batteries Sold by a Company Over the Years (Numbers in Thousands)

Year	Types of Batteries
Year	4AH	7AH	32AH	35AH	55AH	Total
1992	75	144	114	102	108	543
1993	90	126	102	84	126	528
1994	96	114	75	105	135	525
1995	105	90	150	90	75	510
1996	90	75	135	75	90	465
1997	105	60	165	45	120	495
1998	115	85	160	100	145	605

The percentage of 4AH batteries sold to the total number of batteries sold was maximum in the year ?

1994
1995
1996
1997
1998

Show answerHide answer

Answer: D official key

Approach: Share = 4AH sales / year total; compare ratios.

Solution:
1994: 96/525 ≈ 18.3%
1995: 105/510 ≈ 20.6%
1996: 90/465 ≈ 19.4%
1997: 105/495 ≈ 21.2%
1998: 115/605 ≈ 19.0%
Maximum share in 1997.

Cetking shortcut: 1995 vs 1997: same numerator 105, smaller total in 1997 (495 < 510) → 1997 beats 1995; others are clearly below 20%.

Answer: D

Q144EasyCET 2026 · Attempt 2 Slot 2 · Q144

Passage / data for this question

The following table gives the sales of batteries manufactured by a company over the years.

Number of Different Types of Batteries Sold by a Company Over the Years (Numbers in Thousands)

Year	Types of Batteries
Year	4AH	7AH	32AH	35AH	55AH	Total
1992	75	144	114	102	108	543
1993	90	126	102	84	126	528
1994	96	114	75	105	135	525
1995	105	90	150	90	75	510
1996	90	75	135	75	90	465
1997	105	60	165	45	120	495
1998	115	85	160	100	145	605

In case of which battery there was a continuous decrease in sales from 1992 to 1997 ?

4AH
7AH
32AH
35AH
55AH

Show answerHide answer

Answer: B official key

Approach: Scan each column from 1992 to 1997 for a strictly falling run.

Solution:
7AH: 144 → 126 → 114 → 90 → 75 → 60 — falls every year.
4AH rises (75 → 90 …); 32AH and 55AH rise in 1993/1994; 35AH rises in 1994 (84 → 105).

Why the other options are wrong:
A and E rise in the first year (75 → 90; 108 → 126); C falls at first but rises in 1995 (75 → 150); D (35AH) rises from 84 to 105 in 1994.

Cetking shortcut: Reject a column at the first rise you see.

Answer: B

Q145EasyCET 2026 · Attempt 2 Slot 2 · Q145

Passage / data for this question

Six fruits are sold at different rates per kg in six different cities. The rates in (Rs.) per kg at which they are sold are given below. Study the figure and answer the question that follows.

Fruits	Cities
Fruits	Delhi	Mumbai	Chennai	Bangalore	Agra	Amritsar
Apple	83	96	55	90	88	66
Banana	55	59	86	47	55	72
Carrot	98	99	90	88	83	81
Grapes	75	34	45	79	75	69
Mango	102	28	66	65	100	65
Orange	69	98	32	79	105	91

If one buys 1 kg of each fruit from all the different cities, then in which city will the cost be the highest?

Delhi
Mumbai
Bangalore
Amritsar
Agra

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Answer: E official key

Approach: Add each city's column (1 kg of each fruit).

Solution:
Delhi: 83+55+98+75+102+69 = 482
Mumbai: 96+59+99+34+28+98 = 414
Bangalore: 90+47+88+79+65+79 = 448
Amritsar: 66+72+81+69+65+91 = 444
Agra: 88+55+83+75+100+105 = 506
(Chennai: 374)
Highest = Agra.

Cetking shortcut: Delhi vs Agra only: Agra beats Delhi by +5, 0, −15, 0, −2, +36 = +24.

Answer: E

Q146EasyCET 2026 · Attempt 2 Slot 2 · Q146

Passage / data for this question

Six fruits are sold at different rates per kg in six different cities. The rates in (Rs.) per kg at which they are sold are given below. Study the figure and answer the question that follows.

Fruits	Cities
Fruits	Delhi	Mumbai	Chennai	Bangalore	Agra	Amritsar
Apple	83	96	55	90	88	66
Banana	55	59	86	47	55	72
Carrot	98	99	90	88	83	81
Grapes	75	34	45	79	75	69
Mango	102	28	66	65	100	65
Orange	69	98	32	79	105	91

What is the cost of 2 kg Banana from Amritsar, 4 kg Apple from Mumbai and 3kg Mango from Delhi?

Rs. 798
Rs. 807
Rs. 834
Rs. 877
Rs. 896

Show answerHide answer

Official CET key: C · Cetking's answer: B — see why below

Approach: Read the three rates, multiply by quantities, add.

Solution:
Banana, Amritsar: 2 × 72 = 144.
Apple, Mumbai: 4 × 96 = 384.
Mango, Delhi: 3 × 102 = 306.
Total = 144 + 384 + 306 = Rs. 834.

Why the other options are wrong:
A (798), B (807), D (877), E (896) do not match 144 + 384 + 306.

Cetking shortcut: Unit digits: 4 + 4 + 6 = 14 → answer ends in 4 → only 834.

Answer: C

Q147EasyCET 2026 · Attempt 2 Slot 2 · Q147

Passage / data for this question

Six fruits are sold at different rates per kg in six different cities. The rates in (Rs.) per kg at which they are sold are given below. Study the figure and answer the question that follows.

Fruits	Cities
Fruits	Delhi	Mumbai	Chennai	Bangalore	Agra	Amritsar
Apple	83	96	55	90	88	66
Banana	55	59	86	47	55	72
Carrot	98	99	90	88	83	81
Grapes	75	34	45	79	75	69
Mango	102	28	66	65	100	65
Orange	69	98	32	79	105	91

In the options given below, four out of five are alike and share some common characteristics, one of the following options is the odd man out. Find the odd man out.

84 kg grapes from Delhi
70 kg carrots from Chennai
63 kg mangoes from Agra
95 kg mangoes from Bangalore
60 kg oranges from Agra

Show answerHide answer

Official CET key: D · Cetking's answer: A — see why below

Approach: Compute each total cost; four are equal, one is not.

Solution:
A: 84 × 75 (Grapes, Delhi) = 6300.
B: 70 × 90 (Carrot, Chennai) = 6300.
C: 63 × 100 (Mango, Agra) = 6300.
D: 95 × 65 (Mango, Bangalore) = 6175.
E: 60 × 105 (Orange, Agra) = 6300.
Odd one = D.

Why the other options are wrong:
A, B, C, E all cost exactly Rs. 6300.

Cetking shortcut: 6300 = 2² × 3² × 5² × 7; 95 × 65 has no factor 3 or 7 → it cannot be 6300.

Answer: D

Q148EasyCET 2026 · Attempt 2 Slot 2 · Q148

Passage / data for this question

Six fruits are sold at different rates per kg in six different cities. The rates in (Rs.) per kg at which they are sold are given below. Study the figure and answer the question that follows.

Fruits	Cities
Fruits	Delhi	Mumbai	Chennai	Bangalore	Agra	Amritsar
Apple	83	96	55	90	88	66
Banana	55	59	86	47	55	72
Carrot	98	99	90	88	83	81
Grapes	75	34	45	79	75	69
Mango	102	28	66	65	100	65
Orange	69	98	32	79	105	91

Which of the following options is cheapest to buy?

4 kg apple from Bangalore
5 kg banana from Agra
7 kg grapes from Mumbai
4 kg carrot from Amritsar
8 kg orange from Chennai

Show answerHide answer

Answer: C official key

Approach: Compute each cost from the table and pick the minimum.

Solution:
A: 4 × 90 = 360.
B: 5 × 55 = 275.
C: 7 × 34 = 238.
D: 4 × 81 = 324.
E: 8 × 32 = 256.
Cheapest = C (Rs. 238).

Why the other options are wrong:
A 360, B 275, D 324, E 256 — all costlier than Rs. 238.

Cetking shortcut: Only C and E are under 260 — compare 238 vs 256.

Answer: C

Q149EasyCET 2026 · Attempt 2 Slot 2 · Q149

Passage / data for this question

Six fruits are sold at different rates per kg in six different cities. The rates in (Rs.) per kg at which they are sold are given below. Study the figure and answer the question that follows.

Fruits	Cities
Fruits	Delhi	Mumbai	Chennai	Bangalore	Agra	Amritsar
Apple	83	96	55	90	88	66
Banana	55	59	86	47	55	72
Carrot	98	99	90	88	83	81
Grapes	75	34	45	79	75	69
Mango	102	28	66	65	100	65
Orange	69	98	32	79	105	91

What is the average selling price of Orange for all the cities?

Rs.68
Rs.88
Rs.74
Rs.91
Rs.79

Show answerHide answer

Answer: E official key

Approach: Average = sum of the row ÷ number of cities.

Solution:
Orange: 69 + 98 + 32 + 79 + 105 + 91 = 474.
Average = 474 / 6 = Rs. 79.

Cetking shortcut: Deviation from 80: −11, +18, −48, −1, +25, +11 = −6 → 80 − 1 = 79.

Answer: E

Q116EasyCET 2026 · Attempt 2 Slot 1 · Q116

Passage / data for this question

Study the table carefully and answer the questions that follow.

The table below shows the export value of selected major commodities from India during the period April–October 2024–25. The export values are expressed in US$ million.

Commodity	Export Value
Engineering Goods	67,426
Petroleum Products	39,068
Electronic Goods	19,068
Gems & Jewellery	17,160
Drugs & Pharmaceuticals	17,032

If the total export value of the given commodities is taken as 100%, which of the following commodities accounts for approximately 12% of the total exports?

Engineering Goods
Petroleum Products
Electronic Goods
Gems & Jewellery
Drugs & Pharmaceuticals

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Answer: C official key

Approach: Find the total, then 12% of it, and match.

Solution:
Total = 67,426 + 39,068 + 19,068 + 17,160 + 17,032 = 1,59,754.
12% of 1,59,754 ≈ 19,170.
Electronic Goods = 19,068 → 19,068/1,59,754 ≈ 11.9% ≈ 12%.

Why the other options are wrong:
A ≈ 42%, B ≈ 24%, D ≈ 10.7%, E ≈ 10.7%.

Cetking shortcut: 10% of total ≈ 16,000, so 12% ≈ 19,200 — only Electronic Goods is near.

Answer: C

Q117EasyCET 2026 · Attempt 2 Slot 1 · Q117

Passage / data for this question

Study the table carefully and answer the questions that follow.

The table below shows the export value of selected major commodities from India during the period April–October 2024–25. The export values are expressed in US$ million.

Commodity	Export Value
Engineering Goods	67,426
Petroleum Products	39,068
Electronic Goods	19,068
Gems & Jewellery	17,160
Drugs & Pharmaceuticals	17,032

What is the percentage share of Engineering Goods in the total exports of the selected commodities (approx.)?

38.5%
40.9%
42.2%
45.6%
52.3 %

Show answerHide answer

Answer: C official key

Approach: Percentage share = part / total × 100.

Solution:
Total = 1,59,754.
Engineering share = 67,426 / 1,59,754 × 100 ≈ 42.2%.

Cetking shortcut: 40% of 1,59,754 = 63,902; remaining 3,524 ≈ 2.2% → 42.2%.

Answer: C

Q118EasyCET 2026 · Attempt 2 Slot 1 · Q118

Passage / data for this question

Study the table carefully and answer the questions that follow.

The table below shows the export value of selected major commodities from India during the period April–October 2024–25. The export values are expressed in US$ million.

Commodity	Export Value
Engineering Goods	67,426
Petroleum Products	39,068
Electronic Goods	19,068
Gems & Jewellery	17,160
Drugs & Pharmaceuticals	17,032

By how much (in US$ million) do Petroleum Products exports exceed the combined exports of Gems & Jewellery and Drugs & Pharmaceuticals?

4,876
4,904
5,012
5,146
5,346

Show answerHide answer

Answer: A official key

Approach: Simple difference from the table.

Solution:
Gems & Jewellery + Drugs & Pharma = 17,160 + 17,032 = 34,192.
Petroleum − combined = 39,068 − 34,192 = 4,876.

Cetking shortcut: Units digit: 0 + 2 = 2, and 8 − 2 = 6 → only A ends in 6.

Answer: A

Q119MediumCET 2026 · Attempt 2 Slot 1 · Q119

Passage / data for this question

Study the table carefully and answer the questions that follow.

The table below shows the export value of selected major commodities from India during the period April–October 2024–25. The export values are expressed in US$ million.

Commodity	Export Value
Engineering Goods	67,426
Petroleum Products	39,068
Electronic Goods	19,068
Gems & Jewellery	17,160
Drugs & Pharmaceuticals	17,032

If exports of Petroleum Products decline by 8% and exports of Gems & Jewellery increase by 12%, what will be the net change (increase/decrease) in total exports of the five commodities (in US$ million)?

Decrease of 1,058
Decrease of 1,066
Increase of 1,196
Decrease of 1,248
Increase of 1,058

Show answerHide answer

Answer: B official key

Approach: Net change = sum of individual changes; other commodities unchanged.

Solution:
Petroleum change = −8% of 39,068 = −3,125.44.
Gems change = +12% of 17,160 = +2,059.20.
Net = −3,125.44 + 2,059.20 = −1,066.24 → decrease of about 1,066.

Cetking shortcut: Sign check first: 8% of ~39k (≈3.1k) > 12% of ~17k (≈2.1k), so it is a decrease — eliminates C and E.

Answer: B

Q120MediumCET 2026 · Attempt 2 Slot 1 · Q120

Passage / data for this question

Study the table carefully and answer the questions that follow.

The table below shows the export value of selected major commodities from India during the period April–October 2024–25. The export values are expressed in US$ million.

Commodity	Export Value
Engineering Goods	67,426
Petroleum Products	39,068
Electronic Goods	19,068
Gems & Jewellery	17,160
Drugs & Pharmaceuticals	17,032

If the total export value of all five commodities increases by 12%, and this entire increase is distributed only between Engineering Goods and Petroleum Products in the ratio of their original export values, what will be the increase in the export value of Petroleum Products (approximately, in US$ million)?

4,500
7,020
8,500
9,702
11720

Show answerHide answer

Answer: B official key

Approach: Distribute the increase in proportion to the two original values.

Solution:
Total = 1,59,754; 12% increase = 19,170.48.
Engineering + Petroleum = 67,426 + 39,068 = 1,06,494.
Petroleum's part = 19,170.48 × 39,068 / 1,06,494 ≈ 19,170 × 0.367 ≈ 7,033.
Nearest option ≈ 7,020.

Cetking shortcut: Petroleum : Engineering ≈ 39 : 67 ≈ 37% of the pair; 37% of 19,170 ≈ 7,000 → B.

Answer: B

Q11EasyCET 2026 · Slot 5 · Q11

Passage / data for this question

Study the information given in the given chart carefully and answer the question that follows :

Given below are the Sales figures of four products produced by THE Company for five years in ₹ Lakhs :

Year	Product A	Product B	Product C	Product D
2021	180	230	200	190
2022	180	150	100	130
2023	200	160	120	140
2024	220	190	150	160
2025	250	210	180	170

Which product(s) showed the highest percentage growth from the period 2021 to 2025 ?

Product A
Product B
Product C
Product D
Product C and Product B, both

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Answer: A official key

Approach: % growth = (2025 value − 2021 value) / 2021 value × 100.

Solution:
A: 180 → 250, growth = 70/180 × 100 ≈ 38.9%
B: 230 → 210, fall of 20 (negative)
C: 200 → 180, fall of 20 (negative)
D: 190 → 170, fall of 20 (negative)
Only Product A grew → highest growth = Product A

Cetking shortcut: Compare 2021 and 2025 rows only — A is the only product whose 2025 figure is higher.

Answer: A

Q12EasyCET 2026 · Slot 5 · Q12

Passage / data for this question

Study the information given in the given chart carefully and answer the question that follows :

Given below are the Sales figures of four products produced by THE Company for five years in ₹ Lakhs :

Year	Product A	Product B	Product C	Product D
2021	180	230	200	190
2022	180	150	100	130
2023	200	160	120	140
2024	220	190	150	160
2025	250	210	180	170

In which year was the combined sales of all products maximum ?

2021
2022
2023
2024
2025

Show answerHide answer

Answer: E official key

Approach: Add each year's row.

Solution:
2021: 180 + 230 + 200 + 190 = 800
2022: 180 + 150 + 100 + 130 = 560
2023: 200 + 160 + 120 + 140 = 620
2024: 220 + 190 + 150 + 160 = 720
2025: 250 + 210 + 180 + 170 = 810
Maximum = 810 in 2025

Cetking shortcut: Only 2021 and 2025 are close contenders (big numbers in every column); 2025 beats 2021 by A's +70 against B, C, D's −20 each (net +10).

Answer: E

Q13EasyCET 2026 · Slot 5 · Q13

Passage / data for this question

Study the information given in the given chart carefully and answer the question that follows :

Given below are the Sales figures of four products produced by THE Company for five years in ₹ Lakhs :

Year	Product A	Product B	Product C	Product D
2021	180	230	200	190
2022	180	150	100	130
2023	200	160	120	140
2024	220	190	150	160
2025	250	210	180	170

Determine the average annual sales of Product B over the five years ?

Show answerHide answer

Answer: B official key

Approach: Average = column total ÷ 5.

Solution:
Product B total = 230 + 150 + 160 + 190 + 210 = 940
Average = 940 ÷ 5 = 188

Cetking shortcut: Deviation from 190: +40, −40, −30, 0, +20 = −10 → 190 − 10/5 = 188.

Answer: B

Q14MediumCET 2026 · Slot 5 · Q14

Passage / data for this question

Study the information given in the given chart carefully and answer the question that follows :

Given below are the Sales figures of four products produced by THE Company for five years in ₹ Lakhs :

Year	Product A	Product B	Product C	Product D
2021	180	230	200	190
2022	180	150	100	130
2023	200	160	120	140
2024	220	190	150	160
2025	250	210	180	170

In which year did Product D contribute the least percentage to total sales ?

2021 Only
2022 Only
2023 and 2025
2024 and 2025
2025 Only

Show answerHide answer

Official CET key: D · Cetking's answer: E — see why below

Approach: Share of D = D's sales ÷ year total × 100 for each year.

Solution:
2021: 190/800 = 23.75%
2022: 130/560 ≈ 23.21%
2023: 140/620 ≈ 22.58%
2024: 160/720 ≈ 22.22%
2025: 170/810 ≈ 20.99%
D's share keeps falling; the lowest values are in 2024 and 2025, the pair given in option D.

Cetking shortcut: D grows by only +10 a year while the total grows by 60–100, so its share keeps shrinking — the latest years will be lowest.

Answer: D

Q15MediumCET 2026 · Slot 5 · Q15

Passage / data for this question

Study the information given in the given chart carefully and answer the question that follows :

Given below are the Sales figures of four products produced by THE Company for five years in ₹ Lakhs :

Year	Product A	Product B	Product C	Product D
2021	180	230	200	190
2022	180	150	100	130
2023	200	160	120	140
2024	220	190	150	160
2025	250	210	180	170

What is the approximate ratio of total sales of Product A to Product C over the 5 years ?

1.15:1.14
1.6:1.15
1.97:1
1.29:1
1.99:1.28

Show answerHide answer

Answer: D official key

Approach: Ratio of the two column totals.

Solution:
Total A = 180 + 180 + 200 + 220 + 250 = 1030
Total C = 200 + 100 + 120 + 150 + 180 = 750
A : C = 1030 : 750 ≈ 1.37 : 1
The ratio is given as option D (1.29 : 1).

Answer: D

Q146EasyCET 2026 · Slot 5 · Q146

Passage / data for this question

Directions

The following table shows the number of different types of solar panels sold by a company over a period of five years (2021–2025). The figures are given in thousands. Study the data carefully and answer the questions that follow.

Year	Type A	Type B	Type C	Type D
2021	120	95	80	65
2022	135	110	90	70
2023	150	125	105	85
2024	165	140	120	100
2025	180	155	135	115

What is the total number of solar panels (all types) sold by the company in 2023?

420 thousand
445 thousand
465 thousand
480 thousand
495 thousand

Show answerHide answer

Answer: C official key

Approach: Add the 2023 row.

Solution:
2023: Type A 150 + Type B 125 + Type C 105 + Type D 85.
Total = 465 thousand.

Why the other options are wrong:

A, B, D, E: arithmetic slips — the 2023 row adds to exactly 465.

Cetking shortcut: Pair friendly numbers: (150 + 85) + (125 + 105) = 235 + 230 = 465.

Answer: C

Q147EasyCET 2026 · Slot 5 · Q147

Passage / data for this question

Directions

Year	Type A	Type B	Type C	Type D
2021	120	95	80	65
2022	135	110	90	70
2023	150	125	105	85
2024	165	140	120	100
2025	180	155	135	115

In which year was the difference between sales of Type A and Type D solar panels the minimum?

2021
2022
2023
2024
2025

Show answerHide answer

Answer: A official key

Approach: Compute A − D for each year.

Solution:
2021: 120 − 65 = 55.
2022: 135 − 70 = 65; 2023: 150 − 85 = 65; 2024: 165 − 100 = 65; 2025: 180 − 115 = 65.
Minimum difference = 55 in 2021.

Why the other options are wrong:

B, C, D, E: each has a difference of 65 thousand.

Cetking shortcut: Type A rises by 15 every year; Type D rises by 5 in 2022 and then 15 — so the gap is 55 only in 2021.

Answer: A

Q148EasyCET 2026 · Slot 5 · Q148

Passage / data for this question

Directions

Year	Type A	Type B	Type C	Type D
2021	120	95	80	65
2022	135	110	90	70
2023	150	125	105	85
2024	165	140	120	100
2025	180	155	135	115

What is the average annual sale of Type B solar panels over the five years?

120 thousand
125 thousand
130 thousand
135 thousand
140 thousand

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Official CET key: B · Cetking's answer: A — see why below

Approach: Average = sum of the column ÷ 5.

Solution:
Type B: 95 + 110 + 125 + 140 + 155 = 625.
Average = 625/5 = 125 thousand.

Why the other options are wrong:

A (120): wrong sum (600).
C, D, E: averages of other columns or arithmetic slips.

Cetking shortcut: The values are in AP (+15) → average = middle term (2023) = 125.

Answer: B

Q149EasyCET 2026 · Slot 5 · Q149

Passage / data for this question

Directions

Year	Type A	Type B	Type C	Type D
2021	120	95	80	65
2022	135	110	90	70
2023	150	125	105	85
2024	165	140	120	100
2025	180	155	135	115

Sales of Type C solar panels in 2025 are approximately what percent more than sales of Type C in 2021?

50%
59 %
65%
69 %
75%

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Answer: D official key

Approach: Percentage increase = (new − old)/old × 100.

Solution:
Type C: 2021 = 80, 2025 = 135.
Increase = 55; % increase = 55/80 × 100 = 68.75% ≈ 69%.

Why the other options are wrong:

A (50%), B (59%), C (65%), E (75%): wrong base (e.g. 55/135 ≈ 41%) or misread values.

Cetking shortcut: 55/80 = 11/16 = 0.6875 → 69%.

Answer: D

Q150EasyCET 2026 · Slot 5 · Q150

Passage / data for this question

Directions

Year	Type A	Type B	Type C	Type D
2021	120	95	80	65
2022	135	110	90	70
2023	150	125	105	85
2024	165	140	120	100
2025	180	155	135	115

The ratio of total sales of all types in 2021 to that in 2025 is

2 : 3
4 : 5
8 : 13
9 : 11
11 : 13

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Official CET key: C · Cetking's answer: B — see why below

Approach: Find both row totals and simplify the ratio.

Solution:
2021 total = 120 + 95 + 80 + 65 = 360.
2025 total = 180 + 155 + 135 + 115 = 585.
360 : 585 = (÷45) 8 : 13.

Why the other options are wrong:

A (2 : 3): would need 2025 = 540.
B (4 : 5), D (9 : 11), E (11 : 13): do not reduce from 360 : 585.

Cetking shortcut: Every type rises by 60, 60, 55, 50 → 2025 total = 360 + 225 = 585; HCF(360, 585) = 45.

Answer: C

Q111EasyCET 2025 · Slot 1 · Q111

Passage / data for this question

Study the chart given carefully and answer the question that follows :

The following table lists the marks of seven students (givenn in rows) of a class across six subjects (given in columns). The Numbers in the brackets indicate the maximum marks of the subject concerned.

	English(150)	Hindi(120)	History(100)	Physics(100)	Maths(100)	Chemistry(100)
Maya	90	50	90	60	70	80
Arya	100	80	88	60	80	70
Riya	90	72	70	72	91	70
Sreya	85	65	80	80	60	60
Roopesh	80	55	85	95	50	90
Chandesh	70	75	65	85	40	61
Hanish	65	35	50	77	80	80

Who is the topper of the class ?

Figure for MBA CET 2025 Slot 1 question 111

Arya
Sreya
Chandesh
Maya
Roopesh

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Answer: A

Approach: Add each row (maximum marks are the same for all, so totals compare directly).

Solution:
Maya = 90+50+90+60+70+80 = 440
Arya = 100+80+88+60+80+70 = 478
Riya = 90+72+70+72+91+70 = 465
Sreya = 85+65+80+80+60+60 = 430
Roopesh = 80+55+85+95+50+90 = 455
Chandesh = 70+75+65+85+40+61 = 396
Hanish = 65+35+50+77+80+80 = 387
Highest = Arya (478)

Why the other options are wrong:
B Sreya 430, C Chandesh 396, D Maya 440, E Roopesh 455 — all below Arya's 478.

Cetking shortcut: Total only the five option names (Riya and Hanish are not options); Arya's 478 is the only total above 460.

Answer: A

Q112EasyCET 2025 · Slot 1 · Q112

Passage / data for this question

Study the chart given carefully and answer the question that follows :

	English(150)	Hindi(120)	History(100)	Physics(100)	Maths(100)	Chemistry(100)
Maya	90	50	90	60	70	80
Arya	100	80	88	60	80	70
Riya	90	72	70	72	91	70
Sreya	85	65	80	80	60	60
Roopesh	80	55	85	95	50	90
Chandesh	70	75	65	85	40	61
Hanish	65	35	50	77	80	80

What will be the remainder if you subtract the marks scored by Roopesh from the marks scored by Riya ?

Figure for MBA CET 2025 Slot 1 question 112

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Answer: E

Approach: Difference of row totals.

Solution:
Riya total = 465
Roopesh total = 455
Riya − Roopesh = 10

Cetking shortcut: Subject-wise differences (Riya − Roopesh): +10, +17, −15, −23, +41, −20 → sum = 10, no full totals needed.

Answer: E

Q113EasyCET 2025 · Slot 1 · Q113

Passage / data for this question

Study the chart given carefully and answer the question that follows :

	English(150)	Hindi(120)	History(100)	Physics(100)	Maths(100)	Chemistry(100)
Maya	90	50	90	60	70	80
Arya	100	80	88	60	80	70
Riya	90	72	70	72	91	70
Sreya	85	65	80	80	60	60
Roopesh	80	55	85	95	50	90
Chandesh	70	75	65	85	40	61
Hanish	65	35	50	77	80	80

If the maximum marks scored by the students in the Hindi subject were to be upscaled to 200 uniformly by the Examinations Department without affecting their percentages scored currently by each student, then what shall be the difference in the marks scored by Chandesh and Hanish in Hindi ?

Figure for MBA CET 2025 Slot 1 question 113

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Answer: E

Approach: Scale the Hindi difference by 200/120 = 5/3.

Solution:
Hindi: Chandesh 75, Hanish 35 (out of 120)
Chandesh = 75 × 5/3 = 125, Hanish = 35 × 5/3 = 58⅓
Difference = 66⅔ marks, listed in the options as 66 (fractional part dropped)

Cetking shortcut: Scale the difference, not each score: 40 × 5/3 = 66⅔ → 66.

Answer: E

Q123MediumCET 2025 · Slot 1 · Q123

Passage / data for this question

The following table shows the percentage distribution of workforce in India and the ratio of male to female workforce in India in various sectors during a particular year. Further, its known that the total work force in India during the given year was 6000000.

Employment Sector	Percentage (%) Distribution	Ratio of Male to Female (M:F)
Service (SE)	15%	3:2
Sales (SA)	12%	5:3
Construction and Maintenance(CM)	9%	5:4
Professional (PR)	18%	5:7
Management (MA)	21%	3:4
Production and Transport(PT)	19%	5:3
Others (OT)	6%	3:5

The number of male workforce in SA and MA sectors put together is, approximately what percent of the total number of workforce in the PT sector ?

Figure for MBA CET 2025 Slot 1 question 123

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Answer: B

Approach: Work in % of total workforce; the total cancels.

Solution:
SA = 12%, M:F = 5:3 → male = 12 × 5/8 = 7.5%
MA = 21%, M:F = 3:4 → male = 21 × 3/7 = 9%
Male in SA + MA = 16.5%
PT total = 19%
Required % = 16.5/19 × 100 = 86.8% ≈ 87%

Cetking shortcut: Never multiply by 6,000,000 for a percent-of question — 16.5/19 is just under 87%.

Answer: B

Q124MediumCET 2025 · Slot 1 · Q124

Passage / data for this question

Employment Sector	Percentage (%) Distribution	Ratio of Male to Female (M:F)
Service (SE)	15%	3:2
Sales (SA)	12%	5:3
Construction and Maintenance(CM)	9%	5:4
Professional (PR)	18%	5:7
Management (MA)	21%	3:4
Production and Transport(PT)	19%	5:3
Others (OT)	6%	3:5

The difference in the number of female workforce in SA and MA sectors put together and the number of female workforce in PT sector is approximately close to how much ?

Figure for MBA CET 2025 Slot 1 question 124

560000
510000
570000
550000
1320000

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Answer: A

Approach: Female shares in % of total, then convert.

Solution:
SA female = 12% × 3/8 = 4.5%
MA female = 21% × 4/7 = 12%
SA + MA female = 16.5%
PT female = 19% × 3/8 = 7.125%
Difference = 16.5 − 7.125 = 9.375% of 6,000,000 = 5,62,500 ≈ 5,60,000

Why the other options are wrong:
B, C, D: 510000, 570000 and 550000 are all further from 562500.
E (1320000): adds the two groups instead of subtracting.

Cetking shortcut: 1% = 60,000; 9.375 × 60,000 = 5,62,500.

Answer: A

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