35 questions · CET 2025–2026 · Easy 25 · Medium 8 · Hard 2. Newest paper first. Full papers
If + means ÷, - means x, x means +, ÷ means -, then give the value for 45 + 9 - 3 x 15 ÷ 2
Answer: B official key
Approach: Symbol substitution, then BODMAS.
Solution:
Replace: + → ÷, − → ×, × → +, ÷ → −.
45 + 9 − 3 × 15 ÷ 2 becomes 45 ÷ 9 × 3 + 15 − 2.
45 ÷ 9 = 5; 5 × 3 = 15.
15 + 15 − 2 = 28.
Cetking shortcut: Rewrite the whole expression first, then solve — never substitute and compute at the same time.
Answer: B
If 'K' means 'minus', 'L' means 'divided by', 'M' means 'plus' and 'D' means 'multiplied by', then
117 L 3 K 5 M 12 D 8 = ?
Answer: B official key
Approach: Letter-to-operator substitution, then BODMAS.
Solution:
K = −, L = ÷, M = +, D = ×.
117 L 3 K 5 M 12 D 8 = 117 ÷ 3 − 5 + 12 × 8.
117 ÷ 3 = 39; 12 × 8 = 96.
39 − 5 + 96 = 130.
Cetking shortcut: Division and multiplication first: 39 and 96, then 39 + 96 − 5.
Answer: B
If you write down all the numbers from 1 to 100, then how many times do you write 3 ?
Answer: C official key
Approach: Digit counting: count the digit 3 in the units place and in the tens place separately.
Solution:
Units place: 3, 13, 23, 33, 43, 53, 63, 73, 83, 93 ⇒ 10 times.
Tens place: 30, 31, …, 39 ⇒ 10 times.
33 is counted in both lists, which is right because it has two 3s.
100 has no 3. Total = 10 + 10 = 20.
Why the other options are wrong:
A (11), E (10): count only one place value.
B (18), D (21): miscount the overlap at 33.
Cetking shortcut: From 1 to 99, every non-zero digit appears 10 times in units and 10 times in tens = 20.
Answer: C
Find the number that shall come in place of "?" in the given table :
| 7 | 3 | 6 | 2 |
| 2 | 8 | 5 | 4 |
| 1 | 1 | 2 | 4 |
| 4 | 2 | 1 | ? |
Official CET key: D · Cetking's answer: E — see why below
Approach: Constant column sum.
Solution:
Column 1: 7 + 2 + 1 + 4 = 14
Column 2: 3 + 8 + 1 + 2 = 14
Column 3: 6 + 5 + 2 + 1 = 14
Column 4: 2 + 4 + 4 + ? = 14 → ? = 4
Cetking shortcut: In number grids test row sums and column sums first — here the column sums are all equal.
Answer: D
Which interchange of sign will make the following equation correct :
10 + 10 ÷ 10 – 10 × 10 = 10
Official CET key: E · Cetking's answer: C — see why below
Approach: Swap the two signs everywhere, then evaluate with BODMAS.
Solution:
Given: 10 + 10 ÷ 10 − 10 × 10 = 10 + 1 − 100 = −89 (wrong as it stands).
Interchange + and ×: 10 × 10 ÷ 10 − 10 + 10
= 100 ÷ 10 − 10 + 10
= 10 − 10 + 10 = 10 ✓
Why the other options are wrong:
A) 10 − 10 ÷ 10 + 10 × 10 = 10 − 1 + 100 = 109 ✗
C) 10 ÷ 10 + 10 − 10 × 10 = 1 + 10 − 100 = −89 ✗
B) 10 + 10 ÷ 10 × 10 − 10 = 10 + 10 − 10 = 10 and D) 10 + 10 − 10 ÷ 10 × 10 = 10 + 10 − 10 = 10 also balance under BODMAS — the official key is E.
Cetking shortcut: With all numbers equal to 10, look for a swap that makes 10 × 10 ÷ 10 = 10 and leaves '− 10 + 10' to cancel.
Answer: E
If :
R stands for -
A stands for +
B stands for ÷
C stands for X
Then determine the value of the given equation [without applying the BODMAS Rule] ?
25 A 37 C 2 B 4 R 1 = ?
Official CET key: C · Cetking's answer: D — see why below
Approach: Replace letters by signs and evaluate.
Solution:
25 A 37 C 2 B 4 R 1 → 25 + 37 × 2 ÷ 4 − 1
The key's value comes from the usual order of operations:
37 × 2 = 74, 74 ÷ 4 = 18.5
25 + 18.5 − 1 = 42.5
(Strict left-to-right work gives 62 × 2 = 124, ÷ 4 = 31, − 1 = 30, which is not an option — so the options are built on the BODMAS value.)
Cetking shortcut: If the left-to-right value is not in the options, switch to BODMAS — the paper's options reveal the intended method.
Answer: C
If :
X means addition
- means division
÷ means subtraction
+ means multiplication
Then, which of the following equation is correct ?
Solve without applying BODMAS Rule
Answer: D official key
Approach: Substitute the signs (X → +, − → ÷, ÷ → −, + → ×) and evaluate left to right.
Solution:
D) 16 + 5 − 10 X 4 ÷ 3 → 16 × 5 ÷ 10 + 4 − 3
16 × 5 = 80, 80 ÷ 10 = 8, 8 + 4 = 12, 12 − 3 = 9 ✓
Why the other options are wrong:
A) 16 × 5 − 10 + 4 ÷ 3 = (80 − 10 + 4) ÷ 3 = 24.67 ≠ 9
B) 16 × 5 − 10 + 3 ÷ 6 = 73 ÷ 6 ≈ 12.17 ≠ 7
C) 16 ÷ 5 + 10 − 4 × 3 = 9.2 × 3 = 27.6 ≠ 12
E) 16 + 5 − 9 ÷ 4 × 10 = 12 ÷ 4 × 10 = 30 ≠ 8
Answer: D
Which two signs should be interchanged to make the given equation correct :
12 + 156 ÷ 13 × 6 – 100 = 50
Official CET key: A · Cetking's answer: D — see why below
Approach: Try each interchange and evaluate with BODMAS.
Solution:
Interchange + and ×: 12 × 156 ÷ 13 + 6 − 100
12 × 156 = 1872, 1872 ÷ 13 = 144
144 + 6 − 100 = 50 ✓
Why the other options are wrong:
B) 12 + 156 − 13 × 6 ÷ 100 ≈ 167.2
C) 12 + 156 ÷ 13 − 6 × 100 = −576
D) 12 − 156 ÷ 13 × 6 + 100 = 40
E) 12 + 156 × 13 ÷ 6 − 100 = 250
Cetking shortcut: 156 = 12 × 13, so 12 × 156 ÷ 13 = 144 instantly.
Answer: A
In the question, certain mathematical operations are redefined. Find the value of the given expression using the new meanings of the symbols.
If + means ×, × means –, ÷ means + & – means ÷,
then Find 200 – 20 ÷ 5 + 20 × 3+10 = ?
Official CET key: E · Cetking's answer: D — see why below
Approach: Replace each symbol with its new meaning, then apply BODMAS.
Solution: Given: + → ×, × → −, ÷ → +, − → ÷.
200 – 20 ÷ 5 + 20 × 3 + 10 becomes 200 ÷ 20 + 5 × 20 − 3 × 10.
Division/multiplication first: 200 ÷ 20 = 10; 5 × 20 = 100; 3 × 10 = 30.
Then: 10 + 100 − 30 = 80.
Cetking shortcut: Rewrite the whole expression once with new symbols before calculating – substituting on the fly causes most errors.
Answer: E
If ‘when’ means ‘x’, ‘you’ means ‘÷’, ‘come’ means ‘-’ and ‘will’ means ‘+’, then what will be the value of “8 when 12 will 16 you 2 come 10”?
Answer: D official key
Approach: Replace the words with operators and apply BODMAS.
Solution: when = ×, will = +, you = ÷, come = −.
8 × 12 + 16 ÷ 2 − 10 = 96 + 8 − 10 = 94.
Cetking shortcut: Do ÷ and × first: 96 and 8, then add/subtract.
Answer: D
Which of the following equation will be correct if ÷ & +, 12 & 18 are interchanged with each other?
Official CET key: D · Cetking's answer: E — see why below
Approach: Interchange ÷ ↔ + and 12 ↔ 18 in each option and check which equation holds.
Solution: Option D: (12 + 6) × 18 = 36 → (18 ÷ 6) × 12 = 3 × 12 = 36 ✔.
Check others: A → (90 × 12) ÷ 12 = 90 ≠ 60; B → (12 ÷ 6) + 18 = 20 ≠ 2; C → (72 + 12) × 12 = 1008 ≠ 72; E → (36 + 12) ÷ 18 = 2.67 ≠ 4.
Why the other options are wrong: A gives 90, B gives 20, C gives 1008, E gives 2.67 – none equal the RHS.
Cetking shortcut: Start with options whose RHS is small and has both 12 and 18 in it – D works immediately.
Answer: D
If P means –, Q means ×, R means ÷ & S means +, then what will be the value of given equation?
14 Q 3 P 12 S 4 R 2 = ?
Official CET key: C · Cetking's answer: D — see why below
Approach: Replace letters with operators and apply BODMAS.
Solution: P = −, Q = ×, R = ÷, S = +.
14 Q 3 P 12 S 4 R 2 = 14 × 3 − 12 + 4 ÷ 2.
= 42 − 12 + 2 = 32.
Cetking shortcut: Multiplication and division first: 42 and 2; then 42 − 12 + 2.
Answer: C
If
P $ Q, means divide
P # Q, means subtract
P% Q, means Add
P @Q, means multiply
then, 70 # 30% 80$ 20@ 10 = ?
Answer: C official key
Approach: Decode the symbols and apply BODMAS.
Solution: $ = ÷, # = −, % = +, @ = ×.
70 # 30 % 80 $ 20 @ 10 = 70 − 30 + 80 ÷ 20 × 10.
80 ÷ 20 = 4; 4 × 10 = 40.
70 − 30 + 40 = 80.
Cetking shortcut: Division and multiplication left to right first: 80 ÷ 20 × 10 = 40.
Answer: C
If × means –, + means ÷, – means × and ÷ means +, then 11 – 2 ÷ 700 + 70 × 50 = ?
Official CET key: C · Cetking's answer: A — see why below
Approach: Replace symbols, then apply BODMAS.
Solution:
Rules: × → –, + → ÷, – → ×, ÷ → +.
11 – 2 ÷ 700 + 70 × 50 becomes 11 × 2 + 700 ÷ 70 – 50
= 22 + 10 – 50
= –18.
Why the other options are wrong: 10 / –10 / –32 / –24 come from wrong substitution or from solving left to right without BODMAS.
Cetking shortcut: Rewrite the whole expression first, then compute — never substitute and calculate at the same time.
Answer: C
| 4 | 5 | 3 | 2 | 0 |
| 7 | 3 | 4 | 4 | 21 |
| 6 | 4 | 4 | 5 | 22 |
| 9 | 6 | 5 | 5 | ? |
Answer: E official key
Approach: Row rule: (1st × 4th) – (2nd + 3rd) = 5th.
Solution:
Row 1: 4 × 2 – (5 + 3) = 8 – 8 = 0 ✓
Row 2: 7 × 4 – (3 + 4) = 28 – 7 = 21 ✓
Row 3: 6 × 5 – (4 + 4) = 30 – 8 = 22 ✓
Row 4: 9 × 5 – (6 + 5) = 45 – 11 = 34.
Cetking shortcut: A 0 in the result column signals equal parts cancelling — look for (product) – (sum) = 0 in that row.
Answer: E
Figure: a rectangle divided by its two diagonals, a vertical centre line and a horizontal centre line into 8 triangular regions. Numbers: top triangle 25200 (left of vertical line) and 5 (right of vertical line); left triangle 3600 (upper) and ? (lower); right triangle 5 (upper) and 10 (lower); bottom triangle 120 (left of vertical line) and 30 (right of vertical line).
Answer: A official key
Approach: Numbers in the 8 regions form a chain, read clockwise, with multipliers ×1, ×2, ×3 …
Solution:
Start at the top-right region (5) and go clockwise:
5 ×1 = 5 (right-upper), 5 ×2 = 10 (right-lower), 10 ×3 = 30 (bottom-right), 30 ×4 = 120 (bottom-left),
120 ×5 = 600 (left-lower, the ?), 600 ×6 = 3600 (left-upper) ✔, 3600 ×7 = 25200 (top-left) ✔.
Why the other options are wrong:
B (400), C (360), D (500), E (550): none gives 3600 when multiplied by 6.
Cetking shortcut: Large neighbours like 3600 and 25200 signal factorial-type growth: 25200/3600 = 7, so check 3600/6 = 600 directly.
Answer: A
Figure (3 columns x 4 rows grid):
| 7 | 22 | 5 |
| 5 | 9 | 11 |
| 9 | 11 | 15 |
| 38 | 77 | ? |
Official CET key: E · Cetking's answer: B — see why below
Approach: Column rule: (2nd number × 3rd number) − 1st number = bottom number.
Solution:
Column 1: 5 × 9 − 7 = 45 − 7 = 38 ✔
Column 2: 9 × 11 − 22 = 99 − 22 = 77 ✔
Column 3: 11 × 15 − 5 = 165 − 5 = 160.
Why the other options are wrong:
A (200), B (180), C (190), D (150): none fits the rule that works for both known columns.
Cetking shortcut: Bottom row numbers close to a product of the two middle numbers (38 ≈ 45, 77 ≈ 99) → test product minus the top number.
Answer: E
| 4 | 5 | 3 | 2 | 0 |
| 7 | 3 | 4 | 4 | 21 |
| 6 | 4 | 4 | 5 | 22 |
| 9 | 6 | 5 | 5 | ? |
Answer: A official key
Approach: Row rule: (1st × 4th) − (2nd + 3rd) = 5th.
Solution:
Row 1: 4 × 2 − (5 + 3) = 8 − 8 = 0 ✔
Row 2: 7 × 4 − (3 + 4) = 28 − 7 = 21 ✔
Row 3: 6 × 5 − (4 + 4) = 30 − 8 = 22 ✔
Row 4: 9 × 5 − (6 + 5) = 45 − 11 = 34.
Why the other options are wrong:
B (42), C (44), D (45), E (38): do not satisfy the rule verified on three rows (45 is just the product, ignoring the subtraction).
Cetking shortcut: The 0 in row 1 is the giveaway: some product must equal a sum — 4×2 = 5+3.
Answer: A
Three inverted-V/diamond number diagrams:
Diagram 1: top 18; middle 24 (left) and 6 (right); bottom 8.
Diagram 2: top 12; middle 16 (left) and 3 (right); bottom 4.
Diagram 3: top ?; middle 20 (left) and 5 (right); bottom 5.
Answer: D official key
Approach: Top = (left × right) ÷ bottom.
Solution:
Figure 1: 24 × 6 ÷ 8 = 144 ÷ 8 = 18 ✔
Figure 2: 16 × 3 ÷ 4 = 48 ÷ 4 = 12 ✔
Figure 3: 20 × 5 ÷ 5 = 100 ÷ 5 = 20.
Why the other options are wrong:
A (25), B (35), C (64), E (56): do not satisfy (left × right) ÷ bottom.
Cetking shortcut: When bottom divides the product cleanly in every figure, test product ÷ bottom first.
Answer: D
| 72 | 24 | 6 |
| 96 | 16 | 12 |
| 108 | ? | 18 |
Answer: D official key
Approach: Row rule: (2nd × 3rd) ÷ 2 = 1st.
Solution:
Row 1: 24 × 6 = 144, ÷ 2 = 72 ✔
Row 2: 16 × 12 = 192, ÷ 2 = 96 ✔
Row 3: ? × 18 ÷ 2 = 108 → ? × 18 = 216 → ? = 12.
Why the other options are wrong:
A (18): 18 × 18 / 2 = 162.
B (20): 180.
C (16): 144.
E (22): 198 — none equals 108.
Cetking shortcut: Check ratio 1st ÷ (2nd × 3rd): 72/144 = 96/192 = ½ → constant.
Answer: D
Answer: D official key
Approach: Replace symbols, then apply BODMAS.
Solution:
Given: × → −, + → ×, ÷ → +, − → ÷.
175 – 25 ÷ 5 + 20 × 3 + 10 becomes 175 ÷ 25 + 5 × 20 − 3 × 10.
= 7 + 100 − 30
= 77.
Why the other options are wrong:
A (80), B (85), C (92), E (65): arise from left-to-right evaluation or a wrong substitution.
Cetking shortcut: Rewrite the whole expression once before calculating — substituting while computing causes most errors.
Answer: D
In a certain code language, the symbols ×, –, ÷, and + do not represent their usual meanings.
Instead:
Answer: A official key
Approach: Replace symbols, then apply BODMAS.
Solution:
Given: × → ÷, − → ×, ÷ → +, + → −.
(5 – 17 ÷ 5) × 9 + 13 becomes (5 × 17 + 5) ÷ 9 − 13.
= (85 + 5) ÷ 9 − 13 = 90 ÷ 9 − 13
= 10 − 13 = −3.
Why the other options are wrong:
B (3): sign error.
C (2), D (−4), E (5): wrong substitution or order of operations.
Answer: A
Official CET key: B · Cetking's answer: D — see why below
Approach: Test simple combinations of product and sum on the given pairs.
Solution:
Rule: a * b = 2ab + 2.
4 * 5 = 2 × 20 + 2 = 42 ✓
6 * 3 = 2 × 18 + 2 = 38 ✓
7 * 8 = 2 × 56 + 2 = 114 ✓
9 * 6 = 2 × 54 + 2 = 110.
Cetking shortcut: All results are even and just above double the product (40→42, 36→38, 112→114) — answer = 2 × 54 + 2.
Answer: B
The first two circles shown below follow a certain definite pattern. Consider the same pattern for the the third circle too and determine the number that shall come in place of ' ? ' in the third circle ?
Data read from figure (each circle split into four quadrants, top-left, top-right, bottom-left, bottom-right): Circle 1: 10, 0, 8, 8. Circle 2: 9, 3, 6, 7. Circle 3: 8, ?, 4, 6.
Answer: E official key
Approach: Find a rule inside each circle linking the top-right number with the other three.
Solution:
Rule: top-right = (top-left − bottom-left) × (bottom-right − bottom-left).
Circle 1: (10 − 8) × (8 − 8) = 2 × 0 = 0 ✓
Circle 2: (9 − 6) × (7 − 6) = 3 × 1 = 3 ✓
Circle 3: (8 − 4) × (6 − 4) = 4 × 2 = 8.
Cetking shortcut: A 0 in circle 1 hints at a product with a zero factor — bottom-left = bottom-right (8, 8) there, so test (BR − BL) as a factor.
Answer: E
Answer: E official key
Approach: Mathematical operations — replace the symbols, then apply BODMAS.
Solution:
Code: '−' means +, '+' means ×, '×' means −.
Option E: 33 × 5 − 10 + 20 becomes 33 − 5 + 10 × 20 = 33 − 5 + 200 = 228 ✓.
Check the rest: B: 44 + 9 × 6 − 11 = 87 ≠ 86. C: 7 × 28 + 3 − 52 = 147 ≠ 127. D: 22 + 0 × 0 − 11 = 11 ≠ 0.
Note: option A, 22 + 7 − 3 × 9 → 22 × 7 + 3 − 9 = 154 + 3 − 9 = 148, also balances under the same code; the keyed answer is E.
Why the other options are wrong:
B, C, D: fail after substitution (87, 147 and 11 instead of 86, 127 and 0).
Cetking shortcut: Substitute only the operators, then do × before + and −; reject an option the moment it misses the target.
Answer: E
Answer: E official key
Approach: Balancing an equation — try the given sign sets with BODMAS.
Solution:
Option E: 24 ÷ 6 + 12 − 16.
= 4 + 12 − 16 = 0 ✓.
Why the other options are wrong:
A: 24 − 6 ÷ 12 + 16 = 24 − 0.5 + 16 = 39.5.
B: 24 − 6 − 12 + 16 = 22.
C: 24 ÷ 6 + 12 ÷ 16 = 4 + 0.75 = 4.75.
D: 24 ÷ 6 − 12 ÷ 16 = 4 − 0.75 = 3.25.
Cetking shortcut: To reach 0 the last sign must subtract 16; 24 ÷ 6 + 12 = 16 fits instantly.
Answer: E
Answer: E official key
Approach: Number pattern — sum of all digits on the left side.
Solution:
64 × 52 → 6 + 4 + 5 + 2 = 17 ✓.
48 × 56 → 4 + 8 + 5 + 6 = 23 ✓.
74 × 35 → 7 + 4 + 3 + 5 = 19 ✓.
84 × 37 → 8 + 4 + 3 + 7 = 22.
Why the other options are wrong:
A 32, B 23, C 21, D 20: none equals the digit sum 22.
Cetking shortcut: When results are small (under 40) for 2-digit 'products', test the digit sum first.
Answer: E
If ‘+’ means ‘÷’, ‘÷’ means’-‘, ‘-‘ means ‘×’ and ‘×’ means ‘+’, then 10+5÷3-2×9 is equal to
Answer: E
Approach: Substitute the real operators, then apply BODMAS.
Solution:
+ → ÷, ÷ → −, − → ×, × → +.
10 + 5 ÷ 3 − 2 × 9 becomes 10 ÷ 5 − 3 × 2 + 9.
= 2 − 6 + 9 = 5.
Cetking shortcut: Rewrite the full expression once before calculating — mid-way substitution causes most errors.
Answer: E
find the alternative which will replace question mark
Answer: D
Approach: Find the rule linking the side numbers to the centre number in each figure.
Solution:
Figure 1: left 7, right 6 → 7 × 6 + 5 = 47 (centre) ✓
Figure 2: left 12, right 8 → 12 × 8 + 5 = 101 ✓
Figure 3: ? × 8 + 5 = 77 → ? × 8 = 72 → ? = 9.
(Top = 5 × bottom in each figure: 45 = 5×9, 65 = 5×13, 80 = 5×16 — a separate check, not needed for ?.)
Cetking shortcut: Back-solve: (77 − 5) ÷ 8 must be a whole number — only 9 works.
Answer: D
Find the correct alternative which will replace the question mark.
Answer: B
Approach: Find the rule moving around the star's outer numbers.
Solution:
9 → 17 → 33 → 65: each term = previous × 2 − 1 (9×2−1 = 17, 17×2−1 = 33, 33×2−1 = 65).
Next = 65 × 2 − 1 = 129.
Check with centre: 9 + 17 + 33 + 65 + 129 = 253 ✓
Cetking shortcut: Centre 253 − (9 + 17 + 33 + 65 = 124) = 129 directly.
Answer: B
Answer: C
Approach: Count the even digits (0, 2, 4, 6, 8) written in each number. Zero is an even digit.
Solution:
291, 293, 295, 297, 299: one even digit each (the 2), so 5 × 1 = 5.
292, 294, 296, 298: two even digits each, so 4 × 2 = 8.
300: two zeros, which are even digits, so 2.
Total = 5 + 8 + 2 = 15.
Why the other options are wrong:
B (13): counts only 291 to 299 and leaves out the two zeros of 300.
A (11), D (17), E (21): these do not match a digit-by-digit count.
Cetking shortcut: Do the 290s as a block: the hundreds digit 2 gives 9, the even units digits (2, 4, 6, 8) give 4, and 300 gives 2 more: 9 + 4 + 2 = 15.
Answer: C
Answer: B
Approach: Knockout tournament: each match knocks out exactly one player.
Solution:
To find a winner, 30 − 1 = 29 players must be knocked out.
Each match knocks out exactly one player, so 29 matches are needed.
Why the other options are wrong:
A (15): this is only the first round (30 ÷ 2).
E (30): this counts the winner as knocked out too.
C (61), D (60): these count twice the matches or include extra rounds.
Cetking shortcut: For any knockout with n players, the number of matches = n − 1. Byes do not change this.
Answer: B
Answer: B
Approach: Swap the two signs everywhere they occur, then apply BODMAS.
Solution:
Swap + and ×: 10 × 10 × 10 − 10 + 10 = 1000 − 10 + 10 = 1000 ✓.
Why the other options are wrong:
A (+ ↔ ÷): 10 ÷ 10 ÷ 10 − 10 × 10 = 0.1 − 100 ✗.
C (÷ ↔ −): 10 + 10 + 10 ÷ 10 × 10 = 30 ✗.
D (× ↔ −): 10 + 10 + 10 × 10 − 10 = 110 ✗.
Cetking shortcut: A big right-hand side (1000) needs multiplications on the left — try swapping + with × first.
Answer: B
Answer: C
Approach: Relate each inner number to the two outer numbers beside it.
Solution:
Outer: top 12, right 15, bottom 11, left 18. Inner: top 27, right 26, bottom 29, left ?.
Top inner 27 = 12 + 15 (top + right).
Right inner 26 = 15 + 11 (right + bottom).
Bottom inner 29 = 11 + 18 (bottom + left).
Left inner = 18 + 12 (left + top) = 30.
Cetking shortcut: Inner sum (27 + 26 + 29 + ?) = 2 × outer sum (56) = 112 → ? = 30.
Answer: C
Answer: E
Approach: Compare the middle two numbers of a column with its top and bottom numbers.
Solution:
Column 4: top 15, bottom 15; middle 20 + 10 = 30 = 15 + 15.
Column 3: top 11, bottom 11; middle 5 + ? must equal 11 + 11 = 22 → ? = 17.
Answer: E
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