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Ages – MBA CET questions with solutions

20 questions · CET 2025–2026 · Easy 16 · Medium 4 · Hard 0. Newest paper first. Full papers

Q42MediumCET 2026 · Attempt 2 Slot 2 · Q42

The age of the father is twice that of the elder son. Ten years hence the age of father will be three times that of the younger son. If the difference of ages of two sons is 15 years, the age of the father is :

  1. 50 Years
  2. 55 Years
  3. 60 Years
  4. 65 Years
  5. 70 Years
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Official CET key: A · Cetking's answer: C — see why below

Approach: Age equations with two sons.

Solution:
Let father = F, elder son = E, younger son = Y.
F = 2E → E = F/2.
E − Y = 15 → Y = F/2 − 15.
Ten years hence: F + 10 = 3(Y + 10) = 3(F/2 − 5) = 1.5F − 15.
0.5F = 25 → F = 50.
Check: E = 25, Y = 10; after 10 years 60 = 3 × 20 ✓.

Cetking shortcut: Test options: F must be even; F = 50 → Y = 10 → 60 = 3 × 20 ✓ in one line.

Answer: A

Q123EasyCET 2026 · Attempt 2 Slot 1 · Q123

Two years ago, the ratio of Neha’s age to Pooja’s age was 5 : 6.
Four years from now, this ratio will become 7 : 8.
What is Pooja’s present age?

  1. 17 years
  2. 20 years
  3. 26 years
  4. 28 years
  5. 30 years
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Answer: B official key

Approach: Ages with two ratios: take the earlier ages as 5k and 6k.

Solution:
Two years ago: Neha = 5k, Pooja = 6k.
Four years from now (6 years later): (5k + 6)/(6k + 6) = 7/8.
40k + 48 = 42k + 42 → k = 3.
Pooja now = 6k + 2 = 18 + 2 = 20 years.

Cetking shortcut: Option check: Pooja 20 → Neha must be 17 (15 : 18 = 5 : 6 two years ago); in 4 years 21 : 24 = 7 : 8 ✓.

Answer: B

Q111MediumCET 2026 · Slot 5 · Q111

Rohan’s age after 8 years will be two-fifths of his father Mahesh’s age.
12 years ago, the ratio of their ages was 1 : 4.
What is Mahesh’s present age?

  1. 72 years
  2. 84 years
  3. 88 years
  4. 92 years
  5. 96 years
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Official CET key: D · Cetking's answer: B — see why below

Approach: Form two linear equations from the future and past age conditions.

Solution:
Let Rohan = R, Mahesh = M (present).
After 8 years: R + 8 = (2/5)(M + 8) → 5R + 40 = 2M + 16 → 5R = 2M − 24 … (1)
12 years ago: (R − 12)/(M − 12) = 1/4 → 4R − 48 = M − 12 → M = 4R − 36 … (2)
Substitute (2) in (1): 5R = 8R − 72 − 24 → 3R = 96 → R = 32.
M = 4 × 32 − 36 = 92 years.
Check: after 8 years 40 and 100 → 40 = 2/5 × 100 ✓; 12 years ago 20 : 80 = 1 : 4 ✓.

Why the other options are wrong:

  • A (72): 1 : 4 gives Rohan = 27; after 8 years 35 ≠ 2/5 × 80 = 32.
  • B (84): Rohan would be 30 (from 1:4), but 38 ≠ 2/5 × 92.
  • C (88), E (96): fail one of the two conditions.

Cetking shortcut: Option check with the 1:4 condition: M − 12 must be divisible by 4 and R = (M − 12)/4 + 12; only M = 92 (R = 32) then satisfies 40 : 100 = 2 : 5.

Answer: D

Q102EasyCET 2026 · Slot 4 · Q102
The ratio of the present ages of a mother and her daughter is 7:1. Four years ago, the ratio of their ages was 19:1. What will be the mother's age 4 years from now?
  1. 42 years
  2. 38 years
  3. 46 years
  4. 36 years
  5. 40 years
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Answer: C official key

Approach: Ages in ratio — form one equation from the past ratio.

Solution:
Present ages: mother = 7x, daughter = x.
4 years ago: (7x − 4)/(x − 4) = 19/1.
7x − 4 = 19x − 76 ⇒ 12x = 72 ⇒ x = 6.
Mother now = 42 years (daughter 6; 4 years ago 38 : 2 = 19 : 1 ✓).
Mother 4 years from now = 42 + 4 = 46 years.

Why the other options are wrong:
A (42) – mother's present age; the question asks 4 years later.
B (38) – mother's age 4 years ago.
D, E (36, 40) – do not satisfy both ratios.

Cetking shortcut: Options test: the present age must be a multiple of 7 and (age − 4) : (age/7 − 4) = 19 : 1; 42 → 38 : 2 = 19 : 1 instantly.

Answer: C

Q115EasyCET 2026 · Slot 4 · Q115
The ratio of the ages of A and B is 3:4. After 10 years, the ratio of their ages will be 4:5. What is the sum of their present ages?
  1. 60 years
  2. 70 years
  3. 80 years
  4. 50 years
  5. 90 years
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Answer: B official key

Approach: Ages in ratio — the future ratio gives one equation.

Solution:
Present ages: A = 3x, B = 4x.
(3x + 10)/(4x + 10) = 4/5.
15x + 50 = 16x + 40 ⇒ x = 10.
Ages 30 and 40 (after 10 years 40 : 50 = 4 : 5 ✓). Sum = 70.

Why the other options are wrong:
A (60), C (80), D (50), E (90) – sum must be 7x and satisfy the future ratio; only 70 does.

Cetking shortcut: Sum must be a multiple of 7 (3x + 4x) → only 70 among options.

Answer: B

Q48EasyCET 2026 · Slot 3 · Q48
A father tells his son, "I was 3 times of your present age when you were born." If the father's present age is 48 years, how old was the boy 4 years ago ?
  1. 8 years
  2. 12 years
  3. 32 years
  4. 16 years
  5. 14 years
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Answer: A official key

Approach: Father's age at son's birth = father's age now – son's age now.

Solution:
Let son = x. Father then = 48 – x.
48 – x = 3x → 4x = 48 → x = 12.
Son 4 years ago = 12 – 4 = 8 years.

Answer: A

Q116EasyCET 2026 · Slot 3 · Q116
Five years ago, the average age of P and Q was 15 years. After 5 more years, the average age of P, Q, and R will be 25 years. If R is currently 5 years younger than Q, what will be the age of R after 10 years?
  1. 20
  2. 25
  3. 30
  4. 35
  5. 40
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Official CET key: C · Cetking's answer: E — see why below

Approach: Convert every average into a total at a fixed time point, then shift ages carefully.

Solution:
5 years ago: P + Q = 2 × 15 = 30 → now P + Q = 40.
5 years from now: (P + Q + 10) + (R + 5) = 3 × 25 = 75.
50 + R + 5 = 75 → R = 20 (present age).
Check with R = Q − 5: Q = 25, P = 15 → consistent.
R after 10 years = 20 + 10 = 30.

Why the other options are wrong:

  • E (40): does not satisfy the totals; R is 20 now, so 30 after 10 years.
  • A (20): R's present age, not after 10 years.
  • B, D: do not satisfy the totals.

Cetking shortcut: Total of P, Q at +5 years = 30 + 2 × 10 = 50; three-person total 75 → R at +5 = 25 → R at +10 = 30.

Answer: C

Q110MediumCET 2026 · Slot 1 · Q110

The present ages of A, B, and C are in the ratio 6 : 8 : 10. Five years ago, the sum of the ages of A and B was equal to the age of C at that time. Find the total present age of A, B, and C.

  1. 114
  2. 120
  3. 100
  4. 145
  5. 180
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Official CET key: B · Cetking's answer: A — see why below

Approach: Ages in ratio → write as 6k, 8k, 10k and apply the past-age condition.

Solution:
As printed: (6k − 5) + (8k − 5) = 10k − 5 → 14k − 10 = 10k − 5 → k = 5/4 → total 24k = 30, which is not among the options.
The official key (120) corresponds to k = 5: A = 30, B = 40, C = 50.
This k satisfies the condition when it reads 'ten years ago, the sum of the ages of A and B equalled C's present age': (30 − 10) + (40 − 10) = 50 = C ✓ → 14k − 20 = 10k → k = 5.
Total = 24k = 24 × 5 = 120

Why the other options are wrong:
A (114), C (100), D (145): not multiples of 24, so they cannot be 24k for a whole-number k.
E (180): k = 7.5 (ages 45, 60, 75) fits neither the printed nor the corrected condition.

Cetking shortcut: Total = 24k, so the answer must be a multiple of 24 — only 120 (and 180) qualify; test k = 5 first.

Answer: B

Q112MediumCET 2026 · Slot 1 · Q112

When Ravi was born:

  • His father was 30 years older than his brother.
  • His mother was 26 years older than his sister.
  • His brother is 4 years older than his sister.

After 6 years, the average age of the family (Ravi, his brother, his sister, his father, and his mother) shall be 22 years. What was the age of his mother when Ravi was born?

  1. 40 years
  2. 30 years
  3. 35 years
  4. 46 years
  5. 48 years
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Answer: B official key

Approach: Age differences never change; build every age from the sister's age at Ravi's birth.

Solution:
At Ravi's birth let sister = s. Then brother = s + 4, father = (s + 4) + 30 = s + 34, mother = s + 26, Ravi = 0.
Sum at Ravi's birth = 0 + s + (s + 4) + (s + 34) + (s + 26) = 4s + 64
6 years later each of the 5 members is 6 years older: sum = 4s + 64 + 30 = 4s + 94
Average 22 → sum = 5 × 22 = 110 → 4s + 94 = 110 → s = 4
Mother's age at Ravi's birth = s + 26 = 30 years

Cetking shortcut: Total after 6 years = 110 → total at birth = 110 − 30 = 80 = 4s + 64 → s = 4 → mother = 30.

Answer: B

Q9EasyCET 2025 · Slot 6 · Q9

Rajesh is two years older than Riyansh, who is twice as old as Kailash. If the total of ages of Rajesh, Riyansh and Kailash are 37, then how old is Riyansh?

  1. 12
  2. 11
  3. 14
  4. 20
  5. 16
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Answer: C

Approach: Form one linear equation in the youngest age.

Solution:
Let Kailash = x → Riyansh = 2x → Rajesh = 2x + 2.
x + 2x + 2x + 2 = 37 → 5x = 35 → x = 7.
Riyansh = 2 × 7 = 14.

Cetking shortcut: Riyansh must be even and (37 − 2) must split as 5x → test 14: 7 + 14 + 16 = 37 ✓.

Answer: C

Q102EasyCET 2025 · Slot 6 · Q102
The sum of present ages of Anish, Ajay and Anvit is 75 years. If 5 years ago the ratio of their ages was 3:4:5. What is the present age of Ajay?
  1. 65
  2. 28
  3. 32
  4. 44
  5. 25
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Answer: E

Approach: Ages with a past ratio — add the years back to each part.

Solution:
5 years ago: Anish = 3x, Ajay = 4x, Anvit = 5x.
Present ages: 3x+5, 4x+5, 5x+5 ⇒ sum = 12x + 15 = 75 ⇒ 12x = 60 ⇒ x = 5.
Ajay now = 4x + 5 = 20 + 5 = 25 years.

Cetking shortcut: Sum 5 years ago = 75 − 15 = 60; Ajay's share = 4/12 × 60 = 20; add 5 ⇒ 25.

Answer: E

Q106EasyCET 2025 · Slot 5 · Q106

Raju got married 8years ago. His present age is 6/5 times his age at the time of his marriage. Raju’s sister was 10 years younger than him at the time of his marriage. The present age of Raju's sister is?

  1. 30 years
  2. 35 years
  3. 38 years
  4. 36 years
  5. 40 years
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Answer: C

Approach: Set the age at marriage as x and translate the fractional relation.

Solution:
Age at marriage = x; present age = x + 8
x + 8 = (6/5)x → 5x + 40 = 6x → x = 40
Raju now = 48
Sister at marriage = 40 − 10 = 30
Sister now = 30 + 8 = 38 years

Why the other options are wrong:
A (30): sister's age at the marriage, not now.
D/E: arithmetic slips; B (35): mixes present and past.

Cetking shortcut: (6/5)x − x = 8 → x/5 = 8 → x = 40 instantly.

Answer: C

Q134EasyCET 2025 · Slot 4 · Q134

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

  1. 4
  2. 8
  3. 10
  4. 6
  5. 5
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Answer: A

Approach: AP sum of ages.

Solution:
Ages: x, x + 3, x + 6, x + 9, x + 12.
Sum = 5x + 30 = 50 ⇒ x = 4.
Youngest = 4 years.

Why the other options are wrong:
C (10): the middle child's age.
B, D, E: do not give sum 50.

Cetking shortcut: Middle child = 50/5 = 10 ⇒ youngest = 10 − 6 = 4.

Answer: A

Solution figure for question 134Solution figure for question 134
Q135EasyCET 2025 · Slot 4 · Q135

Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?

  1. 24
  2. 27
  3. 26
  4. 29
  5. 30
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Answer: A

Approach: Ratio of ages with time shift.

Solution:
Sameer = 5x, Anand = 4x.
(5x + 3)/(4x + 3) = 11/9 ⇒ 45x + 27 = 44x + 33 ⇒ x = 6.
Anand = 4 × 6 = 24 years.

Why the other options are wrong:
E (30): Sameer's age.
B, C, D: not multiples of 4 that fit.

Cetking shortcut: Anand's age must be a multiple of 4: test 24 ⇒ Sameer 30 ⇒ 33 : 27 = 11 : 9 ✓.

Answer: A

Solution figure for question 135Solution figure for question 135Solution figure for question 135Solution figure for question 135
Q136EasyCET 2025 · Slot 4 · Q136

The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years)

  1. 8,20,28 respectively
  2. 16,28,36 respectively
  3. 20,35,45 respectively
  4. 18,32,49 respectively
  5. 8,30,45 respectively
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Answer: B

Approach: Ratio ages with a past-sum condition.

Solution:
Present ages 4x, 7x, 9x ⇒ sum 20x.
Eight years ago: 20x − 24 = 56 ⇒ 20x = 80 ⇒ x = 4.
Ages = 16, 28, 36 years.

Why the other options are wrong:
A, D, E: not in ratio 4 : 7 : 9.
C (20, 35, 45): right ratio, but sum 8 years ago = 76, not 56.

Cetking shortcut: Only options in ratio 4:7:9 are B and C; B's sum 80 − 24 = 56 ✓.

Answer: B

Solution figure for question 136Solution figure for question 136
Q65EasyCET 2025 · Slot 3 · Q65
A father is now three times as old as his son. Five years back, he was four times as old as his son. What is the age of the son (in years)?
  1. 12
  2. 15
  3. 18
  4. 20
  5. 22
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Answer: B

Approach: Age equations: form the present and past relations, then solve.

Solution:
Let the son's age be S. Then the father's age is 3S.
Five years ago: 3S − 5 = 4(S − 5) = 4S − 20.
So S = 20 − 5 = 15. (Father = 45. Check: 40 = 4 × 10 ✔)

Cetking shortcut: Check the options: 15 gives a father of 45, and five years ago 40 = 4 × 10 ✔. 12 gives 31 vs 4 × 7 = 28 ✗.

Answer: B

Q68EasyCET 2025 · Slot 3 · Q68
A father tells his son, "I was of your present age when you were born". If the father is 36 now, how old was the boy five years back?
  1. 13
  2. 15
  3. 17
  4. 20
  5. 27
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Answer: A

Approach: Age difference stays the same for life.

Solution:
'I was your present age when you were born' means the age gap = the son's present age (x).
Father = x + x = 2x = 36, so x = 18.
Son five years back = 18 − 5 = 13.

Why the other options are wrong:
D (20): this is not tied to the gap.
B (15), C (17): these subtract the wrong number of years from 18.
E (27): this does not fit the age gap.

Cetking shortcut: The father's present age is twice the son's present age, so the son is 36/2 = 18. Then subtract 5.

Answer: A

Q114EasyCET 2025 · Slot 3 · Q114
The ratio between the present age of A and B is 5:3 respectively. The ratio between A’s age 4 years ago and B’s age 4 years hence is 1:1. What is the ratio between A’s age 4 years hence and B’s age 4 years ago?
  1. 1:3
  2. 3:1
  3. 2:1
  4. 4:1
  5. 1:1
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Answer: B

Approach: Present ages 5x and 3x; use the 1:1 condition.

Solution: A's age 4 years ago = B's age 4 years hence:
5x − 4 = 3x + 4 → 2x = 8 → x = 4.
A = 20, B = 12.
A's age 4 years hence = 24; B's age 4 years ago = 8.
Ratio = 24 : 8 = 3 : 1.

Answer: B

Solution figure for question 114Solution figure for question 114
Q115EasyCET 2025 · Slot 3 · Q115
One year ago, Promila was 4 times as old as her daughter Sakshi. Six years hence, Promila’s age will exceed her daughter’s age by 9 years. What is the ratio of present ages of Promila and her daughter?
  1. 9:2
  2. 11:3
  3. 12:5
  4. 13:4
  5. 9:4
Show answerHide answer

Answer: D

Approach: Age difference is constant; combine with the 'one year ago' multiple.

Solution: Six years hence Promila exceeds Sakshi by 9 → difference is always 9: P − S = 9.
One year ago: P − 1 = 4(S − 1) → P = 4S − 3.
4S − 3 − S = 9 → 3S = 12 → S = 4, P = 13.
Ratio = 13 : 4.

Cetking shortcut: One year ago difference 9 = 4k − k = 3k → k = 3 → ages then 12 and 3 → now 13 and 4.

Answer: D

Q5EasyCET 2025 · Slot 2 · Q5

When Rajesh's age was same as the present age of Garima, the ratio of their ages was 3 : 2. When Garima's age becomes the same as the present age of Rajesh, the ratio of the ages of Rajesh and Garima will become:

  1. 5 : 4
  2. 4 : 5
  3. 2 : 3
  4. 4 : 3
  5. 7 : 6
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Answer: A

Approach: The age gap d between two people never changes.

Solution:
Let Garima now = x, Rajesh now = x + d.
When Rajesh was x (d years ago), Garima was x − d. Ratio x : (x − d) = 3 : 2 → 2x = 3x − 3d → x = 3d.
Now: Garima = 3d, Rajesh = 4d.
When Garima becomes 4d (d years later), Rajesh = 5d.
Ratio = 5d : 4d = 5 : 4.

Why the other options are wrong: 4 : 5 reverses the order (Rajesh is older); 4 : 3 is the present ratio; 2 : 3 and 7 : 6 do not keep a constant gap.

Cetking shortcut: Past, present, future ages form 2, 3, 4, 5 (in units of d): then Rajesh 3 : Garima 2, now 4 : 3, later 5 : 4.

Answer: A

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